similar to: Problem of a function I wrote

Hello everyone, It seems that I was not successfully attached the code. Here is the code. I appreciate any help! Best, Yen ?? b88207001 at ntu.edu.tw: > Hello everyone, > > I have been working on a code which simply repeatedly appends a > number into a vector and write a file. However, it could not be > properly implemented when I use it. It works when I run it line by

Hello everyone, I know where is wrong. I forget to specify the parameters in my function. Thank you for anyone who was trying to help me! Best, Yen ?? b88207001 at ntu.edu.tw: > Hello everyone, > > It seems that I was not successfully attached the code. Here is the > code. I appreciate any help! > > Best, > Yen > > ?? b88207001 at ntu.edu.tw: > >> Hello

Hello dear uesRs, I am working on modeling both level one and level two heteroscedasticity in HLM. In my model, both error variance and variance of random intercept / random slope are affected by some level two variables. I found that nlme is able to model heteroscedasticity. I learned how to use it for level one heteroscedasticity but don't know how to use it to model the level

Hello, everyone, There's a problem about zero in R and I really need your help. I have a vector shown as x=c(0.1819711,0.4811463,0.1935151,0.1433675), The sum of this vector is shown as 1 in R, but when I type 1-sum(x), the value is not zero, but -2.220446e-16. I can accept that this value is quite small and could be seen as zero, but there would be a problem when it's not really

I would like to estimate the sigma matrix of multinormal distribution through ML. But I don't know how to optimize the parameter sigma. Could any one help me? Thank you so much~ Yen Lee

If you don't get a response it is because you did not read the Posting Guide which indicates that the R-sig-ME mailing list is where this question would have been on-topic. -- Sent from my phone. Please excuse my brevity. On August 16, 2017 6:17:03 AM PDT, b88207001 at ntu.edu.tw wrote: >Hello dear uesRs, > >I am working on modeling both level one and level two

A better place for this post would be on R's mixed models list: r-sig-mixed-models . Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Wed, Aug 16, 2017 at 6:17 AM, <b88207001 at ntu.edu.tw> wrote: > Hello dear

I'm new to post in R-help and my native language is not English. I apologize if my sentence is not fluent to read. I am doing a simulation study and I need to execute SAS and read a SAS code in R. I try the following code but it doesn't work. system('"c:\\program files\\SAS\\SAS 9.1\\sas.exe" "c:\\syntax.sas"') can anyone give me some help with this?

Dear all, I've written a function and repeated it for 5000 times with loops with different value, and the messages returned are the output I set and 15 warnings. I would like to trace the warnings by stopping the loop when warning came out. Does anyone know how to make it? Thanks a lot for your help. Yen [[alternative HTML version deleted]]

x["V2"] is more efficient than using drop=FALSE, and perfectly normal syntax (data frames are lists of columns). I would ignore the naysayers, or put a comment in if you want to accelerate their uptake. As I understand it, one of the main reasons tibbles exist is because of drop=TRUE. List-slice (single-dimension) indexing works equally well with both standard and tibble types of data

You could declare a matrix much larger than you intend to use. This works with a few megabytes of data. It is not very efficient, so scaling up may become a problem. m22 <- matrix(NA, 1:600000, ncol=6) It does not work to add a new column to the matrix, as in you get an error if you try m22[ , 7] but convert to data frame and add a column m23 <- data.frame(m22) m23$x7 <- 12 The only

I need to read csv files repeatedly, named data1.csv, data2.csv,? data24.csv, 24 altogether. That is, data<-read.csv(?data1.csv?) ? data<-read.csv(?data24.csv?) ? Is there a way to do this in a loop? Thank you. Steven from iPhone [[alternative HTML version deleted]]

"Or use <<- assignment I think. (I usually return, but return can only return one object and I think you want two or more" You can return any number of objects by putting them in a list and returning the list. Use of "<<-" is rarely a good idea in R. -- Bert On Fri, Aug 9, 2024 at 1:53?AM CALUM POLWART <polc1410 at gmail.com> wrote: > > OK. The fact

You could also do dim(x) <- c(length(x), 1) On Sat, Aug 5, 2023, 20:12 Steven Yen <styen at ntu.edu.tw> wrote: > I wish to stack columns of a matrix into one column. The following > matrix command does it. Any other ways? Thanks. > > > x<-matrix(1:20,5,4) > > x > [,1] [,2] [,3] [,4] > [1,] 1 6 11 16 > [2,] 2 7 12 17 > [3,]

Thanks to all. Very helpful. Steven from iPhone > On Jan 14, 2023, at 3:08 PM, Andrew Simmons <akwsimmo at gmail.com> wrote: > > ?You'll want to use grep() or grepl(). By default, grep() uses extended > regular expressions to find matches, but you can also use perl regular > expressions and globbing (after converting to a regular expression). > For example: >

Thanks. Will try it. Have not tried it but I think the following may work: out$results<-NULL out$results$ei<-ap out$results$vi<-vap All I need is printing by returning out (unless I turn it off). And, retrieve ap and vap as needed as shown above. Guess I need to read more about invisible. On 8/11/2024 10:09 PM, Rui Barradas wrote: > ?s 09:51 de 11/08/2024, Steven Yen escreveu:

x <- numeric(0) for (...) { x[length(x)+1] <- ... } works. You can build a matrix by building a vector one element at a time this way, and then reshaping it at the end. That only works if you don't need it to be a matrix at all times. Another approach is to build a list of rows. It's not a matrix, but a list of rows can be a *ragged* matrix with rows of varying length. On Wed,

Eric, I am not sure your solution is particularly economical albeit it works for arbitrary arrays of any dimension, presumably. But it seems to involve converting a matrix to a tensor just to undo it back to a vector. Other solutions offered here, simply manipulate the dim attribute of the data structure. Of course, the OP may have uses in mind which the package might make easier. We often get

OK. The fact it's in a function is making things clearer. Are you trying to update the values of an object from within the function, and have them available outside the function. I don't speak functional programming articulately enough but basically v <- 1 funA <- function() { v <- v+1 } funA() cat (v) # 1 You either return the v from the function so funB <- function() {

I have trouble documenting an R package. In my .Rd file (sixth line below), I have uhat<-m%*%y but when the package is built (successfully), the matrix multiplication part does not show up in the documentation. The line become (missing %*% y) uhat<-m === \examples{ x<-c(1,2,3,4,5) y<-c(1,1,2,2,4) x<-cbind(1,x) m<-mmat(x) uhat<-m%*%y dstat(uhat) } ?-- styen at ntu.edu.tw