similar to: A problem with order() function in R

Dears, I saw in the R-project site some R-books. However, I'm new in this community and I didn't figure out what are the best books. Can you suggest me some "reference" books? My intentions with R is concerned to Artificial Intelligence simulations, Classification and general Statistics (e.g., regression, multivariate regression, etc). Thanks for any help, Anderson

I am working on a project that requires me to do very large factorial evaluations. On R the built in factorial function and the one I created both are not able to do factorials over 170. The first gives an error and mine return Inf. Is there a way to have R do these larger calculations (the calculator in accessories can do 10000 factorial and Maple can do even larger) -- View this message in

Dear All, Is there any simple way to way to produce "rank", for a given list, but in a descending order? E.G: x = list(a=c(1,5,2,4)); rank(x$a); produces 1,4,2,3 However I am looking for a way to generate (4,1,3,2). It would be particularly nice if the proposed solution has all the niceties of rank function (like NA handling and ties.method functionality) TIA Manoj

I don't know the difference between rank and order.For example: > x=c(10,30,30,20,10,20) > x[rank(x,ties.method="first")] [1] 10 10 20 30 30 20 > x[order(x)] [1] 10 10 20 20 30 30 the result is quite different, x[rank(x,ties.method="first")] [1] 10 10 20 30 30 20 It is not sorted,why? -- View this message in context:

Hi I want to use order() to get the order of a vector. But I would need a different behavior when ties occur: similar to the parameter ties.method = "random" in the rank() function, I would need to randomise the ties. Is this possible? Example: x <- rep(1:10, 2) order(x) [1] 1 11 2 12 3 13 4 14 5 15 6 16 7 17 8 18 9 19 10 20 order(x) [1] 1 11 2 12 3 13 4 14 5 15

I"ve got a data frame with a selection of columns I want to compute a rank-order correlation matrix from without disturbing the original data frame. foo[,c("a","b","d","f","g")] What I wanted to do, intuitively, was: > cor(rank(foo[,c("a","b","d","f","g")])) but rank in that context

Dear all, I would like to get the order of the values in a vector. I have tried rank(), order() and searched the archive, though without success. Here is an example of a try x= c(20,30,50,40,60,10) cbind(sort.list(x),x) x [1,] 6 20 [2,] 1 30 [3,] 2 50 [4,] 4 40 [5,] 3 60 [6,] 5 10 but I was hoping to get this: x [1,] 2 20 [2,] 3 30 [3,] 5 50 [4,] 4 40 [5,] 6 60 [6,] 1 10 I'm

Is it possible to override has_many''s :order attribute at run-time? e.g. something like: <% for category in @site.categories(:order=>''name'') %> ... <% for category in @site.categories(:order=>''rank'') %> ... thanks csn -- Posted via http://www.ruby-forum.com/.

Hi All, I want to give ranks to elements in a column so I used: total_list$field1.rank <- rank(total_list$field1,ties.method="min") But this gives me the rank in increasing order. How do I get the ranks in decreasing order? I know decreasing = FALSE is not a legal argument here. Thanks. Jiong The email message (and any attachments) is for the sole use of the intended recipient(s)

Hi, This looks OK: > x <- c("_1_", "1_9", "2_9") > rank(x) [1] 1 2 3 But this does not: > xa <- paste(x, "a", sep="") > xa [1] "_1_a" "1_9a" "2_9a" > rank(xa) [1] 2 1 3 Cheers, H. > sessionInfo() R version 2.14.0 (2011-10-31) Platform: x86_64-unknown-linux-gnu (64-bit) locale: [1]

Hi, Is there any simple solution to get ranks in descending order? Example, a <- c(10, 98, 98, 98, 99, 100) r <- rank(a, ties.method="average") produces 1 3 3 3 5 6 I would want this instead: 6 5 3 3 3 1 Note that reversing r doesn't work but in small examples. Thanks, -Jose -- jquesada at andrew.cmu.edu Research associate http://lsa.colorado.edu/~quesadaj Dept. of

Dear all, I have recently experienced something with the function order I cannot explain: The help(order) (which I admit having overlooked before) rises even more my confusion... The following lines made me think order() was returning the 'order' each value in a vector would take when sorted. > a <- c(4.1, 3.2, 6.1) > order(a) [1] 2 1 3 Doing > plot(a,

Dear R-helpers, I would like to do a Spearman rank order test, and used the cor() function with the method "spearman". It gives me a number (correlation coefficient?) , but how can I get the p-value? Thank you for the help in advance! Regards, Anne-Katrin -- [[alternative HTML version deleted]]

I'm doing a study where people place a deck of cards in a certain order. It's sufficient to assume that their colors & each has a number (it's actually about attributes of hobbies). I'd like to look for patterns in how they've arranged the deck. For each subject I have a list like 3,5,2,4,1, indicating that (s)he chose 3 first, then 5, then 2. . . . I think what I first

Dear all, I have encountered some strange things when creating lm objects in R: model depends on the order of the terms specified in a formula. Let us consider the following simple example: > dat <- expand.grid(A = factor(c("a1", "a2")), + B = factor(paste("b", 1:4, sep="")), + rep = factor(1:2)) >

I thought I've understood the 'order' function, using simple examples like: order(c(5,4,-2)) [1] 3 2 1 However, I arrived to the following example: order(c(2465, 2255, 2085, 1545, 1335, 1210, 920, 210, 210, 505, 1045)) [1] 8 9 10 7 11 6 5 4 3 2 1 and I was completely perplexed! Shouldn't the output vector be 11 10 9 8 7 6 4 1 2 3 5 ? Do I have a damaged

Hi, In the order() help file, there is an example like: a <- c(4, 3, 2, NA, 1) b <- c(4, NA, 2, 7, 1) z <- cbind(a, b) (o <- order(a, b)); z[o, ] How can I do something like "order a in ascending order, b in descending order"? And say I have a third vector c, and I'd like to add this to the previous condition "a ascending, b descending, c

I have found that order() fails in a rather arcane circumstance, as in this example: > foo <- I( c('x','\265g') ) > order(foo) Error in if (xi > xj) 1L else -1L : missing value where TRUE/FALSE needed > foo <-c('x','\265g') > order(foo) [1] 1 2 > sessionInfo() R version 3.1.1 (2014-07-10) Platform: x86_64-apple-darwin13.1.0 (64-bit)

Hi all, If presented with a singular design matrix, lm drops columns to make the design matrix non-singular. What algorithm is used to select which (and how many) column(s) to drop? Particularly, given a factor, how does lm choose levels of the factor to discard? Thanks for the help. Best, Anirban [[alternative HTML version deleted]]

I am using the order function and the result seems to be incorrect: > a<-c(20,30,15,40) > order(a) [1] 3 1 2 4 Any suggestions? Thanks, Laura -- View this message in context: http://www.nabble.com/Incorrect-order-tp20224993p20224993.html Sent from the R help mailing list archive at Nabble.com.