similar to: assign color to subsets

'grepl' returns a logical vector; you have to use this to get your subset. You can use: df_tq <- subset(df, grepl("t1", Command)) df_t2 <- subset(df, grepl("t2", Command)) # if you want to also get a subset that has both, use df_both <- subset(df, grepl("t1", Command) & grepl("t2", Command)) Jim Holtman Data Munger Guru What is

now after this: df_both <- subset(df, grepl("t1", Command) & grepl("t2", Command)) I use factor to apply the subset to df but then the Command level becomes 0 df_both$Command=factor(df_both$Command) str(df_both) $ Protocol : Factor w/ 0 levels: Do you know what is the reason? Thanks for replying On Sunday, April 24, 2016 12:18 PM, jim

my problem is that in Command I have 2229 levels and I want to do subsets based on the names I have in Command. for example if the name has t1 or t2 in it or if it has both of them.and then I need to plot in a way that colors are names with t1,names with t2 and names with both. But now even the grepl I use for the subsets does not work correct! :((( hast1=grepl("t1", df$Command,

Thanks Jean, Does anyone know how to set these [hast1] and [hast2] as the colors of a plot? On Friday, April 22, 2016 7:39 AM, "Adams, Jean" <jvadams at usgs.gov> wrote: You can use the grepl() function to give you logicals for each criterion, then combine them as needed. For example: # example version of Command Command <- paste0("_localize_",

You can use the grepl() function to give you logicals for each criterion, then combine them as needed. For example: # example version of Command Command <- paste0("_localize_", c("PD","t2","t1_seq", "abc", "xyz", "PD_t1")) hasPD <- grepl("PD", Command, fixed=TRUE) hast1 <- grepl("t1", Command,

Hi all, I have one factor variable in my df and I want to extract the names from it which contain both "t2" and "pd": 'data.frame': 36919 obs. of 162 variables $TE :int 38,41,11,52,48,75,..... $TR :int 100,210,548,546,..... $Command :factor W/2229 levels

Hi all, I have a data frame df and I want to do subset based on several conditions of letters of the names in Command.1)if the names contain PD 2)if the names contain t1 3)if the names contain t2 4)if the names contain t1 and PD 5)if the names contain t2 and PD 6)otherwise the names would be unknown. I don't know how to use grep for all these conditions. 'data.frame': 36919

Hi all, I would like to get ideas about how to fill out a PDF form in R and to know if it's possible or not. I could not find something helpful in Internet. Does anyone know a good link for that or have experience in this? Thanks for any help! Elahe

You can define stop words as below. data <- tm_map(data, removeWords, stopwords("english")) Patrick Casimir, PhD Health Analytics, Data Science, Big Data Expert & Independent Consultant C: 954.614.1178 ________________________________ From: R-help <r-help-bounces at r-project.org> on behalf of Bert Gunter <bgunter.4567 at gmail.com> Sent: Monday, June 12, 2017

Hi all, Is there a way in R to count the number of stop words (English) of a string using tm package? str="Mhm . Alright . There's um a young boy that's getting a cookie jar . And it he's uh in bad shape because uh the thing is falling over . And in the picture the mother is washing dishes and doesn't see it . And so is the the water is overflowing in the sink . And the

Thanks for your reply. I know the command data <- tm_map(data, removeWords, stopwords("english")) removes English stop words, I don't know how should I count stop words of my string: str="Mhm . Alright . There's um a young boy that's getting a cookie jar . And it he's uh in bad shape because uh the thing is falling over . And in the picture the mother is

define your string as whatever object you want: data <- "Mhm . Alright . There's um a young boy that's getting a cookie jar . And it he's uh in bad shape because uh the thing is falling over . And in the picture the mother is washing dishes and doesn't see it . And so is the the water is overflowing in the sink . And the dishes might get falled over if you don't fell

You can use regular expressions. ?regex and/or the stringr package are good places to start. Of course, you have to define "stop words." Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Mon, Jun 12, 2017 at 5:40

Defining data as you mentioned in your respond causes the following error: Error in UseMethod("tm_map", x) : no applicable method for 'tm_map' applied to an object of class "character" I can solve this error by using Corpus(VectorSource(my string)) and the using your command but I cannot see the number of stop words in my string! On Monday, June 12, 2017 8:36

Hi all, I would like to do cross validation in random forest using rfcv function. As the documentation for this package says: rfcv(trainx, trainy, cv.fold=5, scale="log", step=0.5, mtry=function(p) max(1, floor(sqrt(p))), recursive=FALSE, ...) however I don't know how to build trianx and trainy for my data set, and I could not understand the way trainx is built in the package

Hi Elahe, I have no clue, but maybe you can dump the data fields using pdftk, and work with those in R. HTH Ulrik On Wed, 26 Jul 2017 at 13:50 Elahe chalabi via R-help <r-help at r-project.org> wrote: > Hi all, > > I would like to get ideas about how to fill out a PDF form in R and to > know if it's possible or not. I could not find something helpful in > Internet.

Hi, I have a data set (mydata), which a part of this is like the following: 'data.frame': 36190 obs. of 16 variables: $ RE : int 38 41 11 67 30 18 38 41 41 30 ... $ LU : int 4200 3330 530 4500 3000 1790 4700 3400 3640 4000 ... $ COUNTRY : Factor w/ 4 levels "DE","FR","JP", "FR"? $Light

It's not what I want, the first data frame has 499 observations and the second data frame is a subset of the first one but with 375 observations. I want something that returns the ID for training data frame On Wednesday, November 1, 2017 10:18 AM, Eric Berger <ericjberger at gmail.com> wrote: matches <- merge(training,data,by=intersect(names(training),names(data))) HTH, Eric

Hi all, Does anyone know how to overlay two facet_grids? I have two facet grids as following: ggplot(data=df,aes(x=TE,y=TR,color="orange"))+geom_point()+facet_grid(FS+TRJ~OR+INV,labeller=label_both)+xlim(0,200)+ylim(0,10000) ggplot(data=df,aes(x=TE,y=TR))+geom_point(aes(color=TST))+facet_grid(FS+TRJ~OR+INV,labeller=label_both)+xlim(0,200)+ylim(0,10000) Thanks for any help! Elahe

Hi all, How can I overlay these two histograms? ggplot(gg, aes(gg$Alz, fill = gg$veg)) + geom_histogram(alpha = 0.2) ggplot(tt, aes(tt$Cont, fill = tt$veg)) + geom_histogram(alpha = 0.2) thanks for any help! Elahe