similar to: na.rm = T treatment by ggplot2's geom_bar

Displaying 20 results from an estimated 20000 matches similar to: "na.rm = T treatment by ggplot2's geom_bar"

2017 Jul 27
0
na.rm = T treatment by ggplot2's geom_bar
To clarify: my question is not about "who could I exclude NAs from being counted" - I know how to do that. My question is: Why na.rm = T is not working for geom_bar in this case? On Thu, Jul 27, 2017 at 8:24 AM, Dimitri Liakhovitski < dimitri.liakhovitski at gmail.com> wrote: > Hello! > > I am trying to understand how ggplot2's geom_bar treats NAs. > The help file
2017 Jul 27
2
na.rm = T treatment by ggplot2's geom_bar
Just a thought: Did you try na.rm = TRUE in case you have an object named "T" in scope? -- Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Thu, Jul 27, 2017 at 7:49 AM, Dimitri Liakhovitski <dimitri.liakhovitski at
2017 Jul 27
1
na.rm = T treatment by ggplot2's geom_bar
I suspect this is by design. Questions about "why" should probably cc the contributed package maintainer(s). -- Sent from my phone. Please excuse my brevity. On July 27, 2017 7:49:47 AM PDT, Dimitri Liakhovitski <dimitri.liakhovitski at gmail.com> wrote: >To clarify: my question is not about "who could I exclude NAs from >being >counted" - I know how to do
2017 Jul 27
2
na.rm = T treatment by ggplot2's geom_bar
I think you should be more suspicious of yourself, Dimitri. A letter T variable can easily arise in the problem domain when you are not thinking of logical values at all, at which point your cavalier use of T as a synonym for TRUE can suddenly become a bug. -- Sent from my phone. Please excuse my brevity. On July 27, 2017 8:18:03 AM PDT, Dimitri Liakhovitski <dimitri.liakhovitski at
2017 Jul 27
0
na.rm = T treatment by ggplot2's geom_bar
Thank you, Bert! I do NOT have an object named "T" in scope (I checked - and besides, it would never occur to me to use this name). TRUE or T results in the same unexpected behavior: ggplot(data = md, mapping = aes(x = a)) + geom_bar(na.rm = TRUE) On Thu, Jul 27, 2017 at 10:57 AM, Bert Gunter <bgunter.4567 at gmail.com> wrote: > Just a thought: > > Did you try
2017 Jul 27
0
na.rm = T treatment by ggplot2's geom_bar
?hanks for the advice, Jeff. Will keep it in mind. But I am anal - I shy away from using letters and words that "look familiar" to me in R (such as mean, sd, T, etc.) But still, it's a good advice. On Thu, Jul 27, 2017 at 11:53 AM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote: > I think you should be more suspicious of yourself, Dimitri. A letter T > variable can
2013 Oct 30
1
ggplot2 - how to get rid of bar boarder lines
Hello! I am using ggplot2: ggplot(myplotdata, aes(x=att_levels, y=WTP)) + geom_bar(stat="identity",fill="dark orange",colour="black", alpha = 1,position = "identity") + geom_text(aes(label=WTP),colour="black",size=4,hjust=1.1,position='dodge') + coord_flip() + xlab("") +
2013 Oct 30
1
ggplot2 question: keeping the order as in the input data
Hello! I am using ggplot2 (see the code below) to plot the data in 'myplotdata'. The first column of 'myplotdata' is called "att.levels" and contains strings; the second column is called "WTP" and contains numeric values. Notice - I use 'coord.flip()' The command aes(x=att_levels, y=WTP), if I understand correctly, sorts things alphabetically based on
2017 Jun 27
4
ggplot2 geom_bar arrangement
Hi, I was trying to draw a geom_bar plot. However, by default, the bars are arranged according to the label, which I don't want. I want the bars to appear exactly as they appear in the data frame. For example in the code: Lab=c(letters[4:6],letters[1:3]) valuex = c(3.1,2.3,0.4,-0.4,-1.2,-4.4) df <- data.frame(Lab,valuex) px <- ggplot(df,aes(Lab,valuex,label=Lab)) +
2017 Jun 27
0
ggplot2 geom_bar arrangement
You just have to change the levels of the factor ... library(ggplot2) Lab = c(letters[4:6], letters[1:3]) valuex = c(3.1,2.3,0.4,-0.4,-1.2,-4.4) df <- data.frame(Lab,valuex) # set the factor levels to the same order as observed in the data frame df$Lab <- factor(df$Lab, levels=unique(df$Lab)) px <- ggplot(df,aes(Lab,valuex,label=Lab)) + geom_text(aes(y=0)) + geom_bar(stat =
