similar to: dygraphs, multiple graphs and shiny

Hi all, I am trying to figure out how to do this in R and I need your help. My journey started from something like the following: http://stackoverflow.com/questions/11365857/real-time-auto-updating-incremental-plot-in-r/1#1 n=1000 df=data.frame(time=1:n,y=runif(n)) window=100 for(i in 1:(n?\window)) { flush.console() plot(df$time,df$y,type='l',xlim=c(i,i+window)) Sys.sleep(.09) }

Hi all, I am trying to figure out how to do this in R and I need your help. My journey started from something like the following: http://stackoverflow.com/questions/11365857/real-time-auto-updating-incremental-plot-in-r/1#1 n=1000 df=data.frame(time=1:n,y=runif(n)) window=100 for(i in 1:(n?\window)) { flush.console() plot(df$time,df$y,type='l',xlim=c(i,i+window)) Sys.sleep(.09) }

Need Help in Debugging below script:-------------------------------- dat <- get_majorlandmarks(dat,Dmin,Per) fit_xts <- xts(dat$fit,order.by = dat$Date,frequency = 365) close_xts <- xts(dat$Close, order.by = dat$Date, frequency = 365 ) majorlandmarks_xts <-xts(dat$Close[dat$majorlandmarks==TRUE], order.by = dat$Date[dat$majorlandmarks==TRUE], frequency = 365 ) minorlandmarks_xts

Carlos el código es el ejemplo de shiny: # # This is a Shiny web application. You can run the application by clicking # the 'Run App' button above. # # Find out more about building applications with Shiny here: # # http://shiny.rstudio.com/ # #setwd("C:/curso 2017-18/curso R/shiny/prueba1") library(shiny) # Define UI for application that draws a histogram ui <-

Estimados miembros de la lista. Estoy usando 2 funciones del paquete vcd y obtengo resultados que parecen discrepar entre ambas funciones. > dput(peces) c(26L, 63L, 1L, 21L, 20L, 50L, 0L, 104L, 19L, 0L, 8L, 32L, 0L, 24L, 5L, 2L, 0L, 36L, 0L, 5L, 27L, 1L, 13L, 24L, 15L, 25L, 23L, 5L, 37L, 26L, 29L, 14L, 15L) La función Ord_plot me dice que la mejor distribución para los datos es binomial

Hi all, I am new. I am installing the library sjPlot on Ubunto 16.10 and I guess it is installing some dependencies. But it is taking more than 1.5 hours, is it possible? It has right now halted (hope momentarily) in installing the package 'rstan', particularly the file lang__grammars__statement_grammar_inst.o Other packages installed include: dygraphs, colourpicker, raster. Is it good

De acuerdo Carlos pero en mi ordenador no funciona y me da el error que he comentado. Muchas gracias por tu colaboración. Saludos, Juan El 04/03/2018 a las 20:09, Carlos J. Gil Bellosta escribió: Corre perfectamente en mi máquina si borro la última línea (print(environment(show))). Simplemente, he creado un directorio vacío (/tmp/prueba), he copiado el código (menos esa última línea) en el

That is very strange. I am using Ubuntu 16.04 and managed to install it in less than 5 minutes. OA On Wed, Jan 10, 2018 at 12:00 PM, Luca Danieli <mr.lucedan at hotmail.it> wrote: > Hi all, > > I am new. I am installing the library sjPlot on Ubunto 16.10 and I guess > it is installing some dependencies. But it is taking more than 1.5 hours, > is it possible? > > It

When I run the "acf()" function using the "acf(ts.union(mdeaths, fdeaths))" example, the "acf()" function calls the "acf.plot()" function to generate this plot... http://members.cox.net/ddebarr/images/acf_example.png The plot in the lower right-hand corner is labeled "fdeaths & mdeaths", but the negative lags appear to belong to "mdeaths

Full_Name: Wolfgang Koller Version: 1.0.0 OS: linux Submission from: (NULL) (137.208.7.48) > data(UKLungDeaths) > ts.union(mdeaths, fdeaths,dframe=TRUE) Error in names<-.default(*tmp*, value = nmsers) : names attribute must be the same length as the vector > cbind(mdeaths, fdeaths,dframe=TRUE) Error in names<-.default(*tmp*, value = nmsers) : names attribute

### First, is there a way to access a univariate time series as a matrix instead of a vector? # For example: data(UKLungDeaths) # If I do apply(mdeaths,1,cumsum) # Gives an error as mdeaths is not a matrix but a vector, although when I look at it : mdeaths # the ts object has a matrix like "appearance" # The only way of doing it I've found is: mdeaths2<-as.matrix(mdeaths)

Estimados compañeros tengo un problema con shiny. Es un problema local de mi ordenador, porque en otro va si problemas pero no consigo saber ¿cómo arreglarlo?. He instalado incluso la nueva versión de Rstudio. Os explico: 1) lanzo el programa app.R, el ejemplo de shiny e intenta mostrar los resultados pero si hago: print(environment(show)) da como resultado Error in func(fname, ...) : app.R did

I am looking for a way to produce a "distribution graph" as in the example: (http://cecsweb.dartmouth.edu/release1.1/datatools/dgraph.php?year=2003&geotype=STD_HRR&event=A01_DIS&eventtype=UTIL Anybody who can help? Christian von Plessen Department of Pulmonary Medicine Haukeland university hospital Bergen Norway

Reading "Modern Applied Statististics with S" and trying the corresponding examples both in the book and in ../lib/R/library/MASS/script, I'm now trying chapter 4 plotting bars with the following code on a linux box with R 1.8.1: ---------------------- library(MASS) library(lattice) options(echo=T, width=65, digits=5) lung.deaths <- aggregate(ts.union(mdeaths, fdeaths), 1)

Hi all i need to put on one graph 2 functions who's x axis is the same and y not. I mean on horizontal the time, and on vertical left: pressure, on vertical right: rpm of a motor, is R able to do that? i've found this that i could adapt maybe (i don't need time series really?) :/ : (http://tolstoy.newcastle.edu.au/R/help/04/03/1456.html) ## ## Description: A simple function which

Hi, this is probably a very newbie statistical question. I have some experimental data. My hypothesis is that the data are binomially distributed with a known N and p. I am trying to obtain a sort of p-value to tell me whether or not my hypothesis is correct. What can I do with R? Thank you, Pier Luca

Dear R experts: Can you help me to overlap a histogram and theoretical density curve of poison distribution? for example data like this: The numbers of sanils found in each of 100 sampling quadrats in an area were as follows: number of snails, r 0 1 2 3 4 5 8 15 f=frequency of r 69 18 7 2 1 1 1 1 apparently this is not Poison but near to Poison, How to overlap the theoretical desity curve to

I ran across this problem when playing with ccf(). Its function call is >function (x, y, lag.max = NULL, type = c("correlation", "covariance"), plot = TRUE, na.action = na.fail, ...) Internally, ccf() calls plot(), which digs up plot.acf() whose default style is type='h' . I wanted to pass the argument type='l' to the plotting routine, but of

Hello, what is the meaning of the plots of an acf()-plot, when using a data frame as argument? The result is NOT obvious for me. There are combinations of the columns of a dataframe in the reulting plot. But an acf() is just defined for onyl one time-sreies. So what do the plots mean? I did not found a description in the help-page. Ciao, Oliver

I am trying to run a cross-correlation using the "ccf()" function. When I select plot = TRUE in the ccf() I get a graph which has ACF on the y-axis, which would suggest that these y-values are the auto-correlation values. How should I adjust the code to produce a plot that provides the cross-correlation values? Here is my code: w002dat <-