similar to: Merging dataframes

Thanks, Peter, Eivind and Lui Sorry, I could not explain it properly in the first go. Trying to simplify it here with an example - Say I have two dataframes as below that are not equally-sized data frames: Table_A: Email Name Phone abc at gmail.com<mailto:abc at gmail.com> John Chan 0909 bcd at yahoo.com<mailto:bcd at yahoo.com> Tim Ma

Thanks - Peter, Eivind, Rui Sorry, I perhaps could not explain it properly in the first go. Trying to simplify it here with an example - Say I have two dataframes as below that are NOT equally-sized data frames (i.e., number of columns are different in each table): Table_A: Email Name Phone abc at gmail.com John Chan 0909 bcd at yahoo.com Tim Ma

Hi, I'll coded your example into R code: Table_A <- c('abc at gmail.com', 'John Chan', '0909') Table_A <- rbind(Table_A, c('bcd at yahoo.com', 'Tim Ma', '89089')) colnames(Table_A) <- c('Email', 'Name', 'Phone') Table_A Table_B <- c('abc at gmail.com', 'John Chan', 'M',

Hello, Is it something like this that you want? x <- data.frame(a = c(1:3, 5, 5:10), b = c(1:7, 7, 9:10)) y <- data.frame(a = 1:10, b = 1:10) which(x != y, arr.ind = TRUE) Hope this helps, Rui Barradas On 5/1/2018 11:35 AM, Chintanu wrote: > Hi, > > > May I please ask how I do the following in R. Sorry - this may be trivial, > but I am struggling here for this. >

Hi, This is a simple problem, but for the life of me I cannot find the answer. How to determine frequency within given ranges ? I know that table() gives frequency, for example a <- table(numbers) > a numbers 4 5 23 34 43 54 56 65 67 324 435 453 456 567 657 2 1 2 2 1 1 2 1 2 1 3 1 1 1 1 > as.data.frame(table(numbers)) numbers

Hi, A very simple thing that I'm unable to do. I did look at the help but .... While putting a legend on a plot, I don't wish to have the enclosing border surrounding the words (as given below). Tried to use the following, but didn't help : legend (locator(1), border=FALSE, fill=FALSE, "Important ones") legend (locator(1), border=NILL, fill=NILL, "Important

Hi, I am not sure how to fix the following error. LGD <- c(11.6, 12.3, 15.8, 33.1, 43.5, 51.3, 67.3, 84.9) cor (x=(file [1:47231,3:10]), y= rep (LGD, 47231), method = "pearson") Error in cor(x = (file[1:47231, 3:10]), y = rep(LGD, 47231), method = "pearson") : incompatible dimensions > sessionInfo() R version 2.13.0 (2011-04-13)

Hello, I need to upgrade Samba 2.2.2 to a stable Samba version compatible with AIX5.1 . Need to know the samba version I need to download and apply. Tito

I'm looking for a tutorial or notes on the use of contrasts factor in linear model in R, I've found some mails and infos about in various documents about R, but I've probably missed a good review on this subject. -- Robert Espesser Laboratoire Parole et Langage UMR 6057, CNRS 29 Av. Robert Schuman 13621 AIX (FRANCE) Tel: +33 (0)4 42 95 36 26 Fax: +33 (0)4 42 59 50

Hi all, I wish to merge 24 .csv files, each having a common identifier-column ("Name") and do two things: 1. Retrieve the common one's. [Analogy: while merging 2-dataframes, similar to using: merge (.... ,by="Name", all=FALSE) ] 2. Retrieve all, i.e., the union of the rows of 24 files. [again, somthing like: merge (.... ,by="Name", all=TRUE) ] On the web,

Hi, I have got two groups of samples; and for every row, I wish to calculate Kruskal-Wallis' p-value. In the example below, and the stars (****) show where I am struggling to design and put things together. Any help would be appreciated. myFile <- data.frame(Sample_1a = 1:10, Sample_1b = 2:11, Sample_1c = 3:12, Sample_2a=4:13, Sample_2b=7:16, row.names=LETTERS[1:10]) groups <- rep

Hi listers, I want to make lattice plots xyplots with the indication of legends inside each panel with only the points and the lines actually ploted inside each given panel according to the group(ing) factor. The code below shows what I have achieved so far and I hope will make clear what I want to have. It seems to me that my solution is a very "dirty hack" and there certainly is

Hi, I installed Samba on Solaris to enable me print from the solaris workstation to a windows print server. When I start smbd and nmbd , smbd does not run but nmbd runs

I'm getting spec files from centos git which is really convenient when the related source is easy to find. But some things - e.g. from a spec file # How to create the source tarball: # # git clone git://git.fedorahosted.org/git/python-rhsm.git/ # cd client/python-rhsm # tito build --tag python-rhsm-$VERSION-$RELEASE --tgz Never used tito before, so I install it and try, and rather than

Hi, I wonder why my attempt to extend an existing loess fit to a new data set is producing error. I was trying the following: dat = read.csv(choose.files()) x = dat[,2]; y = dat[,1] x.sort = sort(x) y.loess = loess(y~x, span=0.75) # For testing the above fit with a new dataset: test = read.csv(choose.files()) # test data new_x = test [,1]; new_y = test[,2] new_x.sort = sort(new_x) predicted

Hi, I have two dataframes (Dataframe_A, Dataframe_B) with the same no. of columns. The first column of both the dataframes contains unique names. I wish to have Dataframe_A with the rows that are NOT common to Dataframe_B. With merge (), it is possible to get the common rows or to merge rows, but I am not quite sure how to do it in a simpler way. Any help would be much appreciated. Thank you.

Hi, I understand that to test the significance of correlation between two PAIRED variables, the function, cor.test () can be used. However, in my case, I have tested the correlation (i.e., Correlation Coefficient, r) between two independent (i.e, different) variables, and now I wish to test for the statistical significance of the correlation. Could you please suggest how I should do that. Thank

Thanks for the info so far. I am still trying to asterisk'ize my ML9.2 firewall box and can't get the external SIP registration to work. If I hook up my Sipura directly to the WAN it registers OK. This is the message I get from asterisk: Mar 8 21:03:07 NOTICE[196621]: chan_sip.c:3140 sip_reg_timeout: Registration for '263872@192.246.69.223' timed out, trying again If tried

Buenas, compañeros. Tengo una base de datos con bastantes variables todas medidas como factor, quiero que todos los factores pasen a ser variables binarias en función de sus valores. En este ejemplo de Stackoverflow muestran como hacerlo con una variable: https://stackoverflow.com/questions/33990760/converting-factors-to-binary-in-r df <-data.frame(a = c(1,2,3), b = c(1,1,2), c =

Hi listers, A few days ago I posted a question about the use of the stars function on selected lines of a frame. Thanks to two helpers, a closer look at the scale argument allowed to partially solve the problem. Yet I still have a problem with stars. Allow me to explain what I intend to do (sorry for my poor English and the long post): I want to graph an activity index of a fish during the day