similar to: comparing two strings from data

It's generally a very good idea to examine the structure of data after you have read it in. str(data2) would have shown you that read.csv() turned your strings into factors, and that's why the == operator no longer does what you think it does. use ... data_2 <- read.csv("excel_data.csv", stringsAsFactors = FALSE) ... to turn this off. Also, the %in% operator will achieve

Combining and completing the advice from Greg and Boris the complete solution is two lines: data_2 <- read.csv("excel_data.csv", stringsAsFactors = FALSE) match_list <- match( data_2$data1, data_2$data2 ) The vector match_list will have the matching position when it exists and NA's otherwise. Its length will be the same as the length of data_2$data1. You should get

Hi there I have two dataframes Dataframe_1 column_1 colum_2 121 12345 145 1675 167 2765 Dataframe_2 column_1 column2 121 abc 345 lmn 167 efg I want a resulting dataframe 121 12345 abc 167 2765 efg how do i go abt it Ramya -- View this message in context: http://n4.nabble.com/Dataframe-help-tp947934p947934.html Sent from the R

How would one server out to excel a html table with the mime/content type application/vnd.ms-excel ? In PHP it would be something like ?php header("Content-Type: application/vnd.ms-excel"); ------ But how do I do this in rails? Cheers Glenn -- Posted via http://www.ruby-forum.com/.

Hi, I am stuck with creating a conditional categorical variable in R If my dataframe data_2 has 3 variables A,B,C I want to create variable D which would be something like : data_2$D <- ifelse(data_2$A < data_2$B & promotion_ind =="N",1,0), this throws up an error "In Ops.factor(data_2$A,data_2$B) : < not meaningful for factors I have tried converting the

On Fri, Jan 8, 2016 at 5:46 PM, Geert Stappers via Syslinux <syslinux at zytor.com> wrote: > On Fri, Jan 08, 2016 at 03:40:37PM -0600, Matt Zagrabelny via Syslinux wrote: >> Greetings, >> >> Is this list (a|the best) place to make feature requests for tftp-hpa? > > Yes, it is. > from email header List-Id: For discussion of Syslinux and tftp-hpa

Hola buenas, a veces empleo desde R shells de unix, Existe alguna manera de utilizar estos shelss desde windows o el lenguaje awk. La idea es hacerlo siempre desde R, igual invoncando cygwin desde windows es posible. Pero no me queda claro Un abrazo y gracias por adelntado Javier #_____________________________________________________________________ # EJEMPLO, ¿Que habría que poner en #

Hi,? I have two big data set.? data _1 :? > dim(data_1) [1] 15820 5 > head(data_1) ? ?Chromosome ?????Start????????End????????Feature GroupA_3 1: ? ? ? ????????chr1 521369 ?750000 ????chr1-0001 ? ?????0.170 2: ? ? ? ????????chr1 750001 ?800000 ????chr1-0002 ? ????-0.086 3: ? ? ? ????????chr1 800001 ?850000 ????chr1-0003 ? ?????0.006 4: ? ? ? ????????chr1 850001 ?900000 ????chr1-0004 ?

Hi I download the R, but I dont know how to get the script (syntax) file and run it. I would be very pleased for any help. Regards. Yasin -- Yasin Al-tawarah Tel: (01782) 583652 E-mail: mad26 at keele.ac.uk

Hi,* *I would like to set the entries of an array that appear as "NA" to a certain integer, but did not find a way to do so. The related code is given below: A <- array(-1000 , dim=c(100) ); for(i in 1: 100 ){ A[i] =B[i,57] - B[i,5]; } A [ which( A == "NA") ] <- 900; The "NA"s still appear as the entries of the array A. Can you tell me what is

Hi everybody, I' ve been following this list for a while now. Is there a way to detect the individual and cumulative s/n ratio values for the incoming calls in Asterisk or any other Call Center solution?... -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://lists.digium.com/pipermail/asterisk-users/attachments/20111130/d0d53c1f/attachment.htm>

On Thu, 11 Oct 2018, Damien Miller wrote: > On Thu, 11 Oct 2018, Adam Eijdenberg wrote: > > > Thanks for looking into. I wasn't able to get the patch to apply > > cleanly to the portable source for whatever reason, so I manually made > > the changes and got a little further. I now get past the "no mutual > > signature algorithm" client message, and get

HI, I would like to extract data in a specific way.  For example, the rainfall data 0,0,1.5,0,0, 3,1,2.5,0,0,0,0, 2.3,0,0,0, 2.1,1.4,0,0,0, 3,2,1,0,0,0... data_1: 1.5, 2.3               ( a single nonzero data between zeros data) data_2: 3.1, 2.5, 2.1,1.4   ( two nonzero data between zeros data) data_3: 3,1,2.5, 3,2,1       ( three nonzero data between zeros data) Thank you so much for any

Al final resulto más fácil de lo esperado. Hay que instalar cywin y utilizar los comandos de la siguiente manera system('C:/cygwin/bin/wc -l var_risco_2012.csv') Esto en principio funciona El 8 de junio de 2015, 17:41, Carlos Ortega <cof en qualityexcellence.es> escribió: > Hola, > > Mira esto: > >

I am absolutely new to R and I am aware of only a few basic command lines. I was running a robust regression in R, using the following command line library (MASS) rfdmodel1 <- rlm (TotalEmployment_2004 ~ MISSISSIPPI + LOUISIANA + TotalEmployment_2000 + PCWhitePop_2004 + UnemploymentRate_2004 + PCUrbanPop2000 + PCPeopleWithACollegeDegree_2000 + PCPopulation.of.or.over.65.years.of.age_2004)

Greetings, Is this list (a|the best) place to make feature requests for tftp-hpa? If not, would you point me in the right direction, please? Thanks much! -m

Hi, I have been examining large data and need to do simple linear regression with the data which is grouped based on the values of a particular attribute. For instance, consider three columns : ID, x, y, and I need to regress x on y for each distinct value of ID. Specifically, for the set of data corresponding to each of the 4 values of ID (76,111,121,168) in the below data, I should invoke

I would like to calculate the mean of tree leader increment growth over 5 years (I1 through I5) where each tree is a row and each row has 5 columns. So far I have achieved this using rowMeans when all columns are numeric type and used in the calculation: Data1 <- data.frame(cbind(I1 = 3, I2 = c(0,3:1, 2:5,NA), I3 =c(1:4,NA,5:2),I4=2,I5=3)) Data1 Data1$mean_5 <- rowMeans(Data1, na.rm =T)

Hello everybody, I have usually solved this problem by repeating lines of codes instead of a loop, but it's such a waste of time, I thought I should really learn how to do it with loops: What I want to do: Say, I have several data files that differ only in a number, e.g. data points (or vector, or matrix...) Data_1, Data_2, Data_3,... and I want to manipulate them e.g. a simple sum of

Hello all, I am new to Rails. I don''t know whether it is possible are not. In my application, I need get data from one table , then arrange these data in table in textfield, then I need to edit data in all rows in single form. At the end I need to save these data back to databse. How can I do this Is this possible <%= tag("input" , {:type => '''',