similar to: removing part of a string

Displaying 20 results from an estimated 2000 matches similar to: "removing part of a string"

2018 Jan 30
2
variable names in lm formula ~.
dear all, Is the following intentional? Am I missing anything in documentation? d<-data.frame(y=rnorm(10,5,.5),exp=rnorm(10), age=rnorm(10)) formula(lm(exp(y)~exp+age, data=d)) #--> exp(y) ~ exp + age formula(lm(exp(y)~., data=d)) #--> exp(y) ~ age variable 'exp' (maybe indicating "experience") is not included in the model. The same happens with 'log' (and
2010 Mar 04
1
only actual variable names in all.names()
dear all, When I use all.vars(), I am interest in extracting only the variable names.. Here a simple example all.vars(as.formula(y~poly(x,k)+z)) returns [1] "y" "x" "k" "z" and I would like to obtain "y" "x" "z" Where is the trick? many thanks vito -- ==================================== Vito M.R. Muggeo Dip.to Sc
2010 Oct 25
1
building lme call via call()
dear all, I would like to get the lme call without fitting the relevant model. library(nlme) data(Orthodont) fm1 <- lme(distance ~ age, random=list(Subject=~age),data = Orthodont) To get fm1$call without fitting the model I use call(): my.cc<-call("lme.formula", fixed= distance ~ age, random = list(Subject = ~age)) However the two calls are not the same (apart from the data
2013 Feb 14
0
IWSM 2013: LAST call for papers
dear all, apologizes for this OT =========================== 28th International Workshop on Statistical Modelling (IWSM), Palermo (Italy) 8-12 July 2013. http://iwsm2013.unipa.it Dear friend, For your information, I would like to bring to your attention that deadline for submission of abstracts is FEBRUARY 18 If you are still interested to visit Palermo (and taste its specialities :-))
2012 Jun 01
1
getting the name of the working .Rdata file
dear all, I do not if it is a nonsense question.. Is it possible in the R session to get the name of the current .Rdata file that I ran? I mean: suppose I double click the file myfile.Rdata. ls() returns the names of the objects in the current workspace (that is saved in myfile.Rdata). In the current R session, I would like to obtain "myfile.Rdata". Is it possible? Thanks in
2013 Jan 18
0
OT: IWSM 2013
dear all, apologizes for this off topic. I would like to inform you that registration and paper submission for the 28th International Workshop on Statistical Modelling (IWSM) to be held in Palermo (Italy) 8-12 July 2013 is now open at http://iwsm2013.unipa.it Register at http://iwsm2013.unipa.it/?cmd=registration and then submit your abstract. Deadlines for Abstract submission is February 4,
2012 Mar 21
1
glmnet() vs. lars()
dear all, It appears that glmnet(), when "selecting" the covariates entering the model, skips from K covariates, say, to K+2 or K+3. Thus 2 or 3 variables are "added" at the same time and it is not possible to obtain a ranking of the covariates according to their importance in the model. On the other hand lars() "adds" the covariates one at a time. My question
2009 Nov 02
3
partial matching with grep()
dear all, This is a probably a silly question. If I type > grep("x",c("a.x" ,"b.x","a.xx"),value=TRUE) [1] "a.x" "b.x" "a.xx" Instead, I would like to obtain only "a.x" "b.x" How is it possible to get this result with grep()? many thanks for your attention, best, vito --
2008 May 02
1
error in using by + median
dear all, Could anyone explain me the behaviour of median() within by()? (I am running R.2.7.0) thanks, vito > H<-cbind(rep(0:1,l=20),matrix(rnorm(20*2),20,2)) > by(H[,-1],H[,1],mean) INDICES: 0 V1 V2 -0.2101069 0.2954377 --------------------------------------------------------------------------------------------------------------------- INDICES: 1 V1
2018 May 21
0
removing part of a string
Hello, Try this. ss1 <- "z:f(5, a=3, b=4, c='1:4', d=2)" ss2 <- "f(5, a=3, b=4, c=\"1:4\", d=2)*z" fun <- function(s) sub("(\\().*(\\))", "\\1\\2", s) fun(ss1) #[1] "z:f()" fun(ss2) #[1] "f()*z" Hope this helps, Rui Barradas On 5/21/2018 2:33 PM, Vito M. R. Muggeo wrote: > dear all, > I am stuck
2018 May 21
1
removing part of a string
