similar to: likert Package

R- Help Forum Working with the "likert" package and find that my "bar" graphs are backwards (see attached) > summary(results) Item low neutral high mean sd 4 Q4 5 15 80 2.75 0.5501196 5 Q5 20 40 40 2.20 0.7677719 1 Q1 65 30 5 1.40 0.5982430 3 Q3 5 90 5 2.00 0.3244428 2 Q2 90 10 0 1.10 0.3077935

Dear Richard,? Thank you very much for your reply. I went through the code and it worked. I was also able to change the colours.? I was wondering if I can change the legend position; instead of being in the bottom to be on the left side.? I tried the following but without any success strip = FALSE strip.right = TRUE likert(t(hellisheidi), ReferenceZero=.5, xlab="X-lab",

Hi everyone, I'm stuck on my dissertation which is due next week. I'm a business major student and my project is a comparative research on corporate social responsibility (CSR) between Chinese and German firms. According to my literature review, it's quite obvious that German firms have much better CSR initiatives and strategies than the Chinese ones and I wanted to test whether it was

## you may need to install HH install.packagess("HH") library(HH) hellisheidi <- read.table(text=" Component Sample1 Sample2 Sample3 CaO 45 52 48 SiO2 25 22 18 Al2O3 15 11 14 TiO2 6 5

I'm creating a stacked bar chart using the likert command in the HH package. My data are in a data frame, with two numeric variables and a categorical variable, I can't get likert to use the column containing the categorical variable as a my y axis label. Here is a quick example: library(HH) #my data are:

Hi, I have just found this forum, and it looks like a great place to get some help (I hope) For my dissertation, which is due way too soon, I am doing a survey, comparing attitudes of 2 independent groups, with 5 scale likert questions. Basically I want to show if they have similar or different attitudes. I am testing 4 hypotheses, and have in total about 20 questions. I have to say my

Dear R members Could someone tell me how to simulate Likert-type data using the rnorm function. Let's say, 200*15 random numbers in a variable that goes from 1 to 4 in steps of 1 (i.e., 1, 2, 3, 4) belonging to a normal distribution? random.data <— matrix(rnorm(200 * 15), nrow = 200, ncol = 15) random.data The result cannot be reached. could one help me revise the syntax?

Help with survey data: Hello R colleagues, I hope this is an appropriate place to direct this question. It relates specifically to the comparability of a 5-point likert to a 4- point likert scale. One question in my dataset asks "How much should be done to reduce the gap between rich and poor" Much more, somewhat more, about the same, somewhat less and much less. The second

Hi, I have a question about how to obtain the union of several data frame rows. I'm trying to create a common key for several tests composed of different items. Here is a small scale version of the problem. These are keys for 4 different tests, not all mutually exclusive: id q1 q2 q3 q4 q5 q6 1 A C 2 B D 3 A D B 4 C D B D I would like

----- Original Message ----- From: "Silvano" <silvano at uel.br> To: <r-help at r-project.org> Sent: Thursday, June 30, 2011 9:07 AM Subject: Tables and merge > Hi, > > I have 21 files which is common variable CODE. > Each file refers to a question. > > I would like to join the 21 files into one, to construct > tables for each question by CODE. >

Dear colleagues, I would like to run a cluster analysis on a number of variables. They are Likert Scale (0 to 10), but they also have a "Don't know' option at the end of the scale. Apparently, with the 'Don't Know' option in place, they cannot be considered to be linear or ordinal. How can these variables be analysed using R? One option would be to use poLC and treat

Hi! I am using R to process some community survey data. Several item responses are recorded via a 7-point Likert-Scale. As I have coded the responses, 1 represents high agreement, and 7 high disagreement. This of course impacts the coefficients in a linear regression (of example agreement to self-perception measures on housing satisfaction). For some purposes, in order to make the coefficients

Dear all,? I am trying to plot the following table in stacked barplot in percentages and also horizontal. Component? ? ? Sample 1? ? ? Sample 2? ? ? Sample 3CaO????????????????? ? 45????????????? ? 52????????????? ? 48SiO2????????????????? ?25????????????? ? 22????????????? ? 18Al2O3?????????????????15????????????? ? 11????????????? ? 14TiO2? ? ? ? ? ? ? ? ? ? ?6? ? ? ? ? ? ? ? ? 5? ? ? ? ? ? ? ?

Hello, Before I start to construct something inferior myself I would like to know if such a plot function is already out there. I have count data of a small survey with a few questions which use a scale from "Strongly disagree" to "Strongly agree" and similar things. What I would like to have for a slide is a plot which shows for each question a line over this scale and the

If I'm understanding what's going on in this test correctly, what's happening is: * ARMTargetLowering::LowerCall prefers indirect calls when a function is called at least 3 times in minsize * In thumb 1 (without -fno-omit-frame-pointer) we have effectively only 3 callee-saved registers (r4-r6) * The function has three arguments, so those three plus the register we need to hold the

Hello, I have a table (1) of the form q1 q3 q4 q8 q9 A 5 2 0 1 3 B 2 0 2 4 4 I have another table (2): q1 q2 q3 q4 q5 q6 q7 q8 q9 C 10 7 4 2 6 9 3 1 2 I would like to divide the numbers in table (1) by the number of the appropriate column in table (2): q1 q3 q4 q8 q9 A 5/10 2/4 0/2 1/1 3/2 B 2/10 0/4 2/2 4/1 4/2

From: Jyri Sarha <jsarha at ti.com> I optimized Speex resampler for NEON capable ARM CPUs. The first patch should speed up resampling on any platform that can spare the increased memory usage. It would be nice to have these merged to the master branch. Please let me know if there is anything I can do to help the the merge. The patches have been rebased on top of master branch in

any suggestions on the following gratefully welcome, I have a dataframe, which I am subsetting via labels atpi[, creativity] where (for example) atpi = as.data.frame(matrix(1:50, ncol = 5, nrow = 10)) names(atpi) = c("Q1", "Q2", "Q3", "Q4", "Q5") and creativity = c("Q1", "Q3", "Q4") I want to add an extra column

> Yes! It works! I tried mono 8kbit 8khz Q3 and it seems to work! I am > currently talking to a friend, both ends using Speex! > Sound Quality is not as good as speeak freely@adpvm, but it uses only > quarter of bandwidth and for that the quality is not bad. Perhaps I'll > try Q4, as well. Q4 and Q3 seem to produce the same results. Internally speex is controlled by tables

Hi For first question, maybe I am completely wrong but cor(swiss[,-1], swiss[,1]) should give you what you want in one step. Second question Without an example it is hard to say but maybe aggregate is the way forward. > aggregate(iris[,1:4], list(iris$Species), function (x) c(mean=mean(x), sd=sd(x))) Group.1 Sepal.Length.mean Sepal.Length.sd Sepal.Width.mean Sepal.Width.sd 1