similar to: Package nleqslv ERROR

Displaying 20 results from an estimated 4000 matches similar to: "Package nleqslv ERROR"

2017 Aug 09
0
Package nleqslv ERROR
Santi, In the second line of your function you have the following: f <- numeric(length(x)) This sets the length of this numeric vector (i.e., "f") to the length of the vector "x". Later, inside the function you assign to values to 4 elements of the vector "f". This assumes that "f" is at least 4 element in length. However, you define
2013 Oct 11
3
matrix values linked to vector index
Hi, In the example you showed: m1<- matrix(0,length(vec),max(vec)) 1*!upper.tri(m1) #or ?m1[!upper.tri(m1)] <-? rep(rep(1,length(vec)),vec) #But, in a case like below, perhaps: vec1<- c(3,4,5) ?m2<- matrix(0,length(vec1),max(vec1)) ?indx <- cbind(rep(seq_along(vec1),vec1),unlist(tapply(vec1,list(vec1),FUN=seq),use.names=FALSE)) m2[indx]<- 1 ?m2 #???? [,1] [,2] [,3] [,4] [,5]
2011 Apr 06
5
Need a more efficient way to implement this type of logic in R
I have cobbled together the following logic. It works but is very slow. I'm sure that there must be a better r-specific way to implement this kind of thing, but have been unable to find/understand one. Any help would be appreciated. hh.sub <- households[c("HOUSEID","HHFAMINC")] for (indx in 1:length(hh.sub$HOUSEID)) { if ((hh.sub$HHFAMINC[indx] == '01')
2006 May 26
2
combinatorial programming problem
Hola! I am programming a class (S3) "symarray" for storing the results of functions symmetric in its k arguments. Intended use is for association indices for more than two variables, for instance coresistivity against antibiotics. There is one programming problem I haven't solved, making an inverse of the index function indx() --- se code below. It could for instance return the
2012 Mar 16
3
Faster way to implement this search?
I am working on a simulation where I need to count the number of matches for an arbitrary pattern in a large sequence of binomial factors. My current code is for(indx in 1:(length(bin.05)-3)) if ((bin.05[indx] == test.pattern[1]) && (bin.05[indx+1] == test.pattern[2]) && (bin.05[indx+2] == test.pattern[3])) return.values$count.match.pattern[1] =
2009 Nov 20
2
Finding & replacing non-ASCII characters
Hi guys, Are there any feasible methods in searching & finding non-ASCII characters in R? For example, from the following object, x <- mia. SzaÌmitaÌó The desired output is, x.out <- mia. SzaImitaIA Your help in resolving this would be greatly appreciated. [[alternative HTML version deleted]]
2016 Feb 03
2
[buildSchedGraph] memory dependencies
Hi, (This only concerns MISNeedChainEdge(), and is separate from D8705) I found out that the MIScheduler (pre-ra) could not handle a simple test case (test/CodeGen/SystemZ/alias-01.ll), with 16 independent load / add / stores. The buildSchedGraph() put too many edges between memory accesses, because 1) There was no implementation of areMemAccessesTriviallyDisjoint() for SystemZ. 2) Type
2010 Feb 22
1
shash in unique.c
Looking at shash in unique.c, from R-2.10.1 I'm wondering if it makes sense to hash the pointer itself rather than the string it points to? In other words could the SEXP pointer be cast to unsigned int and the usual scatter be called on that as if it were integer? shash would look like a slightly modified version of ihash like this : static int shash(SEXP x, int indx, HashData *d) {
2005 Sep 01
1
More block diagonal matrix construction code
Folks: In answer to a query, Andy Liaw recently submitted some code to construct a block diagonal matrix. For what seemed a fairly straightforward task, the code seemed a little "overweight" to me (that's an American stock analyst's term, btw), so I came up with a slightly cleaner version (with help from Andy): bdiag<-function(...){ mlist<-list(...) ## handle case in
2009 Sep 14
2
Escaping . in regular expression
If I run cvec<-c("test.f", "test.sf", "try.g","try.res", "try.f") print(cvec) indx<-grep('\.f',cvec,perl=TRUE) fset<-cvec[indx] print(fset) I get > cvec<-c("test.f", "test.sf", "try.g","try.res", "try.f") > print(cvec) [1] "test.f" "test.sf"
2013 Apr 14
1
possible loop problem
