similar to: búsqueda y sustitución masiva

para dibujar la línea del modelo linear con abline ** *Carlos Guadián Orta* Mi Twitter es @carlosguadian <http://twitter.com/carlosguadian> Mi blog es K-Government <http://www.k-government.com> Mi perfil profesional en LinkedIn <http://es.linkedin.com/in/carlosguadian> Trabajo en Autoritas Consulting <http://www.autoritas.es> Coordino #oGov <http://www.ogov.eu>

Si, Carlos, gracias. Pero desafortunadamente el link con el PDF no funciona :( --JIV Sent from my phone. Please excuse my brevity and misspelling. On Jul 24, 2013, at 4:51 PM, Carlos Ortega <cof@qualityexcellence.es> wrote: Hola, ¿Viste la sugerencia/ayuda en StackOverflow?: http://stackoverflow.com/questions/17408930/twitter-first-example Saludos, Carlos Ortega

Cuando hago hago una regresion linealy obtengo los valores a y b como podria ahcer para generar un vector y graficarlo junto con el vector de datos reales? gracias [[alternative HTML version deleted]]

Amalia, Instalaste R? Necesitas R para que RStudio funcione. Saludos, Jorge.- 2016-03-01 21:45 GMT-05:00 Amalia Carolina Guaymas Canavire < acarolinagc en gmail.com>: > Hola les escribo porque R studio en windows 8 no me funciona y no sé como > solucionarlo. El error que arroja es que R no puede iniciar, la sección de > environment no se carga, aparece como procesando y cuando

Puedes utilizar la función plot directamente sobre el objeto lm y te devolverá varios gráficos para la validación del modelo ?plot.lm plot(mimodelo,which=1:6) El 28 de mayo de 2013 11:37, Carlos Guadián Orta <carlosguadian@gmail.com>escribió: > para dibujar la línea del modelo linear con > > abline > > ** > *Carlos Guadián Orta* > Mi Twitter es @carlosguadian

A ver si os sirve. Desde que cambiaron la api a la v 1.1 la identificación a través de la api es obligatoria para poder acceder a información. El proceso que yo sigo es el siguiente: #Se definen los datos de la app registrada en twitter dev tw <- OAuthFactory$new(consumerKey="aquí consumerkey", consumerSecret="aqui consumer secret",

A student asked me about simulation he is doing. This simulation presented an interesting R programming puzzle that we did solve but I am not happy with the solution. I feel there should be a better way of doing this. Briefly, he is simulating births and deaths in a linear array of cells. Births and deaths are required to alternate. For a birth, one of the cells is selected at random to be the

Hi, I have what I hope is a simple text processing question in R. I want to replace every instance of http:\\XXX.com with "WEBSITE" When I try sub('(^http://)(.com$)', 'WEBSITE', <filename>);, it only substitutes http:// and .com so it looks like WEBSITEXXXWEBSITE How do I get it to match the pattern "http:// . . . . .com" and substitute the whole

Hi all, I'm currently working on an R program where I have to access an FTP server to download some of the data I need. However, the people who post up the files I access are at times inconsistent with regards to time posted, if they post at all, etc.... Here's some of the code I use: library(RCurl) url1 = paste("ftp://user:password at a.great.website.com/",

Hello, I''ve been trying for hours to parse an XML using Hpricot. Usually it''s not a problem. Here''s my simple code: #This works and outputs the proper xml data @url1 = ''http://www.sportingnews.com/stories/sportingnews/MLB/rss.xml'' @page1 = Hpricot(open(@url1)) <%= @page 1 %> #This does not work, and I''m scratching my head @url1 =

Hi dear R users: I'm trying the following code to download an information from the web. url1 <-

Dear useRs, I recently began a job at a very large and heavily bureaucratic organization. We're setting up a research office and statistical analysis will form the backbone of our work. We'll be working with large datasets such the SIPP as well as our own administrative data. Due to the bureaucracy, it will take some time to get the licenses for proprietary software like Stata. Right

Hello, I have a problem with using read.csv(). I want to read a table from the ONS neighborhood statistics website which has an address:

On Sun, Mar 11, 2018 at 09:12:56AM -0500, KENNETH ROY CABRERA TORRES wrote: > Hi dear R users: > > I'm trying the following code to download an information from the web. > > url1 <-

Hi all, I'm trying to use the package read.table within a foreach loop. I'm grabbing 500M rows of data at a time from two different files and then doing an aggregate/tapply like function in read.table after that. I had planned on doing a foreach loop 39 times at once for the 39 files I have, but obviously that won't work until I figure out why the segfault is occurring. The

Hi, I have an index where each document contains an untokenized ''url'' field. I would like to query the index for the most popular urls. In SQL I would do this via a Group By clause. Is there anything in Ferret that will do something similar? I found this discussion that proposed a solution involving TermEnums:

Very much a rookie at R, and have only recently started using it again so pardon the simple question. I am trying to produce a box plot from one data set and then overlay a line plot from another data set. The box plot data set is made up of 20 sets of 30 data points, or 600 total data points. The line has only 30 total data points. The box plot is plotting fine, but for some reason, the line plot

Hello, I have two different files which I'd like to combine to make one data frame but I've no idea how to do it! The first file has two columns; one is the date, the following is a binary code for debris flow events. Then my other file has also two columns; the date and then precipitation data. The thing is, is that the two date columns don't all contain the same dates. The binary

Hello again, Let say I have following vector: Vec <- c("0.0365780769", "(1.09738648244378)", "(0.812507787221523)", "0.5778069963", "(0.452456601362355)", "-1.8900812605", "-1.8716093762", "0.0055217041", "-0.4769192333", "-2.4133018880") Now I want to convert this vector to numeric vector. I

I am trying to read some data off the zillow site. Newbie to xml, html, parsing and the xml package. I've been able to load the web page I'm interested with the following code but I'm not sure of the next step to get the information I'm interested in into R : library(XML) url <- "http://www.zillow.com/homes/511 W Lafayette St, Norristown, PA_rb" doc <-doc <-