similar to: Formatting the dates generated by the forecast function

Displaying 20 results from an estimated 1000 matches similar to: "Formatting the dates generated by the forecast function"

2012 Apr 26
1
Using the R predict function to forecast a model fit with auto.arima function
Hello R users, Hope everyone is doing great. I have a dataset that is in .csv format and consists of two columns: one named Period (which contains dates in the format yyyy_mm) and goes from 1995_10 to 2007_09 and the second column named pcumsdry which is a volumetric measure and has been formatted as numeric without any commas or decimals. I imported the dataset as pauldataset and made use of
2017 Dec 06
1
Odd dates generated in Forecasts
Thank you very much David. As a matter of fact, I solved it by doing the following: MyTimeSeriesObj <- ts(MyData, freq=365.25/7, start=decimal_date(mdy("01-04-2003"))) After doing that adjustment, my forecasts dates started from 2017 on. Cheers, Paul 2017-12-06 12:03 GMT-05:00 David Winsemius <dwinsemius at comcast.net>: > > > On Dec 6, 2017, at 5:07 AM, Paul
2023 Aug 20
1
Issues when trying to fit a nonlinear regression model
Basic algebra and exponentials/logs. I leave those details to you or another HelpeR. -- Bert On Sun, Aug 20, 2023 at 12:17?PM Paul Bernal <paulbernal07 at gmail.com> wrote: > Dear Bert, > > Thank you for your extremely valuable feedback. Now, I just want to > understand why the signs for those starting values, given the following: > > #Fiting intermediate model to get
2023 Aug 20
1
Issues when trying to fit a nonlinear regression model
Dear Bert, Thank you for your extremely valuable feedback. Now, I just want to understand why the signs for those starting values, given the following: > #Fiting intermediate model to get starting values > intermediatemod <- lm(log(y - .37) ~ x, data=mod14data2_random) > summary(intermediatemod) Call: lm(formula = log(y - 0.37) ~ x, data = mod14data2_random) Residuals: Min
2017 Jan 03
2
[R] Problems when trying to install and load package "rzmq"
Possibly so. However, the ZeroMQ libraries do exist for Windows, so it might be possible to get the package working there. However, CRAN probably won't have the libraries, so cannot produce a binary package, and it is also quite possible that the package author is not a Windows person. At the very least, you'll need some familiarity with the Windows toolchain and be prepared to apply a
2013 Mar 06
4
Issue when reading a table into R
Hello everyone, I was reading a table into R, and when trying to retrieve it the following message appeared: [ reached getOption("max.print") -- omitted 469376 rows ] Does this mean that R left out 469376 rows? Or R is taking those 469376 rows as well and the limitation is only for printing purposes? Thanks in advance for any help, Best regards, Paul [[alternative HTML version
2023 Aug 20
2
Issues when trying to fit a nonlinear regression model
Dear Bert, Thank you so much for your kind and valuable feedback. I tried finding the starting values using the approach you mentioned, then did the following to fit the nonlinear regression model: nlregmod2 <- nls(y ~ theta1 - theta2*exp(-theta3*x), start = list(theta1 = 0.37, theta2 = exp(-1.8), theta3 =
2023 Aug 20
1
Issues when trying to fit a nonlinear regression model
Oh, sorry; I changed signs in the model, fitting theta0 + theta1*exp(theta2*x) So for theta0 - theta1*exp(-theta2*x) use theta1= -.exp(-1.8) and theta2 = +.055 as starting values. -- Bert On Sun, Aug 20, 2023 at 11:50?AM Paul Bernal <paulbernal07 at gmail.com> wrote: > Dear Bert, > > Thank you so much for your kind and valuable feedback. I tried finding the > starting
2017 Nov 01
3
Adding Records to a Table in R
Dear R friends, I am currently working with time series data, and I have a table(as data frame) that has looks like this (TransitDate are in format = "%e-%B-%Y") : TransitDate Transits CargoTons 1985-04-01 100 2500 1985-05-01 135 4500 1985-06-01 120 1750 1985-07-01 100 3750 1985-08-01 200
2012 Aug 01
1
Odd Results when using R's auto.arima function
Good morning everyone, I have attached an Excel file that contains a macro from which I call and use R's auto.arima function to generate forecasts. The program runs perfectly and it gets me the results; however, those results are pretty unusual. I also tried using the auto.arima function directly in the R console and still get weird results. The results are shown in columns AB, AC and AD
