similar to: Case statement in sqldf

2018-03-3 in your code should be 2018-03-31. The line then'201415' needs to be fixed. When posting please provide minimal self-contained examples. There was no input provided and library statements not relevant to the posted code were included. Fixing the invalid date and bad line, getting rid of those library statements that are unnecessary and providing some test input, it works

> On Sep 11, 2017, at 1:05 AM, Mangalani Peter Makananisa <pmakananisa at sars.gov.za> wrote: > > Hi all, > > I am trying to create a new variable called Fiscal Year (FY) using case expression in sqldf and I am getting a null FY , see the code below . > > Please advise me as to how I can do this mutation. > > library(zoo) > library(lubridate) >

Dear all, I recently read the book " R data preperation and manipulation using sqldf package" by Djoni Darmawikarta However, I have a problem with manipulation of dates using this package, I do not get the expected results. Do I need to install some packages to be able to subset the data by dates in sqldf? I am not getting Djoni Darmawikarta email address. Please see the practice

See FAQ #4 on the sqldf github home page. On Fri, Aug 11, 2017 at 9:21 AM, Mangalani Peter Makananisa <pmakananisa at sars.gov.za> wrote: > Dear all, > > I recently read the book " R data preperation and manipulation using sqldf package" by Djoni Darmawikarta > However, I have a problem with manipulation of dates using this package, I do not get the expected results.

Thank you very much for the support. I have just used the reshape library and my problem was solved. Kind regards, Peter -----Original Message----- From: Jeff Newmiller [mailto:jdnewmil at dcn.davis.ca.us] Sent: 10 July 2017 03:52 PM To: r-help at r-project.org; Mangalani Peter Makananisa; r-help at r-project.org Cc: Vito Ricci (vito_ricci at yahoo.com) Subject: Re: [R] dplyr help I am

A better thanks would be to post the solution that met your needs... particularly since in spite of our efforts it appears we may not have understood your problem. A small sample data set generated with dput along with your code would be helpful in making sure others learn along with you. -- Sent from my phone. Please excuse my brevity. On July 11, 2017 12:56:45 AM PDT, Mangalani Peter

Dear R Gurus, I am currently working on the two dataset ( A and B), they both have the same fields: ID , REGION, OFFICE, CSTART, CEND, NCYCLE, STATUS and CB. I want to merge the two data set by ID. The problem I have is that the in data A, the ID's are unique. However in the data set B, the ID's are not unique, thus some repeat themselves. How do I the merge or retrieve the

HI all, Is it possible to use one column spread on multiple columns values. example spread( Key_col, value1:value7) spreading Key_col to variable value1, value2, ....... Value7 Please advise, Kind regards Mangalani Peter Makananisa (5786) South African Revenue Service (SARS) - HO +2782 456 4669 / +2712 422 7357 Please Note: This email and its contents are subject to our email legal notice

Dear R-Gurus, I am trying to read in data with 24,349,113 rows to R-3.3.3 (64 bit) and have used the library "data.table" and It managed to read 23,347,070 rows and the remainder was 2,043 rows only. Could you please advise me as to which library/R-commands is suitable to read the full data in to R? Kind regards, Mangalani Peter Makananisa (5786) South African Revenue Service

I am pretty sure that this is not a question about dplyr... it is a question about tidyr. Look at the help file ?tidyr::spread. If I understand your question (I may not, because you gave no example of input/output data), the answer is no, the column names come from the column named by the key parameter and the values that fill those columns come from the column named by the value parameter.

Dear all, Please help me with the R code which compute SCHEFFE TEST Thanking you in advance Kind regards Mangalani Peter Makananisa Statistical Analyst South African Revenue Service (SARS) Segmentation and Research : Data Modelling Tel: +2712 422 7357 Cell: +2782 456 4669 Fax:+2712 422 6579 Please Note: This email and its contents are subject to our email legal notice

Hi something like dcast(temp2, minuty~pokus) ? > dput(temp2) structure(list(pokus = structure(c(1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 3L, 3L, 3L, 3L, 4L, 4L, 4L, 5L, 5L, 6L, 6L, 7L, 7L, 8L, 8L ), .Label = c("T42", "T43", "T44", "T45", "T46", "T47", "T48", "T49"), class = "factor"), minuty = structure(c(2L,

Dear all, I'm using garchFit from fSeries package and I am not getting the desired results (error message : could not find function "garchFit" ). Would you please advise as to how I can build an ARIMA(p, d, q) - GARCH(p,q) model using R see the attached data and R-output. Thanking you in advance Kind regards Mangalani Peter Makananisa Statistical Analyst South

Dear "R Gurus", I am having two dummy csv data sets A and B containing 19 and 15 cases/observations respectively. From the two data set 13 cases are intersection. From one of the two (any) data set, How do I then retrieve the unmerged data ? let's take A for example, six cases must appear in our results. See the R codes below. Please assist. Looking forward to hearing

Dear R gurus, I am currently using the chron package for date manipulation in R and I am able to control the date which take the format - 1998/07/03, and - 2006-09-15 (date without time) Library(chron) As.Date(2006-09-15, format = '%Y-%m-%d') However I have a problem with the date containing only the year and month (i.e. 2006-09, 2007/08, 200609).

Sent from Samsung tablet. Dear all, ? I recently read the book ? R data preperation and manipulation using sqldf package? ?by Djoni Darmawikarta? However, I have a problem with manipulation of dates using this package, I do not get the expected results. Do I need to install some packages ?to be able to subset the data by dates in sqldf? ? I am not getting Djoni Darmawikarta?email address. ?

hey I am trying to turn a dataframe into xts with the function: as.xts, but it returns the error: Error in as.POSIXlt.character(x, tz, ...) : character string is not in a standard unambiguous format could someone give me some pointers please the data is coming from a spreadsheet via the excel, and has 5 columns of data (date (with the date and time), open, high, low, close) (excel format) ela

Hello, sorry for incomplete code... with this I read the file and calculate my stuff. I have a plenty of them 80-300K every 5 Kelvin. I start with 79K, 80K...300K test<-read.table("T300_both.txt",header=FALSE,sep="") RH2<-c(RH2,2.5e7*.32e-4/100e-6/5100*(test$V3[c(2)]-test$V3[c(1)]+test $V3[c(4)]-test$V3[c(3)])) n2<-c(n2,-1/(RH2[c(46)]*1.60217e-19))

Hello R community, I am computing weighted average statistic by using ddply function: My data set is: N1 T1 S1 I1 C1 FY-4 ROE11 EPS11 MKT11 N1 T1 S1 I1 C1 FY-3 ROE12 EPS12 MKT12 N1 T1 S1 I1 C1 FY-2 ROE13 EPS13 MKT13 N1 T1 S1 I1 C1 FY-1 ROE14 EPS14 MKT14 N1 T1 S1 I1 C1 FY0 ROE15 EPS15 MKT15 N1 T1 S1 I1 C1 FY1 ROE16 EPS16 MKT16 N1 T1 S1 I1 C1 FY2 ROE17

Hello Group, I am having trouble with the sqldf package on unix. The same code works fine on windows. Silly Example script: # Load the package library(sqldf) # Use the titanic data set data(women) colnames(women) head(women) sqldf('select height, count(*) from women where height is not null group by weight') Unix Output and error: bash-3.00$ R --vanilla <testR.R