similar to: dplyr help

Hi something like dcast(temp2, minuty~pokus) ? > dput(temp2) structure(list(pokus = structure(c(1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 3L, 3L, 3L, 3L, 4L, 4L, 4L, 5L, 5L, 6L, 6L, 7L, 7L, 8L, 8L ), .Label = c("T42", "T43", "T44", "T45", "T46", "T47", "T48", "T49"), class = "factor"), minuty = structure(c(2L,

Thank you very much for the support. I have just used the reshape library and my problem was solved. Kind regards, Peter -----Original Message----- From: Jeff Newmiller [mailto:jdnewmil at dcn.davis.ca.us] Sent: 10 July 2017 03:52 PM To: r-help at r-project.org; Mangalani Peter Makananisa; r-help at r-project.org Cc: Vito Ricci (vito_ricci at yahoo.com) Subject: Re: [R] dplyr help I am

A better thanks would be to post the solution that met your needs... particularly since in spite of our efforts it appears we may not have understood your problem. A small sample data set generated with dput along with your code would be helpful in making sure others learn along with you. -- Sent from my phone. Please excuse my brevity. On July 11, 2017 12:56:45 AM PDT, Mangalani Peter

I am pretty sure that this is not a question about dplyr... it is a question about tidyr. Look at the help file ?tidyr::spread. If I understand your question (I may not, because you gave no example of input/output data), the answer is no, the column names come from the column named by the key parameter and the values that fill those columns come from the column named by the value parameter.

Dear all, I recently read the book " R data preperation and manipulation using sqldf package" by Djoni Darmawikarta However, I have a problem with manipulation of dates using this package, I do not get the expected results. Do I need to install some packages to be able to subset the data by dates in sqldf? I am not getting Djoni Darmawikarta email address. Please see the practice

See FAQ #4 on the sqldf github home page. On Fri, Aug 11, 2017 at 9:21 AM, Mangalani Peter Makananisa <pmakananisa at sars.gov.za> wrote: > Dear all, > > I recently read the book " R data preperation and manipulation using sqldf package" by Djoni Darmawikarta > However, I have a problem with manipulation of dates using this package, I do not get the expected results.

Hi all, I am trying to create a new variable called Fiscal Year (FY) using case expression in sqldf and I am getting a null FY , see the code below . Please advise me as to how I can do this mutation. library(zoo) library(lubridate) library(stringr) library(RH2) library(sqldf) cr$ReportDate = as.Date(cr$ReportDate, format ='%Y-%m-%d') > cr2 = sqldf(" select

Dear R Gurus, I am currently working on the two dataset ( A and B), they both have the same fields: ID , REGION, OFFICE, CSTART, CEND, NCYCLE, STATUS and CB. I want to merge the two data set by ID. The problem I have is that the in data A, the ID's are unique. However in the data set B, the ID's are not unique, thus some repeat themselves. How do I the merge or retrieve the

Dear R-Gurus, I am trying to read in data with 24,349,113 rows to R-3.3.3 (64 bit) and have used the library "data.table" and It managed to read 23,347,070 rows and the remainder was 2,043 rows only. Could you please advise me as to which library/R-commands is suitable to read the full data in to R? Kind regards, Mangalani Peter Makananisa (5786) South African Revenue Service

Your data frame fam contains factors. Turn it into character strings using fam$Family = as.character(fam$Family) and try again. It may be helpful if you read up on R's factors, see ?factor. HTH, Peter On Tue, Nov 21, 2017 at 2:14 PM, Glen Forister <gforister at gmail.com> wrote: > This is a simple problem, but a mystery to me. > I'm trying to grab $Family

Well, ?factor does not say anything about this behaviour (assigning numeric code instead of level of factor). And actually if you do assignment for whole vector the result is different (vector in data frame is changed to factor). > temp2$fff[1]<-vec[1] > head(temp2,2) pokus minuty fff 1 T42 240 3 2 T42 300 <NA> > temp2$fff<-vec > head(temp2,2) pokus

This is a simple problem, but a mystery to me. I'm trying to grab $Family "Scelionidae" from one dataframe and put it into another dataframe occupied with NA in $Family. The result is a "158" ends up there instead of Scelionidae. Simply put fam$Family[1] <- least$Family[1] If I have made a mistake here, can somebody point it out. I've included the simple

> On Sep 11, 2017, at 1:05 AM, Mangalani Peter Makananisa <pmakananisa at sars.gov.za> wrote: > > Hi all, > > I am trying to create a new variable called Fiscal Year (FY) using case expression in sqldf and I am getting a null FY , see the code below . > > Please advise me as to how I can do this mutation. > > library(zoo) > library(lubridate) >

Dear all, Please help me with the R code which compute SCHEFFE TEST Thanking you in advance Kind regards Mangalani Peter Makananisa Statistical Analyst South African Revenue Service (SARS) Segmentation and Research : Data Modelling Tel: +2712 422 7357 Cell: +2782 456 4669 Fax:+2712 422 6579 Please Note: This email and its contents are subject to our email legal notice

2018-03-3 in your code should be 2018-03-31. The line then'201415' needs to be fixed. When posting please provide minimal self-contained examples. There was no input provided and library statements not relevant to the posted code were included. Fixing the invalid date and bad line, getting rid of those library statements that are unnecessary and providing some test input, it works

Dear all, I'm using garchFit from fSeries package and I am not getting the desired results (error message : could not find function "garchFit" ). Would you please advise as to how I can build an ARIMA(p, d, q) - GARCH(p,q) model using R see the attached data and R-output. Thanking you in advance Kind regards Mangalani Peter Makananisa Statistical Analyst South

Dear R gurus, I am currently using the chron package for date manipulation in R and I am able to control the date which take the format - 1998/07/03, and - 2006-09-15 (date without time) Library(chron) As.Date(2006-09-15, format = '%Y-%m-%d') However I have a problem with the date containing only the year and month (i.e. 2006-09, 2007/08, 200609).

Dear "R Gurus", I am having two dummy csv data sets A and B containing 19 and 15 cases/observations respectively. From the two data set 13 cases are intersection. From one of the two (any) data set, How do I then retrieve the unmerged data ? let's take A for example, six cases must appear in our results. See the R codes below. Please assist. Looking forward to hearing

Hi Duncan The simples spreadsheet is: Put a name in the cell, let say "a1" Put number e.g. 1 below "a1" Copy the number to enough rows Select this column and press ctrl-c result is > temp<- read.delim("clipboard") > str(temp) 'data.frame': 1513 obs. of 1 variable: $ a1: Factor w/ 2 levels "1","a1": 1 1 1 1 1 1 1 1 1 1 ...

Dear all I have 3 questions. Due to some reason I switched from Vista to Ubuntu on home PC. I was used to start with Rgui.exe. However I am not able to find it under Ubuntu and R starts as terminal (probably Rterm). Question 1. Is Rgui.exe available on linux? In Windows doc folder I can find manuals, however I did not find doc folder in Ubuntu. I found somewhere that manuals need to be