similar to: offset with a factor

Potential bug: I mistyped weights in the call ('weigths') and it did not produce any error= message. The coefs were exactly the same like without weights, so I was su= spicious and when weights(nls1) gave NULL, I saw my typo. Usually the function will say "Unused arguments", which shows you the error= , but not nls. Regards Stephen [[alternative HTML version deleted]]

Is there a utility which will allow me to upgrade my R version and update all packages from the old version? If I manually upgrade, then I have to manually re-install 50 packages. Thank you. Stephen B [[alternative HTML version deleted]]

Hi All, a) Is it possible to estimate the strength of seasonality in timeseries data. Say I have monthly mean prices of an ten different assets. I decompose the data using stl() and obtain the seasonal parameter for each month. Is it possible to order the assets based on the strength of seasonality? b) which gives a better estimate on seasonality stl() or a robust linear model like

Hi All, I'm fitting an intercept ANOVA model using R. I'm using following contrast statement, so my first level is considered as base level. options(contrasts = c("contr.treatment", "contr.treatment")) My data has two factors are "Month" and "WeekDay". Due to default alphabetic ordering, the Month(April) and WeekDay(Friday) are considered as base

Hello R People: When using the arima function with the seasonal option, are the seasonal options only good for monthly and quarterly data, please? Also, I believe that weekly and daily data are not appropriate for seasonal parm estimation via arima. Is that correct, please? Thanks, Sincerely, Laura Holt mailto: lauraholt_983 at hotmail.com download!

I am using AUTO ARIMA for forecasting. But it is not detecting 'seasonality term' of its own for any data. Is there any other method by which we can detect seasonality and its frequency for any data? Is there any method through which seasonality and its frequency can be automatically detected from ACF plot? -- Siddharth Arun, 4th Year Undergraduate student Industrial Engineering and

However, trying this on Linux Mint gave package ?installr? is not available (for R version 3.4.2) Has the package not been updated yet? JN Try the installr package. It was designed for this purpose. On Fri, Nov 10, 2017 at 11:49 AM, Bond, Stephen <Stephen.Bond at cibc.com> wrote: > Is there a utility which will allow me to upgrade my R version and update all packages from the old

Big thanks. newXMLNode works great. Wonder why it is not included in the documentation. There is newXMLDoc and newXMLNamespace, but no mention of newXMLNode. Stephen From: Ben Tupper [mailto:btupper at bigelow.org] Sent: Wednesday, March 21, 2018 6:18 PM To: Bond, Stephen Cc: r-help Subject: Re: [R] how to add a child to a child in XML Hi, XML doesn't use the `$` to access child nodes.

Hi, I have some doubt about how qualitative factors are coded in R. For instance, I consider a response y, a quantitative factor x and a qualitative factor m at 3 levels, generated as follow : y_c(6,4,2.3,5,3.5,4,1.,8.5,4.3,5.6,2.3,4.1,2.5,8.4,7.4) x_c(3,1,3,1,2,1,4,5,1,3,4,2,5,4,3) m_gl(3,5) lm(y~x+m) Coefficients: (Intercept) x m2 m3 3.96364 0.09818

Hi, It's a reasonable question. The answer is that it actually is included, but there are many instances across packages where multiple functions are documented on a single help page. The following brings up such a page... (for XML_3.98-1.9) > library(XML) > ?newXMLNode You can see the same on line... https://www.rdocumentation.org/packages/XML/versions/3.98-1.9/topics/newXMLDoc

Is there a package or a command that does window aggregation like select sum(col1) over (partition by col2, col3 order by col4 rows between unbounded preceding and current row) as sum1 from table1 ; the above is Netezza syntax, but Postgre has same capability. Stephen B [[alternative HTML version deleted]]

Just to clarify and hopefully catch the attention of the maintainer: The newXMLNode function is not mentioned in: https://cran.r-project.org/web/packages/XML/XML.pdf which supposedly describes all functions in the package. Stephen From: Ben Tupper [mailto:btupper at bigelow.org] Sent: Thursday, March 22, 2018 10:40 AM To: Bond, Stephen Cc: r-help Subject: Re: [R] how to add a child to a

Dear all, I would like to ask one question related to statistics, for specifically on defining dummy variables. As of now, I have come across 3 different kind of dummy variables (assuming I am working with Seasonal dummy, and number of season is 4): > dummy1 <- diag(4) > for(i in 1:3) dummy1 <- rbind(dummy1, diag(4)) > dummy1 <- dummy1[,-4] > > dummy2 <- dummy1 >

This issue does not exist on Linux. My Ubuntu updates both R and all packages. Stephen B -----Original Message----- From: J C Nash [mailto:profjcnash at gmail.com] Sent: Friday, November 10, 2017 1:19 PM To: r-help; RICHARD M. HEIBERGER; Bond, Stephen Subject: Re: [R] update R version in windows However, trying this on Linux Mint gave package ?installr? is not available (for R version

Is this a bug? seasonal.dummies <- function(x, contr=NULL) { # takes a time series and returns a matrix of seasonal dummies for # x. This is almost cycle(x), we only have to make it into a factor # and add suitable level names. # return a matrix which includes a constant! # level names here assumes frequency is 12! cyc <- factor( cycle(x), labels=c("ene","feb",

I am trying to add a child to a child using XML package in R. the following fails library(XML) node1 <- c("val1","val2","val3") names(node1) <- c("att1","att2","att3") root <- xmlNode("root", attrs=node1) node2 <- LETTERS[1:3] names(node2) <- paste("name",1:3,sep="") root <-

Hi Folks, No doubt a question with a well-known answer, but I'm unfortunately not managing to find it readily ... ! I have a quantitative variable Y and a 4-level ordered factor A (with very unequal numbers at the different levels, by the way). The command lm(Y ~ A) returns (amongst other stuff) an intercept, and coefficients A.L, A.Q and A.C for the Linear, Quadratic and Cubic effects.

I need to use contr.sum and observe that some levels are not statistically different from the overall mean of zero. What is the proper way of forcing the zero estimate? It seems the column corresponding to that level should become a column of zeros. Is there a way to achieve that without me constructing the design matrix? Thank you. Stephen Bond [[alternative HTML version deleted]]

Dear Members, I have been searching for a package in R which can handle multiple seasonality suggested by taylor(2003). It will be great help if anybody has used this on R before (i.e. which package). Thanks in Advance. Best Regards Atul Malik [[alternative HTML version deleted]]

Greetings useRs, What is the easiest way to create a design matrix of several factor variables? Function gendata in Design seems to do that for a fitted model, but how to do that only on several factor vectors?? The result should be a df with one row for each distinct combination of levels of factors eg for (M,F) (Y,O) We get M Y M O F Y F O In reality I will have more than 1000 rows so doing