similar to: error.crosses

Hello all, I have used describeBy to generate the following summary statistics. I simply need x and y error bars on a plot that has CQN (xaxis) and Price (yaxis). There should be four total points on the graph (one for each supplier). Using "error.crosses(desc$CQN, desc$Price)" does not work. group: a vars n mean sd median trimmed mad min max range skew CQN

Signed-off-by: Yuval Shaia <yuval.shaia at oracle.com> --- hw/Kconfig | 1 + hw/rdma/Kconfig | 4 + hw/rdma/Makefile.objs | 2 + hw/rdma/virtio/virtio-rdma-ib.c | 287 ++++++++++++++++++++ hw/rdma/virtio/virtio-rdma-ib.h | 93 +++++++ hw/rdma/virtio/virtio-rdma-main.c

Hallo, I am totally confused why Excel and R give me totally different regression results for the data below. If you know the solution, please enlighten me. In Excel I used LINEST() and Data>Data Analysis>Regression and both (fortunately) gave the same result. The coefficients were: /b0=1.16, b1=0.957, b2=0.024, R2=0.0027, adjusted R2=-0.017/ In R I used

Data center backends use more and more RDMA or RoCE devices and more and more software runs in virtualized environment. There is a need for a standard to enable RDMA/RoCE on Virtual Machines. Virtio is the optimal solution since is the de-facto para-virtualizaton technology and also because the Virtio specification allows Hardware Vendors to support Virtio protocol natively in order to achieve

Data center backends use more and more RDMA or RoCE devices and more and more software runs in virtualized environment. There is a need for a standard to enable RDMA/RoCE on Virtual Machines. Virtio is the optimal solution since is the de-facto para-virtualizaton technology and also because the Virtio specification allows Hardware Vendors to support Virtio protocol natively in order to achieve

On 2019/4/11 19:01, Yuval Shaia wrote: > Signed-off-by: Yuval Shaia <yuval.shaia at oracle.com> > --- > drivers/infiniband/Kconfig | 1 + > drivers/infiniband/hw/Makefile | 1 + > drivers/infiniband/hw/virtio/Kconfig | 6 + > drivers/infiniband/hw/virtio/Makefile | 4 + >

Signed-off-by: Yuval Shaia <yuval.shaia at oracle.com> --- drivers/infiniband/Kconfig | 1 + drivers/infiniband/hw/Makefile | 1 + drivers/infiniband/hw/virtio/Kconfig | 6 + drivers/infiniband/hw/virtio/Makefile | 4 + drivers/infiniband/hw/virtio/virtio_rdma.h | 40 + .../infiniband/hw/virtio/virtio_rdma_device.c | 59 ++

Hello, I'm trying to duplicate what's an easy process in RapidMiner. In RM, we can simply use two operators: subgroup iteration attribute value selection (Can use a regex for the attrribute name.) I can do this in R with a lot of code and manual steps. It would be really nice to find a more automated way. My data looks like this group group_height group_weight height

On Mon, Oct 17, 2016 at 10:24 AM, Mark Nienberg < mnlists at tippingstructural.com> wrote: > > On Mon, Oct 10, 2016 at 10:18 AM, Trenta sis via samba < > samba at lists.samba.org> wrote: > >> We have detected that machines with dhcp (It was configured as is >> described >> in samba wiki dhcp and samba 4) are updating correclty and any message >>

Dear R users, I have a dataset with two variables: $esan - a grouping factor with 8 levels and $reus. I'd like to do wilcox.test on this dataset as sugested Weiwei here: https://stat.ethz.ch/pipermail/r-help/2007-July/136627.html. I tried to adapt his recommendation but no succes. Can anyone help me? Regards, Iurie Malai, Senior Lecturer Department of Psychology Faculty of Psychology and

