similar to: ggplot2 error

Thanks, I think, I found the problem. It seems to related locale setting. If I start with 'LANG=C R' everything's good. -- Zeki ?atav zekicatav.com On Nov 8, 2017 1:56 PM, "John Kane" <jrkrideau at yahoo.ca> wrote: I get the same result as Eric with R version 3.4.2 (2017-09-28) Platform: x86_64-pc-linux-gnu (64-bit) Running under: Ubuntu 17.04 It looks like you

I get the same result as Eric? withR version 3.4.2 (2017-09-28) Platform: x86_64-pc-linux-gnu (64-bit) Running under: Ubuntu 17.04 It looks like you have "tidyverse" loaded so I tried it with just ggplot2 loaded and with tidyverse loaded.? On Wednesday, November 8, 2017, 4:16:14 AM EST, Eric Berger <ericjberger at gmail.com> wrote: I was not able to reproduce this

I was not able to reproduce this problem. I tried two environments 1. Ubuntu 14.04.5 LTS, R version 3.4.2 (same R version as yours) 2. Windows 10, same R version On Wed, Nov 8, 2017 at 9:50 AM, Zeki ?ATAV <zcatav at gmail.com> wrote: > Hello, > I've an error recently. > > ggplot(data = mtcars, aes(x= wt, y= mpg)) + geom_line() > Error: Found object is not a stat. >

Hello, I've an error recently. ggplot(data = mtcars, aes(x= wt, y= mpg)) + geom_line() Error: Found object is not a stat. > sessionInfo() R version 3.4.2 (2017-09-28) Platform: x86_64-pc-linux-gnu (64-bit) Running under: Ubuntu 16.04.3 LTS Matrix products: default BLAS: /usr/lib/openblas-base/libblas.so.3 LAPACK: /usr/lib/libopenblasp-r0.2.18.so locale: [1] LC_CTYPE=tr_TR.UTF-8

> lm2 <- function(...) lm(...) > lm2(mpg ~ wt, data=mtcars) Call: lm(formula = ..1, data = ..2) Coefficients: (Intercept) wt 37.285 -5.344 > lm2(mpg ~ wt, weights=cyl, data=mtcars) Error in eval(expr, envir, enclos) : ..2 used in an incorrect context, no ... to look in Can anyone explain why this is happening? (Obviously this is a manufactured example, but it

ggplot2 ------------------------------------------------------------ ggplot2 is a plotting system for R, based on the grammar of graphics, which tries to take the good parts of base and lattice graphics and avoid bad parts. It takes care of many of the fiddly details that make plotting a hassle (like drawing legends) as well as providing a powerful model of graphics that makes it easy to produce

ggplot2 ------------------------------------------------------------ ggplot2 is a plotting system for R, based on the grammar of graphics, which tries to take the good parts of base and lattice graphics and avoid bad parts. It takes care of many of the fiddly details that make plotting a hassle (like drawing legends) as well as providing a powerful model of graphics that makes it easy to produce

Hi everyone, This is about documentation for the model.frame() page. The get_all_vars() function (added in R 2.5.0) is a great addition, but the behavior of its '...' argument is different from that of model.frame() with which it is documented and this creates ambiguity. The current docs read: \item{\dots}{further arguments such as \code{data}, \code{na.action}, \code{subset}. Any

This syntax is already implemented in the {purrr} package, more or less -- you need to add a tilde before your function call for it to work exactly as written: purrr::map_dbl(split(mtcars, mtcars$cyl), ~ summary(lm(wt ~ mpg, .))$r.squared) is equivalent to sapply(split(mtcars, mtcars$cyl), function(d) summary(lm(mpg ~ wt, d))$r.squared) Seems like using this package is probably an easier

I am learning ggplot2, and need your help. When I try > p <- ggplot(mtcars, aes(x = wt, y=mpg)) + geom_point() > p + geom_abline(slope=5) (from http://had.co.nz/ggplot2/geom_abline.html) the slope of the abline does not change, but this works: > p + geom_abline(intercept=20) In order to have slope work, I have to use > p + geom_abline(aes(slope=5)) Is it a bug, or is there

Hello, the same parameter for colour and shape aesthetics gives 2 legends: library(ggplot2) p <- ggplot(mtcars, aes(x=wt, y=mpg)) p + geom_point(aes(colour=factor(cyl), shape=factor(cyl))) Can the 2 legends be consolidated to one with colours and shapes of the symbols matched between legend and plot ? Thank you Bernd Engelmann bernd.engelmann at amd.com phone: + 49-351-277-4545 fax: +

I am trying to plot a graph but the points on the graph should be different symbols and colors. It should represent what is in the legend. I tried using the points command but this does not work. Is there another command in R that would allow me to use different symbols and colors for the points? Thank you kindly. data(mtcars) plot(mtcars$wt,mtcars$mpg,xlab= "Weight(lbs/1000)",

I'm sure this exists elsewhere, but, as a trade-off, could you achieve what you want with a separate helper function F(expr) that constructs the function you want to pass to [lsv]apply()? Something that would allow you to write: sapply(split(mtcars, mtcars$cyl), F(summary(lm(mpg ~ wt,.))$r.squared)) Such an F() function would apply elsewhere too. /Henrik On Thu, Apr 16, 2020 at 9:30 AM

Hello again, It appears that get_all_vars() incorrectly handles model formulae that use a right-hand side (rhs) matrix. For example, consider these two substantively identical models: # model using named variables mpg <- mtcars$mpg wt <- mtcars$wt hp <- mtcars$hp m1 <- lm(mpg ~ wt + hp) # model using matrix y <- mtcars$mpg x <- cbind(mtcars$wt, mtcars$hp) m2 <- lm(y ~ x)

ggplot2 ------------------------------------------------------------ ggplot2 is a plotting system for R, based on the grammar of graphics, which tries to take the good parts of base and lattice graphics and avoid bad parts. It takes care of many of the fiddly details that make plotting a hassle (like drawing legends) as well as providing a powerful model of graphics that makes it easy to produce

ggplot2 ------------------------------------------------------------ ggplot2 is a plotting system for R, based on the grammar of graphics, which tries to take the good parts of base and lattice graphics and avoid bad parts. It takes care of many of the fiddly details that make plotting a hassle (like drawing legends) as well as providing a powerful model of graphics that makes it easy to produce

Serguei, > On 17/04/2020, at 2:24 AM, Sokol Serguei <sokol at insa-toulouse.fr> wrote: > > Hi, > > I would like to make a suggestion for a small syntactic modification of FUN argument in the family of functions [lsv]apply(). The idea is to allow one-liner expressions without typing "function(item) {...}" to surround them. The argument to the anonymous function is

Passing in a function passes not only an argument list but also an environment from which to get free variables. Since your function doesn't pay attention to the environment you get things like the following. > wsapply(list(1,2:3), paste(., ":", deparse(s))) [[1]] [1] "1 : paste(., \":\", deparse(s))" [[2]] [1] "2 : paste(., \":\",

You can get pretty close to that already using fn$ in the gsubfn package: > library(gsubfn) > fn$sapply(split(mtcars, mtcars$cyl), x ~ summary(lm(mpg ~ wt, x))$r.squared) 4 6 8 0.5086326 0.4645102 0.4229655 It is not specific to sapply but rather fn$ can preface most functions. If the only free variables are the arguments to the function then you can omit the left

Sergei, the main problem that I was pointing out is is that there is no way you can introduce the new syntax without breaking the old one. The expression is evaluated to obtain a function, so by definition using anything that results in a valid expression for your syntax will break. E.g., using sapply(x, (foo)) is completely valid so you can't just change the evaluation of the expression to