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Dear All, I have a script that draws longitude and latitude of lightning occurrence. This script was running fine before. But when I changed my system and do a fresh install on another laptop, this error persist. source("script") Error in eval(expr, envir, enclos) : could not find function "pointsToRaster" I have tried to see if there is any other package I need to install

Dear Members, Compliments of the Season!! Below is a part of a code I use for Fourier analysis of signals. The code handles data with the format 05 01 01 8628 (year, month, day and count) 05 01 02 8589 (year, month, day and count) The sample data is attached as 2005daily.txt. I would like to adapt the code to handle data of the form: 05 01 01 00 4009

Hi Ogbos, You can just use ISOdate. If you pass more values, it will process them: ISOdate(2018,01,22) [1] "2018-01-22 12:00:00 GMT" > ISOdate(2018,01,22,18,17) [1] "2018-01-22 18:17:00 GMT" Add something like: if(is.null(data$hour),data$hour<-12 then pass data$hour as it will default to the same value as if you hadn't passed it. Jim On Mon, Jan 22, 2018 at 6:01

Dear ALL, Thank you so much for your contributions. I have made some progress. Below is a simple script I gleaned from your kind responses: Sys.setenv(TZ="Etc/GMT") dates <- c("02/27/92", "02/27/92", "01/14/92", "02/28/92", "02/01/92") times <- c("23:0:0", "22:0:0", "01:00:00", "18:0:0",

Hi, A terrific resource for this type of issue (and pretty much anything related to R) is http://rseek.org/ I'm sure I use it at least daily. Check out ... http://rseek.org/?q=pointsToRaster The first hit is about pointsToRaster() - it has been replaced by raster::rasterize() Cheers, Ben > On Apr 30, 2016, at 4:28 AM, Ogbos Okike <giftedlife2014 at gmail.com> wrote: > >

Kind Experts, Many thanks for your guide. I have tried to figure out something that can help me plot my own data using the examples you referred me to. I copied part of the code as: set.seed(44) N=500 events <- as.POSIXct("2011-01-01", tz="GMT") + days(floor(365*runif(N))) + hours(floor(24*rnorm(N))) + # using rnorm here

Looks like you forgot to load the lubridate package library(lubridate) You are calling functions days(), hours(), minutes(), seconds(), and hour() which all come from that package. ------------------------------------- David L Carlson Department of Anthropology Texas A&M University College Station, TX 77840-4352 -----Original Message----- From: R-help [mailto:r-help-bounces at

Dear Rui, Thanks again for resolving this. I have already started using the version that works for me. But to clarify the second part, please let me paste the what I did and the error message: > set.seed(2024) > data <- data.frame( + Date = sample(seq(Sys.Date() - 5, Sys.Date(), by = "1 days"), 100L, + TRUE), + count = sample(10L, 100L, TRUE) + ) > > # coerce

The most important thing is that Date objects by definition do not include time of day. You want to look at ISOdatetime() and as.POSIXct() instead. And beware daylight savings time issues. -pd On 18 Apr 2016, at 15:09 , Ogbos Okike <giftedlife2014 at gmail.com> wrote: > Dear All, > > I have a data set containing year, month, day and counts as shown below: > data <-

Dear All, I have a data set containing year, month, day and counts as shown below: data <- read.table("data.txt", col.names = c("year", "month", "day", "counts")) Using the formula below, I converted the data to as date and plotted. new.century <- data$year < 70 data$year <- ifelse(new.century, data$year + 2000, data$year + 1900)

Dear All, I am trying to generate a circular/radial plot. The script below has a result I am looking for: testlen<-rnorm(24)*2+5 testpos<-0:23+rnorm(24)/4 clock24.plot(testlen,testpos,main="Test Clock24 (lines)",show.grid=FALSE, line.col="green",lwd=3) if(dev.interactive()) par(ask=TRUE) # now do a 'daylight' plot

I use ggplot2 for all my plotting needs where you can make plots circular with the coord_polar. Maybe this will help you along: http://rstudio-pubs-static.s3.amazonaws.com/3369_998f8b2d788e4a0384ae565c4280aa47.html On Fri, 22 Apr 2016 at 08:31 Ogbos Okike <giftedlife2014 at gmail.com> wrote: > Dear All, > I am trying to generate a circular/radial plot. The script below has a >

Hello, I am runing linux on Ubuntus. I find it difficult to install R packages. I am in South Africa. It always asked me to choose the nearest CRAN mirror. I normally choose South Africa and once I clicked Ok, the error message pasted below will appear. Please I am a new student of R and Ubuntus. The other warning "argument 'lib' is missing: using

Hello, Please I am a learner. My operating system is ubuntus and I am trying to install raster package from R-forge site. I entered sudo apt-get install r-base-dev on the command line and that worked fine. I then typed R at the command line so as to run R. Inside R, I typed > install.packages("raster",repos="http://R-Forge.R-project.org<http://r-forge.r-project.org/>")

Dear all, I am trying to add error bars on a boxplot but have encountered an error as indicated below. Is there a package I need to install or a library I have to load before this goes please. Thanks for any idea. Ogbos x<-replicate(20,rnorm(50)) boxplot(x,notch=TRUE,main="Notched boxplot with error bars") error.bars(x,add=TRUE) Error: could not find function "error.bars"

Good day to you all, I have lightning data containing date, time, latitude and longitude. I hope that distribution of latitude and longitude will give number of lightning occurrence in a region. I have used factor function to sum up the number of events on latitude and longitude axis and saved as x and y. But when I tried to plot the two, I had and error message ( Error in image.default(x, y, z) :

?s 01:43 de 29/03/2024, Ogbos Okike escreveu: > Dear Rui, > Thanks again for resolving this. I have already started using the version > that works for me. > > But to clarify the second part, please let me paste the what I did and the > error message: > >> set.seed(2024) >> data <- data.frame( > + Date = sample(seq(Sys.Date() - 5, Sys.Date(), by = "1

Hi Everybody, I have a matrix of about 45 columns. Some of the rows contain zeros. Using >data1<-data[complete.cases(data),], I can remove the "NA" rows. But I am unable to tackle that of zeros. Can anybody give me an idea of how to remove rows containing zeros in a matrix. Thanks so much Best Ogbos [[alternative HTML version deleted]]

Greetings to you all. I have two datasets - Time and magnitude. For a particular location, the magnitude of the parameter varies with time. I wish to obtain a polar coordinate distribution of time (0-24h) and magnitudes so as to visualize how magnitude varies with different times of the day (e.g., morning, midnight hours). I have searched for "polar coordinates in R" but could not get

Dear List, I am trying to label a plot with the symbol +/- sigma. Using something like - expression (2*sigma) gives me the symbol 2ó. However, adding +/- to it beats me. The code I am using is: plot(x,y,type="l",main=" expression(paste("±", plain(2*ó)),sep=""). Any suggestion will be appreciated. Best Ogbos [[alternative HTML version deleted]]