Hi, It would be better if you provided the output of dput(dataset).? I am not sure about the structure of your dataset. Just from reading the data as is shown. dat1<- read.table(text=" separator,tissID >,>,2 ,2,1 ,6,5 ,11,13 >,>,4 ,4,9 ,6,2 ,7,3 ,21,1 ,23,58 ,25,9 ,26,4 >,>,11 ,1,12 >,>,21 ,4,1 ,11,3
2010 May 20
2
reshaping data
Hello, I am a relatively new R-user who has a lot to learn. I have a large dataset that is in the following dataframe format: red A B C green D blue E F Where red, green and blue are "species" names and A, B and C are observations (corresponding to DNA sequences). Each observation can only belong to one species. I would like to list the observations in one column, with the species
2008 Aug 16
1
unique.default problem (PR#12551)
Full_Name: Vilmos Prokaj Version: R 2.7.1 OS: windows Submission from: (NULL) (213.181.195.84) Dear developers, The following line of code (produced by a mistake) caused an infinite loop unique("a",c("a","b")) or also unique(1,1:2) I made a little investigation, and it seems to be that the following function from unique.c is looping infinitely static int
2017 Oct 12
4
comparing two strings from data
Hi, I have two columns that contain numbers along with letters (as shown below) and have different lengths. Each entry in the first column is likely to be found in the second column at most once. For each entry of the first column, if that entry is found in the second column, I would like to get the corresponding index. For instance, if the first entry of the first column is 5th entry in the
2013 Sep 26
1
Grouping Matrix by Columns; OHLC Data
HI, May be this helps: set.seed(24) ?mat1<- matrix(sample(1:60,30*24,replace=TRUE),ncol=24) colnames(mat1)<- rep(c("O","H","L","C"),6) indx<-seq_along(colnames(mat1)) n<- length(unique(colnames(mat1))) ?res<- lapply(split(indx,(indx-1)%%n+1),function(i) mat1[,i]) lapply(res,head,2) #$`1` #????? O? O? O? O? O? O #[1,] 18 56 51 24 24 52 #[2,]
2012 May 11
2
moving data from one frame to another
Hello, I am working with two different data frames, and I'd like to move data from one to the other. Here is the first frame: > head(five) Week Game.ID VTm VPts HTm HPts HDifferential VDifferential 1 1 NFL_20050908_OAK at NE OAK 20 NE 30 10 -10 2 1 NFL_20050911_ARI at NYG ARI 19 NYG 42 23 -23 3 1 NFL_20050911_CHI
2015 Jul 01
3
[LLVMdev] MIScheduler + AA: Missed scheduling opportunity in MIsNeedChainEdge. Bug?
Hello, While tuning the MIScheduler for my target, I discovered a code that unnecessarily restricts the scheduler. I think this is a bug, but I would appreciate a second opinion. In file ScheduleDAGInstrs.cpp, the function MIsNeedChainEdge determines whether two MachineInstrs are ordered by a memory dependence. It first runs through the standard criteria (Do both instructions access memory?
2010 Aug 13
1
loop for inserting rows in a matrix
Dear R friends, I have a matrix with 2060 rows and 41 columns. One column is Date, another is Transect, and another is Segment. I want to ensure that there are 9 Transects (1 to 9) for each Date, and 8 Segments (1 to 8) for each Transect in the matrix, by inserting rows where these are missing. I am new to coding, but am trying to write a loop which checks if each of the transects already
2012 Dec 11
1
Debian packaging and openblas related crash when profiling in R
Hello R-sig-debian and (hopefully) Dirk: On Debian wheezy, I have the R packaging that CRAN (you) provide. I run into a little trouble while trying to fiddle with alternative BLAS. I know you and I went around on this last year and I think perhaps I've found something wrong in the framework, or I've just done something wrong. I installed the packages openblas-base and openblas-dev, and
2017 Oct 12
0
comparing two strings from data
It's generally a very good idea to examine the structure of data after you have read it in. str(data2) would have shown you that read.csv() turned your strings into factors, and that's why the == operator no longer does what you think it does. use ... data_2 <- read.csv("excel_data.csv", stringsAsFactors = FALSE) ... to turn this off. Also, the %in% operator will achieve