Displaying 20 results from an estimated 1000 matches similar to: "Declaring All Variables as Factors in GLM()"
2013 Apr 25
2
Selecting and then joining data blocks
Hi all,
I have 4 matrices, each having 5 columns and 4 rows .....denoted by
B1,B2,B3,B4.
I have generated a vector of 7 indices, say (1,2,4,3,2,3,1} which refers to
the index of the matrices to be chosen and then appended one on the top of
the next: like, in this case, I wish to have the following mega matrix:
B1over B2 over B4 over B3 over B2 over B3 over B1.
1> How can I achieve this?
2013 May 02
2
saving a matrix
Hi all,
In my data analysis,
I have created a random matrix M ( of order 500 X 7).
I want to use the same matrix when I start a new session, or suppose I want
to send this matrix to one of my friends (because this matrix is randomly
generated, and I dont want to use any other 500X7 matrix randomly generated
by R).
How can I save and call this matrix in the later sessions as well?
Appreciate
2013 Apr 25
1
Bootstrapping in R
Hi all,
1>i have 3 vectors a,b and c, each of length 25....... i want to define a
new data frame z such that z[1] = (a[1] b[1] c[1]), z[2] = (a[2] b[2] c[2])
and so on...how do i do it in R
2> Then i want to draw bootstrap samples from z.
Kindly suggest how i can do this in R.
Thanks,
Preetam
--
Preetam Pal
(+91)-9432212774
M-Stat 2nd Year,
2013 May 02
2
ARMA with other regressor variables
Hi,
I want to fit the following model to my data:
Y_t= a+bY_(t-1)+cY_(t-2) + Z_t +Z_(t-1) + Z_(t-2) + X_t + M_t
i.e. it is an ARMA(2,2) with some additional regressors X and M.
[Z_t's are the white noise variables]
How do I find the estimates of the coefficients in R?
And also I would like to know what technique R employs to find the
estimates?
Any help is appreciated.
Thanks,
2013 Apr 27
1
Selecting ridge regression coefficients for minimum GCV
Hi all,
I have run a ridge regression as follows:
reg=lm.ridge(final$l~final$lag1+final$lag2+final$g+final$u,
lambda=seq(0,10,0.01))
Then I enter :
select(reg) and it returns: modified HKB estimator is 19.3409
modified L-W estimator is 36.18617
smallest value of GCV at 10
I think it means that it is advisable to
2013 May 04
2
Lasso Regression error
Hi all,
I have a data set containing variables LOSS, GDP, HPI and UE.
(I have attached it in case it is required).
Having renamed the variables as l,g,h and u, I wish to run a Lasso
Regression with l as the dependent variable and all the other 3 as the
independent variables.
data=read.table("data.txt", header=T)
l=data$LOSS
h=data$HPI
u=data$UE
g=data$GDP
matrix=data.frame(l,g,h,u)
2013 Apr 30
1
ADF test --time series
Hi all,
I was running the adf test in R.
CODE 1:
adf.test(data$LOSS)
Augmented Dickey-Fuller Test
data: data$LOSS
Dickey-Fuller = -1.9864, Lag order = 2, p-value = 0.5775
alternative hypothesis: stationary
CODE 2:
adf.test(diff(diff(data$LOSS)))
Augmented Dickey-Fuller Test
data: diff(diff(data$LOSS))
Dickey-Fuller = -6.9287, Lag order = 2, p-value = 0.01
alternative
2013 Apr 26
1
Regression coefficients
Hi all,
I have run a ridge regression as follows:
reg=lm.ridge(final$l~final$lag1+final$lag2+final$g+final$g+final$u,
lambda=seq(0,10,0.01))
Then I enter :
select(reg) and it returns: modified HKB estimator is 19.3409
modified L-W estimator is 36.18617
smallest value of GCV at 10
I think it means that it is
2013 May 02
1
warnings in ARMA with other regressor variables
Hi all,
I want to fit the following model to my data:
Y_t= a+bY_(t-1)+cY_(t-2) + Z_t +Z_(t-1) + Z_(t-2) + X_t + M_t
i.e. it is an ARMA(2,2) with some additional regressors X and M.
[Z_t's are the white noise variables]
So, I run the following code:
for (i in 1:rep) { index=sample(4,15,replace=T)
final<-do.call(rbind,lapply(index,function(i)
2013 Apr 29
1
Arma - estimate of variance of white noise variables
Hi all,
Suppose I am fitting an arma(p,q) model to a time series y_t.
So, my model should contain (q+1) white noise variables.
