Displaying 20 results from an estimated 3000 matches similar to: "Dates to numeric in for loop"
2003 Sep 02
1
Plotting dates
I'm trying to plot observations against observation dates and getting julian
dates along the x-axis:
library(date)
Week<-as.date(c("05/02/03","05/09/03","05/16/03","05/23/03","05/30/03","06/0
7/03","06/14/03"))
Leafminers<-c(0,2,5,10,4,6,5)
Diglyphus<-c(0,0,4,5,7,3,1)
LeafDig<-cbind(Week,Leafminers,Diglyphus)
2001 Aug 13
3
subset syntax
Can anyone tell me what's wrong with this command??
xx<-subset(x,LOCAL.NAME==c("Chifumbata","Chikota"),select=c(13,16,19,23,26,2
9,30,33:48))
Warning message:
longer object length
is not a multiple of shorter object length in: LOCAL.NAME ==
c("Chifumbata", "Chikota")
both of the following commands work fine
2002 Jan 08
6
Subsets without NA
Is there a way of removing all rows with missing values from a data frame?
I usually use
subset(x, var1!="NA")
and repeat for each variable. It would be nice to be able to do it in one
fell swoop. Also, surprisingly, it doesn't always work. Sometimes I'm left
with an empty set even though not all rows have missing values for the
variable.
Cheers,
mikkel
Mikkel Grum,
2002 Jan 08
3
colour coding and different point types in a plot
I'm trying to plot four different sorghum types on a plot using a different
colour/symbol combination for each sorghum type (TYPBOTA in the script
below). What am I doing wrong?:
plot(xx$LATITUDE,xx$SFD1,
points(xx$SFD1,xx$LATITUDE,
col=1:4[codes(xx$TYPBOTA)],pch=c(4,3,1,2)[codes(xx$TYPBOTA)])
grid()
I get the following error message
Error in 1:4[codes(xx$TYPBOTA)] : NA/NaN argument
2003 Jan 07
2
Extracting means for given strata from dissimilarity object
Is there a way of extracting mean distance or dissimilarity for a given
strata from a 'dist' or 'dissimilarity' object, e.g. extract mean distances
for each species in Anderson's iris data?
data(iris)
iris.dist<-dist(iris[,1:4])
then what?
Mikkel Grum, PhD
Genetic Diversity Scientist
International Plant Genetic Resources Institute (IPGRI)
Sub-Saharan Africa Group
***
2006 Jan 27
3
substituting an object not found
Is there any function in R like
is.not.found(x, y)
meaning if you can't find object x, then use object
y??
Mikkel Grum
2001 Aug 21
4
looking for a smarter way
I have two problems where I've come up with some code that will do the
analysis that I want, but it looks pretty clumsy. In the first case, I
calculate the variance on five different columns for each of 14 clusters and
get them into one matrix. I get the job done, but I would have thought that
it could be done in one or two lines, not six, and be generalized so that it
didn't matter how
2006 Jan 02
1
"7:9, 12:14" in dataframe to c(7:9, 12:14)
I want to do something like df[df$b %in% df2[i, 2], ]
where df$b is a numeric vector and df2[i, 2] is a
factor with
levels like "7:9, 12:14". For example:
a <- c(paste("A", 1:10, sep = ""), paste("B", 1:10,
sep = ""))
b <- 1:20
df <- as.data.frame(cbind(a, b))
df$b <- as.numeric(levels(df$b))[as.integer(df$b)]
f <-
2006 Mar 15
3
"\r" with RSQLite
What am I doing wrong, or is the \r that I'm getting
in the example below a bug?
> a <- (1:10)
> b <- (LETTERS[1:10])
> df <- as.data.frame(cbind(a, b))
>
> df
a b
1 1 A
2 2 B
3 3 C
4 4 D
5 5 E
6 6 F
7 7 G
8 8 H
9 9 I
10 10 J
> library(RSQLite)
> drv <- dbDriver("SQLite")
> con <- dbConnect(drv, dbname = "Test")
2006 Mar 15
3
"\r" with RSQLite
What am I doing wrong, or is the \r that I'm getting
in the example below a bug?