On 2016-05-25 19:13, Kelly Lesperance wrote: > Hdparm didn?t get far: > > [root at r1k1 ~] # hdparm -tT /dev/sda > > /dev/sda: > Timing cached reads: Alarm clock > [root at r1k1 ~] # Hi Kelly, Try running 'iostat -xdmc 1'. Look for a single drive that has substantially greater await than ~10msec. If all the drives except one are taking 6-8msec, but one is very

hi Friends, Planning to use BlueHost.com for my Ruby on Rails application hosting on their $6.95 per month. Is anyone using them ? What version of ROR do they provide ? What kind of webserver does they provide ? How much RAM ? Can i re-start the web-server if my ROR application demands ? May be the above answers would be best answered by their sales dept. But if anyone is using them, please

I tried toy problems and there doesn't seem to be a basic problem between lm() and ts objects: X = data.frame(x=c(1,2,7,9), y=c(7,2,3,1)) lm(y ~ x, X) X <- lapply(X, function(x) ts(x, frequency=12, start=c(1994,7))) lm(y ~ x, X) and this works fine - whether you do an lm() before or after making ts objects, it's okay. But I have a situation where things aren't okay.

Hi R users. I have a table like that: table var A1 A2 A3 v1 41203 3.69 2.31 v2 20577 4.51 8.60 v3 20625 2.87 3.50 v4 6115 8.92 2.97 v5 3160 1.49 2.21 v6 2954 2.62 5.98 v7 4731 1.83 7.53 v8 2435 7.68 3.50 v9 2296 3.03 4.84 v10 6153 1.06 4.28 v11 3157 1.07 1.15 v12 2996 1.06 1.01 v13 6084 2.65 2.63 v14 3115 2.42

Hi, I am trying to find m breakpoints of a linear regression model. I used the segmented package. It works fine for small number of predicators and breakpoints.(3 r.v. 3 points). However, my model has 14 variables it even would not work even for just one breakpoints!. The error message is always estimated breakpoints are out of range. Since my problem is time related problem. So I

Dear list: I am interested in the following sort of problem, as is found frequently in the field of QSAR. I have biological activity as a function of chemical structure, with structure defined in a categorical manner in that the SUBSTITUENT is the levels of the POSITION factor. For example, data from Kubinyi (http://www.kubinyi.de/dd-12.pdf) for this type of analysis is presented as follows:

Dear Forum, I have a question about interaction estimate in the Cox model: why the hazard ratio of the interaction is not produced in the summary of the model? (Instead, the estimate of the coefficient is given in the print of the model.) # Example: modINT <-cph( Surv(T_BASE, T_FIN,STATUS)~ NYHA + ASINI + RFP + FE_REC + XX_PR*XX_DISF) print(modINT) coef se(coef) z

Hello, I would like to get a correlation coefficient (R-squared) for my model. I don't know how to calculate it in R. What I've done so far: x<-8.5:32.5 #Vektor x y<-c(NA ,5.88 , 6.95 , 7.2 , 7.66 , 8.02 , 8.44 , 9.06, 9.65, 10.22 , 10.63 ,11.06, 11.37, 11.91 ,12.28, 12.69 ,13.07 , 13.5 , 13.3 ,14.14 , NA , NA , NA , NA , NA) #Vektor y

Hello List, My goal is to create a 5 category variable (p1_st_data$ob_mrj_cat), based on the p1_st_data$obt_mrj_p variable, using the following code for 50 States and District of Columbia (N=51). p1_st_data$ob_mrj_cat <- cut (p1_st_data$obt_mrj_p, quantile (p1_st_data$obt_mrj_p, (0:5/5), include.lowest=TRUE)) The issue is that, for Utah, I am getting an <NA> instead of (42,48.7] in

Hi, I am would like to ask few questions. I am trying to forecast hourly electricity prices by 24 hours ahead. I have hourly data starting from 2015*12*18 to 2017-10-24 and I have defined the data as time series as written in the code below. Then I am trying do neural network with 23 non-seasonal dummies and 1 seasonal dummy. But I don?t know whether training set is enough.( Guess it is 50