similar to: Mean of hexadecimal numbers

Displaying 20 results from an estimated 2000 matches similar to: "Mean of hexadecimal numbers"

2016 Apr 16
0
Mean of hexadecimal numbers
On 16/04/2016 8:47 AM, Atte Tenkanen wrote: > Hi, > > How would you calculate the "mean colour" of several colours, for > example c("#FF7C00","#00BF40","#FFFF00")? > Bert answered your subject line question. Your text is asking something else: if those are colours, you don't want to treat each of them as a single integer. A
2016 Apr 16
1
Mean of hexadecimal numbers
Hm..., Should these two versions produce the same solution? Unfortunately and shame to confess, I don't know much about the colors in R: myColors <- c("#FF7C00","#00BF40","#FFFF00") Colors=rgb2hsv(col2rgb(myColors)) apply(Colors,1,mean) h s v 0.2122974 1.0000000 0.9163399 * * * * * # Average the 1st two by taking the middle colour
2016 Apr 16
2
Mean of hexadecimal numbers
... and if you need to convert back: ?as.hexmode -- Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Sat, Apr 16, 2016 at 8:20 AM, Bert Gunter <bgunter.4567 at gmail.com> wrote: > ?strtoi > > You'll have to remove
2016 Apr 16
0
Mean of hexadecimal numbers
Since these are color strings, you can use functions in the grDevices package (other others) to manipulate them. E.g., you can convert them to various color spaces and perhaps use the mean in one of those spaces as your 'average color'. > myColors <- c(One="#FF7C00",Two="#00BF40",Three="#FFFF00") > col2rgb(myColors) One Two Three red
2016 Apr 16
0
Mean of hexadecimal numbers
?strtoi You'll have to remove the "#" first, e.g. via substring() -- Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Sat, Apr 16, 2016 at 5:47 AM, Atte Tenkanen <attenka at utu.fi> wrote: > Hi, > > How
2016 Apr 16
0
Mean of hexadecimal numbers
On 16/04/2016 12:33 PM, Atte Tenkanen wrote: > Hm..., > > Should these two versions produce the same solution? I wouldn't expect them to. Duncan Murdoch Unfortunately and > shame to confess, I don't know much about the colors in R: > > myColors <- c("#FF7C00","#00BF40","#FFFF00") > Colors=rgb2hsv(col2rgb(myColors)) >
2013 Jul 24
1
Alpha channel in colorRamp() and colorRampPalette()
Hi all, I had the need to create a colorbar considering the alpha channel of the colors, but colorRamp() and colorRampPalette() ignored the alpha argument in rgb(). So I performed some minor modifs. in their codes, as to support the interpolation using the alpha channel. I guess that those simple modifications might be useful for other people, so perhaps it would be worth to add them to
2010 Sep 21
1
Colorramp in Maptools, how to choose min and max values for the fg= argument
Hello, I am using maptools for plooting geographical data. The colour of the region indicates some region dependent value (population for example). I pass the colours of the regions to the plot.Map function by defining the foreground colour: jet.colors = colorRampPalette(c("#00007F", "blue", "#007FFF", "cyan", "#7FFF7F", "yellow",
2009 Apr 17
1
ColorRamp different from ColorRampPalette
I try to use ColorRamp as ColorRampPalette (i.e. with the same gradient), but it seems there is a nuance that I've missed. pal.crp<-colorRampPalette( c("blue", "white", "red"), space = "rgb") plot(rep(0,40),pch=16,col=pal.crp(40)) # is great But, using the same gradient with colorRamp is giving erratic colors. pal.cr<-colorRamp(
2005 Oct 03
5
heatmap
Hi, i created a graph with heatmap(sma) function: heatmap(dataHeat(x)) and I wish to change the gradation of colors from blue to red, how could i do? Using "heatmap(dataHeat(x), col=c(2,4))" i will use only 2 colors without gradation. Ty so much Andrea
2005 Dec 13
4
Ploting graphics using X tints from a color
Hi, I'm trying to draw a 2D plot using multiple tints of red. The (simplified) setup is the following: || year | x | y || My idea is that each year is plotted with a different tint of red. Older year (lightest) -> Later year (darkest). I've managed to plot this with different scales of grays simply by doing: palette(gray(length(years):0/length(years))) before the plot and for each
2009 Oct 09
4
Satellite ocean color palette?
