similar to: List of occuring values

unique(x) will give you the distinct values in x. table(x) will give you the distrinct values and their frequencies as an array with dimnames. data.frame(table(x)) will give you a 2-column data.frame with the distinct values and their frequencies. > values <- c("Small", "Large", "Large", "Large") > unique(values) [1] "Small"

Dear Everybody, Enclosed are the tiny beginning of a program and its output. As a pity, if I load the image <load("kanal.RData")> the elements of <de.dd> are non numerical; <de.dd[2]+de.dd[3]> returns <Fehler in de.dd[2] + de.dd[3] : nicht-numerisches Argument f??r bin??ren Operator>. How can I keep the numbers numerical? Thank you in advance. hopefully, Mag.

Dear everybody! I am analysing data from an enquette. The answers are either A or B. How can I draw a histogram without transforming the data from characters to numbers? If the data are saved in a list M, hist(M[,1]) returns: Error in hist.default(M[, 1]) : `x' must be numeric Execution halted Thank you in advance!

Dear everybody! Is there a command to add elements to an existing list, at best excluding the addition of already included ones? Thank you in advance. Yours, Mag. Ferri Leberl

Dear everybody! I am making a graph in R and employ pstoedit to expot the .pdf-output to .svg. When I open the .svg with firefox I get the .svg-code shown wit the following header: "Mit dieser XML-Datei sind anscheinend keine Style-Informationen verkn?pft. Nachfolgend wird die Baum-Ansicht des Dokuments angezeigt." Which information should how be included? Thank you in advance. Yours,

What does this warning mean precisely? Is there any reason to care about it? Can I Avoid it by another way of programming? Thank you in advance.

Dear everybody, How can I transform numbers to a positional system with the base of, e.g., nine, and do further operations with them? Thank you in advance Yours, sincerely Mag. Ferri Leberl

Dear everybody! take a<-c(5,3,NA,6). if(a[1]!=NA){b<-7} if(a[3]!=5){b<-7} if(a[3]!=NA){b<-7} if(a[3]==NA){b<-7} will alltogeather return Fehler in if (a[1] != NA) { : Fehlender Wert, wo TRUE/FALSE n?tig ist (or simularly). Somehow this is logical. But how else should I get out, whether a certain vector-component has an existing value? Thank you in advance! Yours, Mag. Ferri

Dear Everybody! I want to export data to LaTeX. As I want to employ the data as freely as possible I want to avoid the xtable-command and instead generate some List like \MyOwnPrettyCommand{Adam}{Auer}{17} \MyOwnPrettyCommand{Bertram}{Bauer}{14} \MyOwnPrettyCommand{Christoph}{Huber}{75} \MyOwnPrettyCommand{Damian}{Dorfer}{69} \MyOwnPrettyCommand{Emanuel}{Eder}{43} with \MyOwnPrittyCommand

Dear everybody! If I have an array of numbers e.g. the points my students got at an examination, and a key to group the numbers, e.g. the key which interval corresponds with which mark (two arrays of the same length or one 2x(number of marks)), how can I get the array of absolute frequencies of marks? I hope I have expressed my problem clearly. Thank you in advance. Mag. Ferri Leberl

Dear everybody! Please find attached a tiny R-program. It returns: [,1] [,2] [1,] 53.55 NA [2,] 53.55 NA [3,] 53.55 NA How can I manage the first column to show the second component not only of the first list in k??ste but of the second component of every list in k??ste respectively, such as to get the following array returned: [,1] [,2] [1,] 53.55 NA [2,] 53.87 NA [3,] 53.87

Dear Mag. Ferri Leberl, I'm using something like: ----------------------- tex.tex --------------------------- \documentclass{article} \usepackage{graphicx} \usepackage{fancyvrb} \newcommand{\Rlogo}{\protect\includegraphics[height=1.8ex,keepaspectratio]{Rlogo.pdf}} \newcommand{\myinput}[1] {\begin{scriptsize} \VerbatimInput[frame=single,label=#1]{#1} \end{scriptsize}} \title{The R logo,

Dear Mag. Ferri Leberl, I'm using something like: ----------------------- tex.tex --------------------------- \documentclass{article} \usepackage{graphicx} \usepackage{fancyvrb} \newcommand{\Rlogo}{\protect\includegraphics[height=1.8ex,keepaspectratio]{Rlogo.pdf}} \newcommand{\myinput}[1] {\begin{scriptsize} \VerbatimInput[frame=single,label=#1]{#1} \end{scriptsize}} \title{The R logo,

Dear everybody! I have load a list A of numbers and want a histogram to be drawn. on hist(Y) the Machine returns: Error in hist.default(A) : `x' must be numeric I found out, that the list is of type data.frame. Y<-as.numeric(Y) returns Error in as.double.default(A) : (list) object cannot be coerced to double What schould I do? Than you in advance!

Dear everybody, In our game-theory lesson we have run several classroom-experiments where the students had to decide for a natural number between one and seven. I have troubles now to visualize the results: be a the vector of answers. hist(a) will not assume natural numbers as answers, but rational. It will make the brakes exactly at the natural numbers, which is difficult to interpret, as

Dear everyone! Since I saved the workspace-image I get the same row of random-numbers everytime I run R. How can I make the random-numbers random again? Thank you in advance!

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I have installed package xtable with su -c 'R CMD INSTALL xtable' and got this promising feedback: * Installing *source* package 'xtable' ... ** R ** data ** help >>> Building/Updating help pages for package 'xtable' Formats: text html latex example * DONE (xtable) Despite that, R returns: Error: couldn't find function "print.xtable"

Full_Name: Morten Welinder Version: 2 OS: Solaris/space/gcc2.95.2 Submission from: (NULL) (65.213.85.217) I changed src/nmath/standalone/test.c to read: --------------------------------------------------------------------------------- #define MATHLIB_STANDALONE 1 #include <Rmath.h> #include <stdio.h> int main() { double x; for (x = 99990; x <= 100009; x++) printf

Hola Alguien me podría decir como hacer una grafica del tipo persp() de la densidad de una distribucion normal bivariante estandarzada con correlacion 0.5?? gracias [[alternative HTML version deleted]]