Displaying 20 results from an estimated 300 matches similar to: "using for loop with data frames."
2009 Aug 06
2
problem with r import data
Good moorning,
yesterday, i asked for how we can import data into R i found that it is necessary to make the file in csv format then use L<- read.csv2("path of file")
now i see that the dimension of my table importing into R is 1 colonne (i have realy 20) and (655555) the number of all my lines in the excel file (i want to have only the 2600 lines in my table)
Also, when i say to do
2010 May 31
2
accessing a data frame with row names
Readers,
I have entered a file into r:
,column1,column2
row1,0.1,0.2
row2,0.3,0.4
using the command:
dataframe<-read.table("/path/to/file.csv",header=T,row.names=1)
When I try the command:
dataframe[,2]
I receive the response:
NULL
I was expecting:
row1 0.2
row2 0.4
What is my error with the syntax please?
Yours,
r251
mandriva2009
2004 Nov 23
5
number of pairwise present data in matrix with missings
is there a smart way of determining the number of pairwise present data
in a data matrix with missings (maybe as a by-product of some
statistical function?)
so far, i used several loops like:
for (column1 in 1:99) {
for (column2 in 2:100) {
for (row in 1:500) {
if (!is.na(matrix[row,column1]) & !is.na(matrix[row,column2])) {
pairs[col1,col2] <- pairs[col1,col2]+1
2008 Feb 26
1
Split data.frames depeding values of a column
Hello to all
is there a function wich splits a data.frame (column1,column2,column3,....)
into
data1 <-(column1,column3....) #column2 = 1
data2 <-(column1,column3....) #column2 = 2
data3 <-(column1,column3....) #column2 = 3
...
Regards Knut
2009 May 14
2
Function to read a string as the variables as opposed to taking the string name as the variable
I am writing a custom function that uses an R-function from the
reshape package: cast. However, my question could be applicable to
any R function.
Normally one writes the arguments directly into a function, e.g.:
result=cast(table1, column1 + column2 + column3 ~ column4,
mean) (1)
I need to be able to write this statement as follows:
result=cast(table1, string_with_columns ~
2010 Feb 27
1
New Variable from Several Existing Variables
I am new to R, but have been using SAS for years. In this transition period,
I am finding myself pulling my hair out to do some of the simplest things.
An example of this is that I need to generate a new variable based on the
outcome of several existing variables in a data row. In other words, if the
variable in all three existing columns are "Yes", then then the new variable
should
2009 Jun 15
2
Help with syntax error
Hi,
I have written boxplot commands of this form before, but I don''t quite understand why the function call is reporting a syntax error in this instance. All parameters passed to the function are strings.
Thanks in advance.
Payam
> simplevar <- function(wframe,column1,column2) {
+ tframe <- get(wframe)
+ x1 <- which(names(wframe)==column1)
+ x2 <-
2006 Jun 07
4
Question: coding protected methods
Apologies first, because I need to ramp up on Ruby and coding Ruby in Rails,
however it''s my 3rd day with this beast :) so I''m asking :
When I added protected methods to the model before it was like:
protected
method....................
end
Would this be a valid way to write a protected method as well ?:
attr_protected :column1, :column2
Perhaps this particular call
2009 Jun 17
6
script help
Hi
?
I have a file. list.txt (two columns)
?
column1??? column2
name??????? address
?
?
I need to put in the letter file letter.txt eg:
?
Dear: Chloe
Address: CA
?
Can I use this
?
for i `cat list.txt` | sed 's/Chloe/$i.1; /CA/$i.2/g' $i.letter.txt
?
Thank you for your help
?
?
?
?
?
__________________________________________________________________
Looking for the perfect gift?
2013 Mar 21
2
Displaying median value over the horizontal(median)line in the boxplot
Hi,
set.seed(45)
test1<-data.frame(columnA=rnorm(7,45),columnB=rnorm(7,10)) #used an example probably similar to your actual data
apply(test1,2,function(x) sprintf("%.1f",median(x)))
#columnA columnB
# "44.5"? "10.2"
par(mfrow=c(1,2))
lapply(test1,function(x) {b<-
2004 Oct 25
2
Reading sections of data files based on pattern matching
I am about to write general functions to read the output of simulations
models.