I would use sub("\\(.*\\)", "()", s) It is essentially the same as Rui's suggestion, but I find the purpose to be more clear. It might also be a little more efficient. HTH Ulrik On Mon, 21 May 2018, 15:38 Rui Barradas, <ruipbarradas at sapo.pt> wrote: > Hello, > > Try this. > > > ss1 <- "z:f(5, a=3, b=4, c='1:4', d=2)" >
2008 Jun 30
2
difference between MASS::polr() and Design::lrm()
Dear all, It appears that MASS::polr() and Design::lrm() return the same point estimates but different st.errs when fitting proportional odds models, grade<-c(4,4,2,4,3,2,3,1,3,3,2,2,3,3,2,4,2,4,5,2,1,4,1,2,5,3,4,2,2,1) score<-c(525,533,545,582,581,576,572,609,559,543,576,525,574,582,574,471,595, 557,557,584,599,517,649,584,463,591,488,563,553,549) library(MASS) library(Design)
2008 Dec 17
0
OFF topic testing for positive coeffs
Dear all, This is off-topic, however I hope someone can give me useful suggestion.. Given the regression model y = b0 + b1*x + e I am interested in testing for positive coeffs, namely H0: b0>0 AND b1>0 H1: b0,b1 unconstrained It is simple to estimate the model under H0 and H1 (there are several suggestions on the Rlist about estimation but nothing about testing..) perform a likelihood
2005 Mar 11
0
Negative binomial regression for count data,
Dear list, I would like to know: 1. After I have used the R code (http://pscl.stanford.edu/zeroinfl.r) to fit a zero-inflated negative binomial model, what criteria I should follow to compare and select the best model (models with different predictors)? 2. How can I compare the model I get from question 1 (zero-inflated negative binomial) to other models like glm family models or a logistic
2004 Dec 14
1
correlation in lme4
Dear all, I have tried to consider a correlation structure in lme (package lme4), but without success. I have used something like: > risul<-lme(y~x+ z , data=mydata, random=~ x | g, correlation = corAR1()) but the result is the same as: > risul<-lme(y~x+ z , data=mydata, random=~ x | g). Can anybody help me? Antonella ************************************************** Prof.
2007 Dec 06
1
differences in using source() or console
Dear all, Is there *any* reason explaining what I describe below? I have the following line myfun(x) If I type them directly in R (or copy/past), it works.. However if I type in R 2.6.1 > source("code.R") ##code.R includes the above line Error in inherits(x, "data.frame") : object "d" not found namely myfun() does not work correctly. In particular the
2020 May 18
6
[PATCH] SSE2/SSSE3 optimized version of get_checksum1() for x86-64
This drop-in patch increases the performance of the get_checksum1() function on x86-64. On the target slow CPU performance of the function increased by nearly 50% in the x86-64 default SSE2 mode, and by nearly 100% if the compiler was told to enable SSSE3 support. The increase was over 200% on the fastest CPU tested in SSSE3 mode. Transfer time improvement with large files existing on both ends
2020 May 19
5
[PATCHv2] SSE2/SSSE3 optimized version of get_checksum1() for x86-64
I've read up some more on the subject, and it seems the proper way to do this with GCC is g++ and target attributes. I've refactored the patch that way, and it indeed uses SSSE3 automatically on supporting CPUs, regardless of the build host, so this should be ideal both for home builders and distros. Getting the code to build right in c++ mode (checksum_sse2.cpp only) was a bit of an
2006 Nov 03
1
difference in using with() and the "data" argument in glm call
Dear all, I am dealing with the following (apparently simple problem): For some reasons I am interested in passing variables from a dataframe to a specific environment, and in fitting a standard glm: dati<-data.frame(y=rnorm(10),x1=runif(10),x2=runif(10)) KK<-new.env() for(i in 1:ncol(dati)) assign(names(dati[i]),dati[[i]],envir=KK) #Now the following two lines work correctly:
2007 Nov 28
3
using names with functions..
Dear all, I have the following (rather) strange problem.. For some reasons, I finally work with a variable whose name includes an R function, "a.log(z)", say. And that is a problem when I call it in a formula, for instance: > myname<-"a.log(z)" > dd<-data.frame("a.log(z)"=1:10,y=rnorm(10)) > o<-lm(y~1,data=dd) >