2012 Aug 10
1
ggplot2 geom_bar produces white slashes in legend keys
When I am using geom_bar I get these white slashes through the legend keys. I cannot figure out how to remove them. ggplot(diamonds, aes(clarity, fill=cut)) + geom_bar() I have tried using opts(legend.key = theme_blank()) but with no luck. Any suggestions would be much appreciated. I am using R vers. 2.15.0 and ggplot 0.9.1, win xp Best wishes Jonas Hal
2011 Dec 04
1
Polishing my geom_bar for publication
Dear list, I am new with ggplot2 and I have spend quiet some time putting together the following code to create the attached plot. However there's still a few things that I'm having trouble with! I would be grateful if someone can tell me how to fix (1) the colour of my bars into grey scales (2) removing the y-axis (species name) on the right figure to avoid duplication, and (3) fix the
2012 Apr 23
1
ggplot2 - geom_bar
Hello, I've some problem with the ggplot2. Here's a small example: --8<-- library(ggplot2) molten <- data.frame(date=c('01','01','01','01', '02','02','02','02'), channel=c('red','red','blue','blue',
2013 Apr 30
1
Stacked geom_bar with aggregated SE -ggplot2
Hi there,? I've been battling with an extension of this in my own data: getting appropriate error bars once data is stacked in a bar graph.? (original question: http://r.789695.n4.nabble.com/ggplot2-se-variable-in-geom-errorbar-s-limits- td3311176.html). It wouldn't let me reply to that thread. A modification of the earlier answer:? data(diamonds)? ?diamonds_df <- ddply(diamonds,
2011 Nov 16
1
geom_bar with missing data in package ggplot
Dear all, I was hoping someone could help with a ggplot question. I would like to generate a faceted bar chart, but missing data are causing problems. g<-structure(list(Date = structure(c(11322, 11687, 12052, 11322, 11687, 12052, 11322, 11687, 12052, 11322, 11687, 12052), class = "Date"), variable = c("Govt Revenues to GDP", "Govt Revenues to GDP",
2010 Mar 12
1
simple plot in ggplot2, wrong error bars
I was wondering if anyone could help me with this, simple problem. I am essentially following the example on Hadley's webpage (http://had.co.nz/ggplot2/geom_errorbar.html), but it still doesn't make any sense to me. df <- data.frame(trt = factor(c("intact", "intact", "removed", "removed")), coon = c(0.093, 0.06, 0.057, 0.09), group =
2012 Feb 01
1
ggplot2(0.9.0): could not find function "=="
Hi, I have a question related to the newest version of ggplot2 (0.9.0). I just updated this morning and from CRAN it looks like the Mac version is the only one at 0.9.0 as of right now. http://cran.r-project.org/web/packages/ggplot2/index.html Anyway, I was in the midst of a project where I was trying to replicate "Back-to-back Bar Charts" in this blog post.
2010 Oct 06
2
ggplot2 Pareto plot (Barplot in decreasing frequency)
Hi all I have a large dataframe with (among others) a categorical variable of 52 levels and would like to create a barplot with the bars ordered in decreasing frequency of the levels. I belive it is referred to as a pareto plot. Consider a subset where I keep only the categorical variable in question. # Example: v1 = c("aa", "cc", "bb", "bb",
2012 Dec 21
2
ggplot2: setting martin
Is it possible to set the margin in ggplot2 to a fixed size? I create many plots, and I want them to look the same. Especially I want them to have the same left margin. But P<-ggplot()+geom_bar(aes(c("short label1","short label2"),runif(2)))+coord_flip() P<-creates a plot with another margin as ggplot()+geom_bar(aes(c("very very very very long
2016 Apr 12
2
ggplot2
Dear R Community, Below is a problem with a simple ggplot2 graph. The code returns the error message below. Error: stat_count() must not be used with a y aesthetic. My code is below and the data is attached as a ?text? file. # Graph of the probabilities library(digest) library(DT) datatable(probability) str(probability) probability$Fertilizer <- as.factor(probability$Fertilizer)