As far as I know, each of them should have the same variance.
How do I get the estimate of this variance by running the arma(y) function
(or is there any other way)?
Appreciate your help.
Thanks,
Preetam
--
Preetam Pal
(+91)-9432212774
M-Stat 2nd Year,
2013 May 09
0
ARMA(p,q) prediction with pre-determined coefficients
I have the following time series model for prediction purposes
*Loss_t = b1* Loss_(t-1) + b2*GDP_t + b3*W_(t-1)* where W_t is the
usual white noise variable.
So this is similar to ARMA(1,1) except that it also contains an extra
predictor, GDP at time t.
I have only 20 observations on each variable except GDP for which I know
till 100 values.
And most importantly,I have also calculated
2013 Apr 30
0
Ridge regression
Hi all,
I have run a ridge regression on a data set 'final' as follows:
reg=lm.ridge(final$l~final$lag1+final$lag2+final$g+final$u,
lambda=seq(0,10,0.01))
Then I enter :
select(reg) and it returns: modified HKB estimator is 19.3409
modified L-W estimator is 36.18617
smallest value of GCV at 10
I think it
2013 May 03
1
Likelihood
Hi all,
I have run a regression and want to calculate the likelihood of obtaining
the sample.
Is there a way in which I can use R to get this likelihood value?
Appreciate your help on this.
The following are the details:
raw_ols1=lm(data$LOSS~data$GDP+data$HPI+data$UE)
summary(raw_ols1)
Call:
lm(formula = data$LOSS ~ data$GDP + data$HPI + data$UE)
Residuals:
Min 1Q
2009 Feb 27
4
Optimize for loop / find last record for each person
I want to find the last record for each person_id in a data frame
(from a SQL database) ordered by date. Is there a better way than
this for loop?
for (i in 2:length(history[,1])) {
if (history[i, "person_id"] == history[i - 1, "person_id"])
history[i, "order"] = history[i - 1, "order"] + 1 # same person
else
history[i,
2016 Apr 30
3
Could not find function "pointsToRaster"
Dear All,
I have a script that draws longitude and latitude of lightning
occurrence. This script was running fine before. But when I changed my
system and do a fresh install on another laptop, this error persist.
source("script")
Error in eval(expr, envir, enclos) :
could not find function "pointsToRaster"
I have tried to see if there is any other package I need to install
2009 Mar 30
5
Compatibility regression after migrating to 64 bit Linux
I used to use Wine (from 0.9.x to 1.1.x) on ArchLinux 32 bits to run a
Brazilian Dictionary called Houaiss [1], and it worked almost
flawlessly. But then I got a new computer and installed Ubuntu 64 bits
on it, and now Houaiss' interface is unreadable (same Windows software,
not a 64 bits version). I'll provide further information below, and I'd
like to know if it's a 64 bits
2006 Apr 11
1
pattern in history
Hi,
Sometimes I need to consult the history of commands that are matching a
regex, so I modified the utils::history function for that purpose. I
found it useful.
I append the code ( I only added the two lines with #**)
Romain.
history2 <-
function (pattern="", max.show = 25, reverse = FALSE, unique =
pattern!="", ...)
{
file1 <- tempfile("Rrawhist")
2013 Jun 11
0
Re: noapic in /etc/libguestfs-tools.conf
[Please send all questions and replies to the mailing list]
On Mon, Jun 10, 2013 at 09:34:09PM -0400, Preetam Jinka wrote:
> Hi Richard,
>
> I wanted to know how to set LIBGUESTFS_APPEND="noapic" through
> /etc/libguestfs-tools.conf
> but I'm not sure what the format of the file should be.
>
> Could you give me the exact line I should add which will work?
>
2012 Jul 17
2
comparing three vectors
Hi
I 've a data
a=c(10,20,30)
b=c(100,200,300)
c=c(50,60,70)
I want to compare a[1]<=c[1]<b[1],......
How to compare for all the records
-----
Thanks in Advance
Arun
--
View this message in context: http://r.789695.n4.nabble.com/comparing-three-vectors-tp4636728.html
Sent from the R help mailing list archive at Nabble.com.
2009 Apr 30
0
plot scaling bug when using par(mfg)
Dear list,
I've noticed a width/height scaling bug in multi-panel plots when you
change the active plot using par mfg
The underlying par setting that maps the full plot width (or height)
to the numerical axis labels does not get updated when you change
plots with par(mfg=...). Thus plotting a point at c(10,10) in the
first plot will only be in the correct place IF the most recently