similar to: [LLVMdev] ICmp documentation clarification

Hi Baptiste, On Fri, 2007-01-05 at 09:44 +0100, Baptiste Lepilleur wrote: > I just want to make sure I understand the semantic of the icmp function > correctly as assumption are dangerous in this domain. > > The syntax is specified as follow: > <result> = icmp <cond> <ty> <var1>, <var2> ; yields {bool}:result > > But I can not find the

Reid Spencer wrote: > Hi Baptiste, > > On Fri, 2007-01-05 at 09:44 +0100, Baptiste Lepilleur wrote: >> I just want to make sure I understand the semantic of the icmp >> function correctly as assumption are dangerous in this domain. >> >> The syntax is specified as follow: >> <result> = icmp <cond> <ty> <var1>, <var2> ; yields

Hi Baptiste, On Fri, 2007-01-05 at 22:10 +0100, Baptiste Lepilleur wrote: > Reid Spencer wrote: > > Hi Baptiste, > > > > On Fri, 2007-01-05 at 09:44 +0100, Baptiste Lepilleur wrote: > >> I just want to make sure I understand the semantic of the icmp > >> function correctly as assumption are dangerous in this domain. > >> > >> The syntax is

Hello, I use R 2.10, and I am new in R (I used to use SAS and lately Stata), I am using XP. I have a data which has a data.frame format called x.df (read from a csv file). I want to take from this data observations for which the variable "Code" starts with an "R". I took all the Code and put them into a vector vec<-grep("R[A-Z][A-Z]",x.df$Code,value=TRUE) Then I

Hi All, Will try and keep brief, excuse the poor graphics skills, first time using GIMP. I would like to make the first one look (somewhat) like the second if possible. From: http://d.imagehost.org/0519/Screen_shot_2010-12-08_at_3_50_23_PM.png To here: http://d.imagehost.org/0293/Screen_shot_2010-12-08_at_3_50_23_PM2.png I imagine the line going over the top with the p-values is probably not

Hi, This has been asked before but not sufficiently answered from what I could find. How do you create combinations with repetitions (multisets) in R? If I have > set <- array(1:3) And I want to choose all combinations of picking 2 numbers, I want to get a print out like [,1] [,2] [1,] 1 1 [2,] 1 2 [3,] 1 3 [4,] 2 2 [5,] 2 3 [6,] 3 3 subsets(set,

>From: "Baptiste Lepilleur" >Date: Tue, 20 Sep 2005 09:29:07 +0200 > >Henrik Bach wrote: >>Hi, >> >>Please have a look on my private Getting started with MinGW: >> >>http://www.geocities.com/henrik_bach_llvm/ > > >Thanks Henrik.The make line was most useful. Though, in my case I also >needed to add a -L so libimagehlp.a would be

Dear R-helpers, I have a list containing 5000 elements, each element is a dataframe containing one ID column (identical over the 5000 dataframes) and 9 numeric variables, e.g. ID VAR1 VAR2 VAR3 ... VAR9 I would like to create a new dataframe containing the ID column and the mean values of the 9 numeric variables. So, the structure of this new dataframe would be identical to the structure of the

Henrik Bach wrote: >> From: "Baptiste Lepilleur" >> Date: Tue, 20 Sep 2005 09:29:07 +0200 >> >> Henrik Bach wrote: >>> Hi, >>> >>> Please have a look on my private Getting started with MinGW: >>> >>> http://www.geocities.com/henrik_bach_llvm/ >> >> >> Thanks Henrik.The make line was most useful.

Launchpad already maintains bzr mirrors: http://code.launchpad.net/llvm The mirrors are the lp:~vcs-import branches (a specific launchpad user used for automatically mirroring branches). Baptiste. 2009/10/28 Óscar Fuentes <ofv at wanadoo.es> > Time ago when the svn server was crawling due to massive hammering from > people mirroring the repo, someone said that after the 2.6 release

Here are some clarifications for the reference manual. Please verify that my assumptions are correct. Shall I post a patch? Floating-point Constants: Add "The assembler requires the exact decimal value of a floating-point constant. For example, the assembler accepts '1.25' but rejects '1.3' because '1.3' is a repeating decimal in binary." Binary

Here is a patch containing all but one of the changes. I realized that the remainder/modulo discussion does indeed belongs to the srem instruction. The semantics of urem are obvious and need no further clarification. Best Regards, Jon 1572,1573c1572,1575 < notation (see below). Floating point constants must have a <a < href="#t_floating">floating point</a>

Hi, I am using R 1.9.1 on on i686 PC with SuSE Linux 9.0. I have a data.frame, e.g.: > myData <- data.frame( var1 = c( 1:4 ), var2 = c (5:8 ) ) If I add a new column by > myData$var3 <- myData[ , "var1" ] + myData[ , "var2" ] everything is fine, but if I omit the commas: > myData$var4 <- myData[ "var1" ] + myData[ "var2" ] the name

Hi all, I have been trying to solve this problem and have had no luck so far. I have numeric vectors VAR1, VAR2, and VAR3 which I am trying to cbind. I also have a character vector "VAR1,VAR2,VAR3". How do I manipulate this character vector such that I can input a transformed version of the character vector into cbind and have it recognize that I'm trying to refer to my numeric

Dear List, I have Multi-level Data i= Indivitual Level g= Group Level var1= First Variable of interest var2= Second Variable of interest and I want to count the frequency of "var1" and "var2" on the group level. I found a way, but there must be a much simpler way. data.ml <- data.frame(i=c(1:8),g=as.factor(c(1,1,1,2,2,3,3,3)),var1=c(3,3,3,4,4,4,4 ,4),

Buenos días. Hoy ando un poco (o bastante) espeso y no doy con la tecla de una cosa que seguro que es muy simple.. Pongo un ejemplo. var1 <- c(rep(0,3),rep(1,2)) var2 <- c(rep(1,2),0,0,1) var3 <- c(rep(1,2),rep(0,3)) var4 <- c(rep(1,2),rep(0,3)) datos <- data.frame(fila=1:5,var1, var2, var3, var4) datos datos fila var1 var2 var3 var4 1 1 0 1 1 1 2 2 0

I would like to know how to turn a variable into a string. I have tried as.symbol and as.name but it doesnt work for what I'd like to do Essentially, I'd like to feed the function below with two variables. This works fine in the bit working out number of elements in each variable. In the print(sprintf("OK with %s and %s\n", var1, var2)) line I would like var1 and var2 to be

I have a data frame whose first colum contains the names of the variables and whose second colum contains the values to assign to them: : kkk <- data.frame(vars=c("var1", "var2", "var3"), vals=c(10, 20, 30), stringsAsFactors=F) If I do : assign(kkk$vars[1], kkk$vals[1]) it works : var1 [1] 10 However, if I try with mapply

Estimados Estoy entrenando hacer funciones que respondan a comandos, en esta caso en la salida gráfica se observa que dice : Exposure=var3 y outcome=var 1 quisiéramos que se reflejan los nombres de la base de datos : var1=estado, var2=cake, var3=chocolate Espero haberme explicado adecuadamente Adjunto tabla con datos #################################### #Comando que llama

Can someone please give me a clue how to 're'write this so I dont need to use loops. a<-ts(matrix(c(1,1,1,10,10,10,20,20,20),nrow=3),names=c('var1','var2','var3')) b<-ts(matrix(c(2,2,2,11,11,11,21,21,21),nrow=3),names=c('var1','var2','var3'))