Dear List, Is there a color palette avaliable similar to what is used in satellite ocean color imagery? I.e. a gradient with blue on one end and red on the other, with yellow in the middle? I have tried topo.colors(n) but that comes out more yellow on the end. I am looking for something similar to what is found on the CoastWatch web page:
2010 Nov 20
1
Setting a Red->Yellow->Green Color Transition in Image(...) with yellow corresponding with the Mean Value...
In the following example I would like to have the color transition from Red->yellow->green in the image(...) function, and if possible have the yellow be set to correspond with the mean value (for the below 75). ? I was able to figure something like out when using filled.contour(...), e.g. filled.contour(ak.fan, levels = c(70, 73, 76,?80, 90), color = terrain.colors) (I still
2009 May 20
4
Functions returning functions
Dear All: I have a question regarding the behavior of functions. Say I define a function that returns another function : A <- function(parameters) { # calculations w/ parameters returning 'y' tmpf <- function(x) { # function of 'y' } return(tmpf) } The value of the parameters are stored in an environment local to the function. Then I call x<- something
2006 Aug 16
5
How to remove similar successive objects from a vector?
Is there some (much) more efficient way to do this? VECTOR=c(3,2,4,5,5,3,3,5,1,6,6); NEWVECTOR=VECTOR[1]; for(i in 1:(length(VECTOR)-1)) { if((identical(VECTOR[i], VECTOR[i+1]))==FALSE){ NEWVECTOR=c(NEWVECTOR,VECTOR[i+1])} } > VECTOR [1] 3 2 4 5 5 3 3 5 1 6 6 > NEWVECTOR [1] 3 2 4 5 3 5 1 6 _______________________________ Atte Tenkanen University of Turku, Finland
2009 Mar 27
3
color vectors other than gray()
I'm trying to create a graph where different cells of a grid (a shapefile) will be painted with a color share scale, where the most easy way is to use gray(). Can I somehow get a vector (gradient) of colors, a vector of colors with other methods but gray()? I'm doing this until now quad_N_sp <-
2006 Jun 19
3
Border line width?
Is there some way to change the line widths of plot borders? I couldn't find any parameters for that purpose. Atte Tenkanen University of Turku, Finland
2012 Dec 17
3
How to test whether is.element() returns only TRUE's
Hi, How can I test, whether all the values that is.element() -function returns are TRUE's Eg. > (is.element(c(1,4,2),c(1,2,3))) [1] TRUE FALSE TRUE This doesn't work: > (is.element(c(1,4,2),c(1,2,3)))==TRUE [1] TRUE FALSE TRUE Best, Atte Tenkanen, FT, MuM http://users.utu.fi/attenka/
2006 Oct 06
4
Row comparisons to a new matrix?
Hi, Can somebody tell me, which is the fastest way to make comparisons between all rows in a matrix (here A) and put the results to the new symmetric matrix? I have here used cosine distance as an example, but the comparison function can be any other, euclidean dist etc. A=rbind(c(2,3),c(4,5),c(-1,2),c(5,6)) M=matrix(nrow=length(A[,1]),ncol=length(A[,1])) for(i in 1:length(A[,1])) { for(j in
2007 May 06
7
A function for raising a matrix to a power?
Hi, Is there a function for raising a matrix to a power? For example if you like to compute A%*%A%*%A, is there an abbreviation similar to A^3? Atte Tenkanen > A=rbind(c(1,1),c(-1,-2)) > A [,1] [,2] [1,] 1 1 [2,] -1 -2 > A^3 [,1] [,2] [1,] 1 1 [2,] -1 -8 But: > A%*%A%*%A [,1] [,2] [1,] 1 2 [2,] -2 -5