Displaying 20 results from an estimated 4000 matches similar to: "p values from GLM"
2016 Apr 02
0
p values from GLM
Bert Gunter wrote on 01.04.2016 23:46:
> ... of course, whether one **should** get them is questionable...
>
> http://www.nature.com/news/statisticians-issue-warning-over-misuse-of-p-values-1.19503#/ref-link-1
>
This paper repeats the common place statement that a small p-value does
not necessarily indicate an important finding. Agreed, but maybe I
overlooked examples of important
2016 Apr 01
6
p values from GLM
... of course, whether one **should** get them is questionable...
http://www.nature.com/news/statisticians-issue-warning-over-misuse-of-p-values-1.19503#/ref-link-1
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Fri, Apr
2016 Apr 01
0
p values from GLM
On 01/04/2016 6:14 PM, John Sorkin wrote:
> How can I get the p values from a glm ? I want to get the p values so
I can add them to a custom report
>
>
> fitwean<-
glm(data[,"JWean"]~data[,"Group"],data=data,family=binomial(link ="logit"))
> summary(fitwean) # This lists the coefficeints, SEs, z
and p values, but I can't
2016 Apr 02
0
p values from GLM
On 01/04/2016 6:46 PM, Bert Gunter wrote:
> ... of course, whether one **should** get them is questionable...
They're just statistics. How could it hurt to look at them?
Duncan Murdoch
>
> http://www.nature.com/news/statisticians-issue-warning-over-misuse-of-p-values-1.19503#/ref-link-1
>
>
> Cheers,
> Bert
>
>
>
> Bert Gunter
>
> "The trouble
2016 Apr 01
2
p values from GLM
How can I get the p values from a glm ? I want to get the p values so I can add them to a custom report
fitwean<- glm(data[,"JWean"]~data[,"Group"],data=data,family=binomial(link ="logit"))
summary(fitwean) # This lists the coefficeints, SEs, z and p values, but I can't isolate the pvalues.
names(summary(fitwean)) # I see the coefficients,
2016 Apr 02
2
p values from GLM
> On Apr 1, 2016, at 5:01 PM, Duncan Murdoch <murdoch.duncan at gmail.com> wrote:
>
> On 01/04/2016 6:46 PM, Bert Gunter wrote:
>> ... of course, whether one **should** get them is questionable...
>
> They're just statistics. How could it hurt to look at them?
Like Rolf, I thought that this utterance on April 1 deserved fortune enshrinement. It reminded me of one
2018 Dec 17
0
Documentation examples for lm and glm
Dear Heinz,
----------------------------------------------
> On Dec 17, 2018, at 10:19 AM, Heinz Tuechler <tuechler at gmx.at> wrote:
>
> Dear All,
>
> do you think that use of a data argument is best practice in the example below?
No, but it is *normally* or *usually* the best option, in my opinion.
Best,
John
>
> regards,
>
> Heinz
>
> ###
2004 Nov 30
1
Attn Heinz Tuechler: Re: problem with special characters (ä,ö,ü)
[I tried to send this message privately, but the return address
bounced.]
I think this has been fixed in R-patched, but I doubt if the fix has
been tested in Win98. Could you please download a copy from
<http://cran.r-project.org/bin/windows/base/rpatched.html> and confirm
that it has been fixed?
Duncan Murdoch
On Sat, 27 Nov 2004 23:31:23 +0100, Heinz Tuechler <tuechler at gmx.at>
2000 May 09
4
Dispersion in summary.glm() with binomial & poisson link
Following p.206 of "Statistical Models in S", I wish to change
the code for summary.glm() so that it estimates the dispersion
for binomial & poisson models when the parameter dispersion is
set to zero. The following changes [insertion of ||dispersion==0
at one point; and !is.null(dispersion) at another] will do the trick:
"summary.glm" <-
function(object, dispersion =
2006 Jan 05
2
Splitting the list
I've changed the heading because this really is another thread. I
think it inevitable that there will, in the course of time, be other
lists that are devoted, in some shape or form, to the concerns of
practitioners (at all levels) who are using R. One development I'd
not like to see is fracture along application area lines, allowing
those who are comfortable in coteries whose
2015 Jan 27
0
R-devel Digest, Vol 143, Issue 25
OK, I see now that I was supposed to twig that the reference was to putting the ?.Rnw'
files back into the vignettes directory from the inst/doc directory where they?d been
placed in the course of creating the tar.gz file. I am still trying to work out what I need
to put into ?.Rinstignore? so that ?.install_extras? is not installed.