> a <- (1:10)
> b <- (LETTERS[1:10])
> df <- as.data.frame(cbind(a, b))
>
> df
a b
1 1 A
2 2 B
3 3 C
4 4 D
5 5 E
6 6 F
7 7 G
8 8 H
9 9 I
10 10 J
> library(RSQLite)
> drv <- dbDriver("SQLite")
> con <- dbConnect(drv, dbname = "Test")
2001 Aug 09
1
Mixed mode import problem
First question:
I have an Excel file with both character and numeric variables that I want
to import to a data.frame, so I've saved the data to a tab-delimited text
file.
read.table :
* Won't identify the mode of my character variables, as some of them
contain only numbers and none of them are surrounded by quotes,
* Won't allow me to specify the mode of my variables,
* Doesn't
2010 Dec 28
4
batch file output
I run a batch file with the following command in Windows XP:
C:\R\R-2.12.1\bin\Rterm.exe --no-save --no-restore <C:\users\me\file.R> C:\users\me\file.out 2>&1
Is there any way to get only the output of R in file.out, without getting all the code from file.R too?
Any help greatly appreciated,
Mikkel
2004 Dec 31
2
Supressing empty sections with Sweave
Dear useRs,
I'm writing regular survey reports using Sweave. Each
report has several sections along the lines of:
\section*{Disease X}
<<MapX,fig=TRUE,echo=FALSE>>=
image(vectorx,vectory,matrixz)
@
Notes with or without Sexpr{a}.
\vfill
\pagebreak
\section*{Disease Y}
<<MapY,fig=TRUE,echo=FALSE>>=
...etc.
Often one or more of the diseases is not observed (all
2007 Aug 07
2
backslash c
How do I get output with "\color{blue}", i.e. with
only one backslash???
> "\color{blue}"
[1] "color{blue}"
Warning messages:
1: '\c' is an unrecognized escape in a character
string
2: unrecognized escape removed from "\color{blue}"
> "\\color{blue}"
[1] "\\color{blue}"
>
Any help greatly appreciated.
Best regards,
2005 Jul 07
3
xmat[1, 2:3] <- NULL
I have a situation where I'm filling out a dataframe
from a database. Sometimes the database query doesn't
get anything, so I end up trying to place NULL in the
dataframe like below.
> temp <- NULL
> xmat <- as.data.frame(matrix(NA, 2, 3))
> xmat[1, 2:3] <- temp
Error in if (m < n * p && (n * p)%%m)
stop(gettextf("replacement has %d items, need %d",
2007 Dec 30
3
Date formats
Is the following expected behaviour for a date used in
an ifelse function?
> date <- Sys.Date()
> date
[1] "2007-12-30"
> ifelse(TRUE, date-1, date)
[1] 13876
> ifelse(FALSE, date-1, date)
[1] 13877
> ifelse(TRUE, as.character(date-1), date)
[1] "2007-12-29"
> if (TRUE) {date}
[1] "2007-12-30"
It would seem more natural to me if a date produced
2008 Oct 13
1
cut.Date problem when starting on first day of week (PR#13159)
Apparently any (?) call of the form
cut(date,"weeks")
where the date *begins the week*, gives the error
Error in 1:(1 + max(which(breaks < maxx))) :
result would be too long a vector
In addition: Warning message:
In max(which(breaks < maxx)) :
no non-missing arguments to max; returning -Inf
To my surprise, this was first reported as a problem in 2006 (!)
(version 2.3.1
2004 Sep 01
2
RODBC query on one line
Dear R-helpers,
When I use sqlQuery in the package RODBC, I cannot
break the line, but have to write the entire SQL Query
on the same line. Is this expected behaviour? It is
definitely workable, but makes the queries a slightly
difficult to read and edit.
I'm using R 1.9.1 and RODBC 1.0-4 on Windows Server
2003 and querying a Sybase database.
Best wishes,
Mikkel
2010 May 19
1
Pausing calculations for a fixed amount of time
Is there any way to pause R for a gvien time period, i.e. without the
need for user intervention? I've got a loop that I want to have work
as hard as it can as long as there is data coming in, but when there
is no new data, I would like it to pause before checking again.
Something like in the following construction:
Set up environment: load libraries, establish database connections, etc.
2005 Jul 08
2
removing factor level represented by less than x rows
In a number of different situations I'm trying to
remove factor levels that are represented by less than
a certain number of rows, e.g. if I had the dataset aa
below and wanted to remove the species that are
represented in less than 2 rows:
data(iris)
aa <- iris[1:101,]
In this case, since I can see that the species
virginica only has one row, I can write:
table(aa$Species)
setosa