These model generate output files with different sections which I want
to analyze plot etc.
Since this will be used many people at the department I wanted to make
sure that will do this in the best way.
For instance I want to read a snippets of data from a text that look
like this.
2006 Apr 06
1
reshape question
Hi,
I have a data fram like this:
date column1 column2 column3 value1 value2 value3
1-1 A B C 10 5 2
2-1 A B D 5 2 0
3-1 A B E 17 10 7
How can I reshape it to:
date column1 column2 column3 v x
1-1 A B C value1 10
1-1 A B C value2 5
1-1 A B C value3 2
2-1 A B D value1 5
2-1 A B D value2 2
2-1 A B D value3 0
3-1 A B E value1 17
3-1 A B E value2 10
3-1 A B E value3 7
Thx!
Regards,
Richard
2009 Dec 03
2
Dataframe help
Hi there
I have two dataframes
Dataframe_1
column_1 colum_2
121 12345
145 1675
167 2765
Dataframe_2
column_1 column2
121 abc
345 lmn
167 efg
I want a resulting dataframe
121 12345 abc
167 2765 efg
how do i go abt it
Ramya
--
View this message in context: http://n4.nabble.com/Dataframe-help-tp947934p947934.html
Sent from the R
2009 Jul 07
2
How to separate the string?
Hi everyone,
Hi want to separate the string(column1) for example
column1 column2 column3 column4 column5 column6
bear b e a r
cat c a t
tiger t i g e r
I know how to do this in excel where using MID function.
Now I want to solve it using R. The list of strings is in
2005 Dec 31
3
Semi-Dynamic table sorting (without AJAX)
In a previous thread some people were interested in ways to sort a
table. I mentioned a simple method for doing so by using links in the
titles. Having actually tried to implement this strategy, I have come
across several refinements that I would like to share.
First...
your table view should look like this...
...
<table>
<tr>
<th><%= link_to
2006 Jan 04
3
matrix math
I am using R 2.1.1 in an windows XP environment.
I have 2 dataframes, temp1 and temp2.
Each dataframe has 20 variables (“cocolumns") and 525 observations (“rows”). All variables are numeric.
I want to create a new dataframe that also has 20 columns and 525 rows. The values in this dataframe should be the sum of the 2 other dataframe.
(i.e. temp1$column
2003 Aug 07
2
Question about 'NA'
Hi all,
Ive got a database with 10 columns (different
variables) for 100 subjects, each column with
different # of NA's. I'd like to know if it is
possible to use a function to exclude the NA's using
only a specific column, lets say:
Data2 <- omit.exclude(Data1$column1) ??, then
Data3 <- omit.exclude(Data1$column2) and so on
I tried the code above but with no results
Thanks
2009 Aug 12
2
Symbolic references - passing variable names into functions
Hello All,
I am trying to write a function which would operate on columns of a
dataframe specified in parameters passed to that function.
f = function(dataf, col1 = "column1", col2 = "column2") {
dataf$col1 = dataf$col2 # just as an example
}
The above, of course, does not work as intended. In some languages one
can force evaluation of a variable, and then
2010 Feb 09
3
split strings in a vector and convert it to a data.frame
hi,
I have a vector full of strings like;
xy_100_ab xy_101_ab xy_102_ab xy_103_ab
I want to seperate each string in three pieces and the separator should be the "_"
at the end I want a data.frame like:
column1 column2 column3
xy 100 ab
xy 101 ab
xy 102 ab
xy 103 ab
I tried strsplit but I couldn't figure out how to convert the list I get into a data.frame.
I just
2007 Dec 24
2
expand.grid function
useR's,
I have used expand.grid() several times and like the results it gives me. I
am now trying something with it that I have not been able to get to work.
For any n column matrix I would like to run this function on those n columns
and store the results.
For example, if my matrix has 1 column then this is just expand.grid(x =
column1). If my matrix has two columns, then I want