similar to: googlesheets gs_reshape_cellfeed()

I have data I'd like to plot using the formula interface to boxplot. I call boxplot like so: with(mydata, boxplot(count ~ geno * tissue)) I get a boxplot with x axis labels like "wt.kidney". I would like to change the '.' to a newline. Where is this separator configured? Thanks, -Ed

Just change the separator: data(Titanic) Titanic.df <- as.data.frame(Titanic) boxplot(Freq~Class*Sex, Titanic.df, cex.axis=.6, sep="\n") See attached .png. ---------------------------------------- David L Carlson Department of Anthropology Texas A&M University College Station, TX 77843-4352 -----Original Message----- From: R-help [mailto:r-help-bounces at r-project.org] On

I don't really understand. I mean, I understand the solution is print(ggplot(...)). But why is that required in a function and not at the console? Shouldn't I be able to rely on what I do at the console working in a script? Is this inconsistent behavior by design? On Thu, Nov 2, 2017 at 11:54 AM, David Winsemius <dwinsemius at comcast.net> wrote: > >> On Nov 2, 2017,

mybp <- boxplot(count ~ geno * tissue, data = mydata, plot = FALSE) mybp$names <- gsub("\\.", "\n", mybp$names) bxp(mybp) See ?boxplot for details. Best, Ista On Thu, Sep 28, 2017 at 12:40 PM, Ed Siefker <ebs15242 at gmail.com> wrote: > I have data I'd like to plot using the formula interface to boxplot. > I call boxplot like so: > > with(mydata,

Wait. Now I'm really confused. > > head(samples) quant_samples age sapply(yo, toupper) E11.5 F20het BA40 E11.5 F20het BA40 E11.5 F20HET E11.5 F20het BA45 E11.5 F20het BA45 E11.5 F20HET E11.5 F20het BB84 E11.5 F20het BB84 E11.5 F20HET E11.5 F9.20DKO KTr3 E11.5 F9.20DKO KTr3 E11.5 F9.20DKO E11.5

Why doesn't this work? > samples$geno <- as.data.frame(sapply(yo, toupper), col.names="geno") > samples quant_samples age sapply(yo, toupper) E11.5 F20het BA40 E11.5 F20het BA40 E11.5 F20HET E11.5 F20het BA45 E11.5 F20het BA45 E11.5 F20HET

I have dose response data analyzed with the package 'drc'. 'summary(mymodel)' prints my kinetic parameters. I want that text in an ASCII text file. I want to get exactly what I would get if I copied and pasted from the terminal window. I've read the documentation on data export to text files here:

I have a list of suffixes I want to turn into file names with extensions. suff<- c("C1", "C2", "C3") paste("filename_", suff[[1]], ".ext", sep="") [1] "filename_C1.ext" How do I use lapply() on that call to paste()? What's the right way to do this: filenames <- lapply(suff, paste, ...) ? Can I have lapply()

Hi, I am running Debian Sid. I am having trouble with the R packages. Executing 'help()' or 'demo()' launches 'most' with no text. 'help.start()' works properly. When I try to install a package, I get the following problem: ********************************************************************* > install.packages("ctv") Installing package(s) into

?sink On May 18, 2018 9:47:25 AM PDT, Ed Siefker <ebs15242 at gmail.com> wrote: >I have dose response data analyzed with the package 'drc'. >'summary(mymodel)' prints my kinetic parameters. I want >that text in an ASCII text file. I want to get exactly what I >would get if I copied and pasted from the terminal window. > >I've read the documentation on

> On Nov 2, 2017, at 9:27 AM, Ed Siefker <ebs15242 at gmail.com> wrote: > > I have a function: > > myplot <- function (X) { > d <- plotCounts(dds2, gene=X, intgroup="condition", returnData=TRUE) > png(paste("img/", X, ".png", sep="")) > ggplot(d, aes(x=condition, y=count, color=condition)) + >

Is there a way I can get the names of the arguments passed to a function from within a function?

I have a list of file names, and a list of data frames contained in those files. mynames <- list.files() mydata <- lapply(mynames, read.delim) Every file contains two columns. > colnames(mydata[[1]]) [1] "Name" "NumReads" > colnames(mydata[[2]]) [1] "Name" "NumReads" I can set the colnames easily enough with a for loop. for (i in

I'm doing some string manipulation on a vector of file names, and noticed something curious. When I strsplit the vector, I get a list of character vectors. The list is numbered, as lists are. When I cast that list as a data frame with 'as.data.frame()', the resulting columns have names derived from the original filenames. Example code is below. My question is, where are these names

I have a function: myplot <- function (X) { d <- plotCounts(dds2, gene=X, intgroup="condition", returnData=TRUE) png(paste("img/", X, ".png", sep="")) ggplot(d, aes(x=condition, y=count, color=condition)) + geom_point(position=position_jitter(w=0.1,h=0)) + scale_y_log10(breaks=c(25,100,400)) + ggtitle(X) +

I'm trying to read in a tab separated table with read.delim(). I don't particularly care what the row names are. My data file looks like this: start stop Symbol Insert sequence Clone End Pair FISH 203048 67173930 ABC8-43024000D23 TI:993812543 TI:993834585 255176 87869359 ABC8-43034700N15 TI:995224581 TI:995237913 1022033 1060472

I have a data frame full of integer values. I need a matrix full of numeric values. ?data.matrix reads: Return the matrix obtained by converting all the variables in a data frame to numeric mode and then binding them together as the columns of a matrix. This does not work. test.df <- data.frame(a=as.integer(c(1,2,3)), b=as.integer(c(4,5,6))) > class(test.df[[1,1]]) [1]

Interesting problem. I would discretize the x-values and interleave them. Lines from one dataset still overlap, so you see high- density and low-density regions, but lines from the other dataset are drawn into the interval. Like so: interleave <- function(x, MIN, MAX, N, nChannel = 2, channel) { isp <- seq(MIN, MAX, length.out = N + 1) # interleave support points offset <-

I would like to subset by dataframe by matching all rows that have any value from a list of values. I can get it to work if I have exactly one value, I'm not sure how to do it with a list of values though. This works and gives me exactly one line: my.df[ which( mydf$IDX==17)), ] I would like to do something like this: my.df[ which( mydf$IDX==c(17, 42), ] Obviously that won't work, but

I have two chromatograms I want plotted on the same axes. I would like the plots to be transparent, so the first chart is not obscured. I have tried adjustcolor(..., alpha.f=0.3), the problem is that my chromatogram is so dense with datapoints that they overlap and the entire graph just ends up a solid color. The second histogram still obscures the first. Consider this example: col1 <-