similar to: Issue with concatenation of URL losing

a) you need to read the help pages on the paste function... more likely you are looking for the paste0 function because extra spaces will most likely break the GET request format. b) quotes do not become "stuck" as \" ... that is a visual representation intended to clarify that that quote is not terminating the string but is actually part of it. If you want to see the contents

Dear People, I wrote the following bit of C code and (along with other bits) called it mycode.c, and compiled the file into a shared library to load into R, using R CMD SHLIB mycode.c. This was Ok, but when I tried to load this into R using dyn.load("mycode.so") I got the error > dyn.load("mycode.so") Error in dyn.load(x, as.logical(local), as.logical(now)) : unable to

Hey, I don;t know if anyone has come across this error before... I am running R on the terminal of my MAC OS X 10.3.4 and I have written C code and compiled it using R CMD SHLIB mycode.c There were no problems in compiling so I now have mycode.o and mycode.so. I used dyn.load("mycode.so") and again, no problems. But when I try to use the code .C("mycode",x)

Desde el terminal de Ubuntu, he conseguido descargar los datos usando esto: DESCARGAR LISTA DE ESTACIONES wget --method GET --header 'cache-control: no-cache' --no-check-certificate --output-document - https://opendata.aemet.es/opendata/api/valores/climatologicos/inventarioestaciones/todasestaciones/?api_key=*vuestra api key* DESCARGAR DATOS HISTÓRICOS Diciembre 2017, ALICANTE wget

Hi, exists("foo", inherits=TRUE) check whether an object named "foo" exists, and get("foo", inherits=TRUE) retrieves it. I'm looking for a similar function to exists() that returns the environment where the object "foo" exists, iff at all. If not found, NULL is returned. Does that exist? EXAMPLE #1: > sample2 <- base::sample > env <-

Dear R-helper: Suppose we have a matrix: Gene sample1 sample2 Gcnt1 12.0000 52.80000 Max 8.8000 39.10000 Tmem176b 67.9000 304.70000 Shmt2 8.6000 42.40000 Rtn4 11.5000 57.70000 Il17re 7.6000 38.80000 Bclp2 6.2000 32.10000 Mobkl3 4.4000 32.20000 Akr1b10 3.4000 30.10000

R 2.7.2 Windows XP I am using apply to compute a series of Student's t-test from two matrices, sample1 and sample2. boo<-apply(sample1,1,t.test,sample2) I want to pick of the p-values from the tests, but can't seem to get it to work. I have tried several methods to get the values including: boo<-apply(sample1,1,t.test$t.test,sample2) boo<-apply(sample1,1,t.test,sample2)$t.test

Hello all, I have what feels like a simple problem, but I can't find an simple answer. Consider this data frame: > x <- data.frame(sample1=c(35,176,182,193,124), sample2=c(198,176,190,23,15), sample3=c(12,154,21,191,156), class=c('a','a','c','b','c')) > x sample1 sample2 sample3 class 1 35 198 12 a 2 176 176

Hi group, This is how my test file looks like: Chr start end sample1 sample2 chr2 9896633 9896683 0 0 chr2 9896639 9896690 0 0 chr2 14314039 14314098 0 -0.35 chr2 14404467 14404502 0 -0.35 chr2 14421718 14421777 -0.43 -0.35 chr2 16031710 16031769 -0.43 -0.35 chr2 16036178 16036237 -0.43 -0.35 chr2 16048665 16048724 -0.43 -0.35 chr2 37491676 37491735 0 0 chr2 37702947 37703009 0 0

This is what I am starting with: initial<- matrix(c(1,5,4,8,4,4,8,6,4,2,7,5,4,5,3,2,4,6), nrow=6, ncol=3,dimnames=list(c("1900","1901","1902","1903","1904","1905"), c("sample1","sample2","sample3"))) And I need to apply a filter (in this case, any value <5) to give me one dataframe with only the

hi all - i have a source package i'm writing that i'd like to be able to install with a special library that my R src files rely on. to be more precise, i have a normal R package directory structure (i.e. src/ R/ man/ DESCRIPTION NAMESPACE etc.). i also have another directory here called depPkg, and it has it's own configure file for the canonical './configure && make

Hopefully an easy one, how do I merge two or more SQL query results? Example: result1 = find_by_sql(x) result2 = find_by_sql(y) What is the best way to merge result1 and result2? I want to be able to reference the objects as if they were obtained via one query. Cheers, Dan

Dear List Members, I have two small samples (n=20), the distributions are highly skewed. Does it make any sense to do a boostrap test to check for difference in means? And if so, could this be done like this: x <- numeric(10000) for(i in 1:10000) { x[i] <- mean(sample(sample1,replace=TRUE)) - mean(sample(sample2,replace=TRUE)) } (mean(sample1)-mean(sample2))/sd(x) Regards, Erika

Dear Group, I am having a function that I am running in a loop that generated two results for each loop The result1 is a zoo object The result2 is a data frame Now I want to put both of them in a list or some structure ... that I can access or output to a file after the loop is done. For e.g. for (i in 1:20){ niceFunction(x[i],i) } niceFunction (x,i) { result1 = someOperations() #zoo

Hello I am trying to find an automated way of fitting a mixture of normal and log-normal distributions to data which is clearly bimodal. Here's a simulated example: x.1<-rnorm(6000, 2.4, 0.6)x.2<-rlnorm(10000, 1.3,0.1)X<-c(x.1, x.2) hist(X,100,freq=FALSE, ylim=c(0,1.5))lines(density(x.1), lty=2, lwd=2)lines(density(x.2), lty=2, lwd=2)lines(density(X), lty=4) Currently i am using

Hi Group, I have a data frame below. Within this data frame there are samples (columns) that are measured more than once. Samples are indicated by "idx". So "id1" is present in columns 1, 3, and 5. Not every id is repeated. I would like to create a new data frame so that the repeated ids are averaged. For example, in the new data frame, columns 1, 3, and 5 of the original

Dear All, I have a database of 200 observations named myD. In the dataframe there are a column named code (with codes varying from 1 to 77), a column named "prevalence" with some quantitative measurements are given and an column named Pr_mean, with no values. I would like to set a cycle to compute the average of prevalence values for each different code and store the averages under the

I have searched the r-help files but have not been able to find an answer to this question. I apologize if this questions has been asked previously. (Please excuse the ludicrousness of this example, as I have simplified my task for the purposes of this help inquiry. Please trust me that something like this will in fact be useful what I am trying to accomplish. I am using R 2.4.1 in Windows XP.)

Hi all, I am processing 24 samples data and combine them in single table called CombinedSamples using following: CombinedSamples<-rbind(Sample1,Sample2,Sample3) Now variables Sample1, Sample2 and Sample3 have many different columns. To make it more flexible for other samples I'm replacing above code with a for loop: #Sample is a string vector containing all 24 sample names for (k in

I''m just wondering what the best way to go about loading my API keys from the database is ... Should I simply place them in the ENV variable? Is there a way better way to go about this?