2017 Dec 06
0
Odd dates generated in Forecasts
> On Dec 6, 2017, at 5:07 AM, Paul Bernal <paulbernal07 at gmail.com> wrote: > > Dear friends, > > I have a weekly time series which starts on Jan 4th, 2003 and ends on > december 31st, 2016. > > I set up my ts object as follows: > > MyTseries <- ts(mydataset, start=2003, end=2016, frequency=52) > > MyModel <- auto.arima(MyTseries, d=1, D=1)
2017 Sep 12
3
Unable to load packages RODBC and RODBCext in R
Dear all, Hope you are doing great. I am currently using R version 3.4.1 ("Single Candle") and was trying to install packages RODBC and RODBCext using the following steps: > install.packages("RODBCext") Installing package into ?C:/Users/PaulBernal/Documents/R/win-library/3.4? (as ?lib? is unspecified) also installing the dependency ?RODBC? trying URL '
2017 Nov 01
0
Adding Records to a Table in R
Hi Paul, #First I set up some sample data since I don't have a copy of your data dtOrig <- as.Date( c("1985-04-01","1985-07-01","1985-12-01","1986-04-01")) dfOrig <- data.frame( TransitDate=dtOrig, Transits=c(100,100,500,325), CargoTons=c(1000,1080,3785,4200) ) #Generate the complete set of dates as a data frame dfDates<- data.frame(
2013 Feb 21
2
Arimax with intervention dummy and multiple covariates
Hi I'm trying to measure the effect of a policy intervention (Box and Tiao, 1975). This query has to do with the coding of the model rather than with the particulars of my dataset, so I'm not providing the actual dataset (or a simulated one) in this case, apart from some general description. The time series are of length n=34 (annual observations between 1977 and 2010). The policy
2012 May 04
1
Problems Exporting R Output to an xls file need help
Hello R users, I want to export to an xls or .csv some predictions I produced with the auto.arima and forecast functions. A detail of all my work is presented below. I loaded a package called dataframes2xls and tried to use the function write.xls without any success. Can anybody help me figure this out? How could I get R to export the output to an xls file? Any help will be greatly
2017 Sep 12
0
Unable to load packages RODBC and RODBCext in R
I don't use Windows, but this looks like a Windows permissions issue, no? You could try moving them yourself manually or create another library directory that R can access to put them in. ... or wait and hope for advice from someone who uses Windows to give you a definitive answer. Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and
2017 Dec 06
2
Odd dates generated in Forecasts
Dear friends, I have a weekly time series which starts on Jan 4th, 2003 and ends on december 31st, 2016. I set up my ts object as follows: MyTseries <- ts(mydataset, start=2003, end=2016, frequency=52) MyModel <- auto.arima(MyTseries, d=1, D=1) MyModelForecast <- forecast (MyModel, h=12) Since my last observation was on december 31st, 2016 I expected my forecast date to start on
2017 Jun 19
3
How to Transform a Factor Variable into a Date
Dear all, Hope you are doing great. I have a .csv file that I read into R, the .csv file consistss of two fields (TransitDate and CargoTons). The TransitDate I formatted from Excel in the fashion mmm-yy (e.g.: Apr-2013). However R does not recognize the field TransitDate as a date field. Here is the code: library(lubridate) Dataset <- read.table("U:/NEWCargoData.csv",
2017 Sep 21
2
Keep on getting message errors when trying to install and load packages
Hi Paul, I recently ran into file path conflicts and found the following useful (looks like you already know the answer to 1.): 1. Use .libPaths() to find where packages are being stored. 2. To change this path: Control Panel > search ?View advanced system settings? > Environment Variables *button *> a. *Edit* current R_LIBS_USER to new file path b. *New*
2023 Aug 20
1
Issues when trying to fit a nonlinear regression model
I got starting values as follows: Noting that the minimum data value is .38, I fit the linear model log(y - .37) ~ x to get intercept = -1.8 and slope = -.055. So I used .37, exp(-1.8) and -.055 as the starting values for theta0, theta1, and theta2 in the nonlinear model. This converged without problems. Cheers, Bert On Sun, Aug 20, 2023 at 10:15?AM Paul Bernal <paulbernal07 at