similar to: remove quotes from matrix

Dear all; Thanks. Here are the dput results as Duncan suggested. Regards, Greg structure(list(Sub_Pathways = structure(c(3L, 3L, 3L, 3L, 3L), .Label = c("Acetylated_Peptides", "Advanced_Glycation_End-product", "Alanine_and_Aspartate", "Aminosugar", "Ascorbate_and_Aldarate", "Carnitine", "Ceramides", "Creatine",

Works fine for me. What do you object to in the following? Calling the above df "d", > dm <- as.matrix(d) > dm Sub_Pathways BMI_beta SAT_beta VAT_beta 1 "Alanine_and_Aspartate" " 0.23820" "-0.02409" " 0.94180" 2 "Alanine_and_Aspartate" "-0.31300" "-1.97510" "-2.22040" 3

On 19/09/2017 9:47 AM, greg holly wrote: > Hi all; > > I have data at 734*22 dimensions with rows and columns names are > non-numeric.When I convert this data into matrix then all values show up > with quotes. Then when I use > x1= noquotes(x) to remove the quotes from the matrix then non-numeric row > names remain all other values in matrix disappear. > > Your help is

Hi Duncan and Bert; I do appreciate for your replies. I just figured out that after x1= noquotes(x) commend my 733*22 matrix returns into n*1 vector. Is there way to keep this as matrix with the dimension of 733*22? Regards, Greg On Tue, Sep 19, 2017 at 10:04 AM, Duncan Murdoch <murdoch.duncan at gmail.com> wrote: > On 19/09/2017 9:47 AM, greg holly wrote: > >> Hi all;

Friends I can't quite find a direct answer to this question from the lists, so here goes: I have several dataframes, 200+ columns 2000+ rows. I wish to script some operations to perform on some of the variables (columns) in the data frames not knowing what the column number is, hence have to refer by name. I have variable names in a text file "varlist". So, something like this:

The source to the noquote() function looks like this: noquote <- function(obj, right = FALSE) { ## constructor for a useful "minor" class if(!inherits(obj,"noquote")) class(obj) <- c(attr(obj, "class"), if(right) c(right = "noquote") else "noquote") obj } Notice what happens with right =

It is very wierd... Can some of you confirm the following behavior ? It is a new bug (feature ?) which was not yet in 0.49 ... noquote <- function(obj) { ## constructor for a useful "minor" class if(!inherits(obj,"noquote")) class(obj) <- c(class(obj),"noquote") obj } "[.noquote" <- function (x, subs) structure(unclass(x)[subs], class =

Hi everybody, I would like to count how many times names in list L, nombreL, apear in list C, nombreC. Can I improve the next program? cuenta <- 0 topL <- length(nombreL) topC <- length(nombreC) for (i in 1:topL) { for (j in 1:topC) { k <- grep(noquote(nombreL[i]),nombreC[j])

Hi R, When I use the below to write the text file try=data.frame(rep("a",5), rep("b",5)) write.table(try,"z:\\try.txt",row.names=F,col.names=F,sep="\t") the output contains two columns with quotes! Is there a way to write without quotes? I tried try[,1]=noquote(try[,1]) try[,2]=noquote(try[,2]) Thank you, Regards, Ravi Shankar

Full_Name: Franc Brglez Version: R 2.9.1 GUI 1.28 Tiger build 32-bit (5444) OS: MacOSX -- 10.6.2 Submission from: (NULL) (24.148.163.114) I am demonstrating what may be a bug or my lack of experience. Please review as it would help to hear from someone. MANY THANKS -- Franc Brglez The function "binS2binV" returns what I consider a wrong value -- see the terminal output binS2binV =

I currently have a program that automates 2-way ANOVA on a series of endpoints, but before the ANOVA is carried out I want the code to test the assumptions of normality and equal variance and report along with each anova result in the output file.  How can I do this? I have pasted below the code that I currently use.   library(car) numFiles = x #

I'm using R 1.8.1 on Red Hat Linux 9. I've worked out the linear model decomposition by hand. Using "aov" with "Error" to fit a split-plot model, I get very different results depending on whether I use the "data" argument for "aov" or not. When I use the "data" argument, the ANOVA table from "summary" is correct but the

Hello, I'm having difficulty passing an object name to a lapply function. Can somebody tell me the trick to make this work? #Works T13702 <- TRACKDATA[["13702.xls"]][["data"]] min(unlist(lapply(list(T13702), function(x) mdy.date(x[1, 2], x[1, 1], x[1, 3])))) 16553 #Works d<-2 assign(paste("T",substr(names(TRACKDATA)[d],1,(nchar(names(TRACKDATA)[d]

G'day all, I am trying to use a string as an argument in a selection but things are not working as I expect, seems the selection is not seeing the expanded string and I do not know how to make it. Perhaps the noquote class value that is returned is the problem. Here is an example. > selection #this is my string [1] "attackprogress$Se=='Toona ciliata [19825: JMM35]'"

I haven't been able to get anywhere tracking this down. It seems that c.noquote() does something strange with its third (and subsequent) parameters: R-2.7.0 under NetBSD, R-2.6.0 under Solaris, and R-2.8.0 (unstable) (2008-06-10 r45893) under WinXP, I get: > c(noquote('z'), 'y', 'x', '*') [1] z y x * x * > or: > c(noquote('z'),

Is it possible to use "paste" to write out an expression and evaluate it? Suppose I want to add two vectors X1 and X2, defined as follows: X1 <- 1:6 X2 <- 6:1 If I write the following it looks like what I want but is a character: noquote(paste(paste("X", 1, sep = ""), paste("X", 2, sep = ""), sep = "+")) Is there a way to tell R

  Dear R-helpers, hello I am seeking your help in somehow getting names of variables without quotes (" "). Let us say, we have a table with 3 variables V1, V2 and V3. After the table is read, I get names of the variables (thro' the following code) as under quotes (like "V1" rather than the original representation V1)  

Dear all, I am trying to read in and assign data from 50 tables in an automated fashion. I have the following code, which I created with the help of textbooks and the internet, but it only seems to read in the final data file over and over again. For example, when I type:> table_1951 I get the same values in the table as when I type> table_2000 despite the values in the source tables

I'm new to R (previously used SAS primarily) and I have a genetics data frame consisting of genotypes for each of 300+ subjects (ID1, ID2, ID3, ...) at 3000+ genetic locations (SNP1, SNP2, SNP3...). A small subset of the data is shown below: SNP_ID SNP1 SNP2 SNP3 SNP4 Maj_Allele C G C A Min_Allele T A T G ID1 CC GG CT AA ID2 CC GG CC AA ID3 CC GG nc AA

Hi, I apologize if the solution is right in front of me, but I can't find anything on how to convert a class of 'noquote' to 'matrix'. I've tried as.matrix and I've tried coercing it by 'class(x)<-matrix', but of course that didn't work. I've been using the function 'symnum' which returns an object of class 'noquote'. Here is an