similar to: Mi script R es muy lento

Hola Carlos, bueno la verdad es que mi pregunta era algo general, cuando no has usado data.table no parece muy intuitivo pasar de la forma de programar a la que estás más acostumbrado (bucles, notación matricial...) a esa otra. Aun no tengo un cálculo complejo concreto pero lo tendré que hacer... solo quería saber si se puede, y parece que sí, asi que será cuestión de empaparse un poco de

En el correo anterior se me olvidó mencionar que trabajo con Rstudio El 28 de mayo de 2015, 15:18, MªLuz Morales <mlzmrls en gmail.com> escribió: > Hola, > soy nueva en esta lista y también en R. Yo he realizado un script en R > que carga dos archivos csv, uno de ellos con casi 2 millones de filas. El > programa carga esos archivos a data frame, y se trata simplemente de >

Hola, Si no tienes inconveniente en compartir tu conjunto de datos (puedes dejarlo en un Dropbox y compartir enlace) o incluir una salida de la variables: "seta" y "outcomes" (función "save.image()") con eso podemos darte alguna solución mucho más rápida que la que planteas. En tu código con un bucle estás tratando de rellenar una lista que son los diferentes

Hi One of our customers has a Filemaker database which needs to be accessed for some data. Using the Web Companion, I can query the database for an XML version of the data. I need to be able to push this data into an array of hashes, so I can access it in a more convenient way. Filemaker is able to provide me with 2 XML formats (DSO-XML and FMP-XML): *********** DSO-XML ***********

Mª Luz, si el comando de Carlos te devuelve 0 es que no hay NA's. Da igual que tus columnas sean caracteres o número. Lo que intuyo es que tienes celdas con la frase "NA" que interpretas como NA. Mandanos el summary de tu data.table y lo vemos... ----- Mensaje original ----- De: "MªLuz Morales" <mlzmrls en gmail.com> Para: "Carlos J. Gil Bellosta"

Hi, I would like to put a checkbox on a form where the input field is a variable rather than a field in a model. The normal way (with a model) would be: <%= check_box(''client'', ''accept'', {}, "1", "0") %> But since accept is a variable @accept and model client will not be there, how do I make a check box work? Regards, Paul

Hi, I need some help with running a recursive function. I like to run funlp2 recursively. When I try to run recursive function in another function named "calclp" I get this "Error: any(!dat2$norm_sd) >= 1 is not TRUE". I have never built a recursive function before so having trouble executing it in this case. I would appreciate any help or guidance to resolve this issue.

My own typo ... whoops ... !( any(dat2$norm_sd >= 1 )) On Thu, Dec 14, 2017 at 3:43 PM, Eric Berger <ericjberger at gmail.com> wrote: > You seem to have a typo at this expression (and some others like it) > > Namely, you write > > any(!dat2$norm_sd) >= 1 > > when you possibly meant to write > > !( any(dat2$norm_sd) >= 1 ) > > i.e. I think your !

Hello all, I need to setup a new asterisk system with the following requirements: 1. Will be moving from chan_sccp to sip (7960's), but I want to support the sccp phones until everyone has been migrated. 2. Need to maintain current portability of the 7960's. (ie a user can unplug his phone from the internal LAN, take it home or wherever, and plugin and have the phone register and

If you are trying to understand why the "stopifnot" condition is met you can replace it by something like: if ( any(dat2$norm_sd >= 1) ) browser() This will put you in a debugging session where you can examine your variables, e.g. > dat$norm_sd HTH, Eric On Thu, Dec 14, 2017 at 5:33 PM, Eric Berger <ericjberger at gmail.com> wrote: > The message is coming from

Hi, I accidently left out few lines of code from the calclp function. Updated function is pasted below. I am still getting the same error ?Error: !(any(data1$norm_sd >= 1)) is not TRUE? I would appreciate any help. Nilesh dput(calclp) function (dataset) { dat1 <- funlp1(dataset) recursive_funlp <- function(dataset = dat1, func = funlp2) { dat2 <- dataset %>%

Eric: I will try and see if I can figure out the issue by debugging as you suggested. I don?t know why my code after stopifnot is not getting executed where I like the code to run the funlp2 function when the if statement is TRUE but when it is false, I like it to keep running until the stopifnot condition is met. When the stopifnot condition is met, I like to get the output from if statement

You seem to have a typo at this expression (and some others like it) Namely, you write any(!dat2$norm_sd) >= 1 when you possibly meant to write !( any(dat2$norm_sd) >= 1 ) i.e. I think your ! seems to be in the wrong place. HTH, Eric On Thu, Dec 14, 2017 at 3:26 PM, DIGHE, NILESH [AG/2362] < nilesh.dighe at monsanto.com> wrote: > Hi, I need some help with running a

Eric: Thanks for taking time to look into my problem. Despite of making the change you suggested, I am still getting the same error. I am wondering if the logic I am using in the stopifnot and if functions is a problem. I like the recursive function to stop whenever the norm_sd column has zero values that are above or equal to 1. Below is the calclp function after the changes you suggested.

The message is coming from your stopifnot() condition being met. On Thu, Dec 14, 2017 at 5:31 PM, DIGHE, NILESH [AG/2362] < nilesh.dighe at monsanto.com> wrote: > Hi, I accidently left out few lines of code from the calclp function. > Updated function is pasted below. > > I am still getting the same error ?Error: !(any(data1$norm_sd >= 1)) is > not TRUE? > > >

Your code contains the lines stopifnot(!(any(data1$norm_sd >= 1))) if (!(any(data1$norm_sd >= 1))) { df1 <- dat1 return(df1) } stop() "throws an error", causing the current function and all functions in the call stack to abort and return nothing. It does not mean to stop now and return a result. Does the function give

Hi All, I am a newbie to GPU programming. I wonder if anyone can help me with using GPU in .Call in R. Basically, I want to write a function that calcuates the sum of two double type vectors and implement this using GPU. My final goal is to make such an implementation callable from R. (a) First, I wrote a R-C interface handles the R object using .Call (saved as VecAdd_cuda.c

I tried sending this e-mail to the list earlier but no one replied... Right, so I''m brand new to xen, and I''ve had success in making xen boot (kernel /boot/xen-2.0.6.gz module /boot/vmlinuz-2.6.11-xen0), but there are a couple major issues. 1) The screen resolution. I''m running a ThinkPad T30 (2366-92U, for those who want to know), and all the text looks fuzzy. I

Hi, I am getting a lot of warnings since upgrading to 1.1rc10 (from rc4): mbox /home2/seta/Mail/Sent: Can't find next message offset for uid=12 Almost always, it is the Sent or Trash folders that are giving these. Users aren't experiencing any problems, but the errors continue to come. Is this something I should be concerned about? Here is output of "dovecot -n": #

Greetings, Say I have defined mp <- function(a) function(x) x^a f2 <- mp(2) and I would like to retrieve the "a" which is local to f2. Two options come to mind; get("a", envir=environment(f2)) eval(substitute(a), environment(f2)) I'm curious if one of these is preferred over the other in terms of efficiency, robustness, aesthetics, etc. Or perhaps