John Maindonald email: john.maindonald at
2015 Jan 27
0
R CMD check message: "The following files should probably not be installed"
Sorry. This, and the description in the ?Writing R Extensions? manual,
leaves me completely mystified. Is it that I have to remove the PDFs
that are created when I run ?R CMD build?, and somehow ensure that
they are rebuilt when the package is installed? Do I need a Makefile?
John Maindonald email: john.maindonald at anu.edu.au<mailto:john.maindonald at anu.edu.au>
phone :
1999 Dec 03
0
Error in plot.aov() (PR#356) (fwd)
Confirmation from John Maindonald.
--
Brian D. Ripley, ripley@stats.ox.ac.uk
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272860 (secr)
Oxford OX1 3TG, UK Fax: +44 1865 272595
---------- Forwarded message ----------
Date: Fri, 3
2005 Aug 02
3
how to print a data.frame without row.names
Dear All,
is there a simple way to print a data.frame without its row.names?
example:
datum <- as.Date(c("2004-01-01", "2004-01-06", "2004-04-12"))
content <- c('Neujahr', 'Hl 3 K.', 'Ostern')
df1 <- data.frame(datum, content)
print(df1)
datum content
1 2004-01-01 Neujahr
2 2004-01-06 Hl 3 K.
3 2004-04-12 Ostern
Can I get
2011 Nov 03
1
non-parametric sample size calculation
Hi,
I am trying to estimate the sample size needed for the comparison of two groups on a certain measurement, given some previous data at hand. I find that the data collected does not follow a normal distribution, so I would like to use a non-parametric option for sample size calculation.
I found the pwr package but I don't think it has this option and on the internet found that
2006 Jan 02
0
R] lme X lmer results
From a quick look at the paper in the SAS proceedings, the simulations
seem limited to nested designs. The major problems are with repeated
measures designs where the error structure is not compound symmetric,
which lme4 does not at present handle (unless I have missed something).
Such imbalance as was investigated was not a serious issue, at least for
the Kenward and Roger degree of freedom
2005 Feb 28
0
Re: R-help Digest, Vol 24, Issue 28
You've omitted a comma. races2000 is a data frame,
which for purposes of extracting rows behaves like
a 2-dimenional object. The following works fine:
hills2000 <- races2000[races2000$type == 'hill', ]
Additionally, you might like to ponder
> type <- races2000[names(races2000)=="type"]
> type[1:4]
Error in "[.data.frame"(type, 1:4) :
2001 May 07
2
Symbolic substitution of expressions into expressions
In the following
titletxt <- substitute(paste(tx, tilde(y) == sqrt(y)),
list(tx="Replace y by "))
I'd like to be able to replace e.g. sqrt(y) by a symbol or
symbolic expression that has the effect of inserting sqrt(y)
into the place that it occupies. This would allow me to put an
arbitrary expression into that position. [One can use text() or
mtext() etc. to place titletxt
2004 Nov 10
1
Additions to the datasets package?
I have posted, at http://wwwmaths.anu.edu.au/~john/r/newsets/
image (.rda) files, and first stabs at .Rd files for various data on
deaths in London from 1629 to 1939. (There are of course gaps.)
The sources (Guy 1882 & Stocks 1942) are documented in the
.Rd files:
(1) poxetc: measles, smallpox & total deaths: 1629-1881
[I have deliberately left several inconsistencies that were
in
2002 Jul 09
0
Re: Candid comment
<soap-box>
While I agree with John about abuse of methodology, I can't subscribe to
the "failure to read the manual" proposition.
I don't mean to lecture, but it would seem to me that people who, like me,
will probably gain far more from this list than we will be able to
contribute (at least in the near term) owe it to those who will likely
contribute far more than they