similar to: Making several plots using a loop function

I experienced a Windows Explorer crash in https://lists.samba.org/archive/samba/2019-July/224346.html as well... Try samba-tool ntacl sysvolreset (or check first). Joachim Lindenberg -----Urspr?ngliche Nachricht----- Von: Rowland penny <rpenny at samba.org> Gesendet: Monday, 15 July 2019 10:24 An: samba at lists.samba.org Cc: Jeremy Allison <jra at samba.org> Betreff: Re: [Samba]

Hi alL, I have a data frame with 4 columns: "value", "time", "group" and "id". I would like to plot "value" vs. "time" with different colors for different levels of "group" and different symbols for different values of "id". I think I could do this but I would like to see what is an easier way to plot the

On 15/07/2019 20:20, ?brah?m Gyula wrote: > Hi Joachim, > > I tried to use samba-tool ntacl sysvolreset?command, but the it did > not resolve the problem. > > It it very interesting there are not much reports about this bug. Why? > Is it not a common problem? Especially if it is related to a Windows bug. > This isn't a Samba bug and It isn't related to a Windows

Hi all, The function h below is a function of c and it should be a monotone increasing function since the integrand is nonnegative and integral is taken from c to infinity. However, as we can see from the plot, it is not shown to be monotone. Something wrong with the usage of integrate function? Thanks so much for your help. Hanna h <- function(c){ g <- function(x){pnorm(x-8.8,

Hi all, I have a three dimensional array with the corresponding dimension names. I would like to subset the array according to the dimension names. For example, suppose I want to extract the values corresponding to A=20, B=10, C=0. I know I can do: P2[dimnames(P2)$A==20, dimnames(P2)$B==10, dimnames(P2)$C==0] But is there a better way for doing this? Thanks for your help! Hanna >

Hi Hanna, your function is essentially zero outside a short interval around 9. And the help page states: "If the function is approximately constant (in particular, zero) over nearly all its range it is possible that the result and error estimate may be seriously wrong." You could try to integrate over a finite interval, say (7, 12). G?ran Brostr?m On 2018-02-06 19:40, li li wrote:

I have the joint distribution of three discrete random variables z1, z2 and z3 which is captured by "z" and "prob" as described below. For example, the probability for z1=0.46667, z2=-1 and z3=-1 is 2.752e-13. Also, the probability adds up to 1. > head(z) z1 z2 z3 [1,] -0.46667 -1.0000 -1.0000 [2,] -0.33333 -0.9333 -0.9333 [3,] -0.20000 -0.8667 -0.8667

Hi all, I have a question with regard to making plots using function "scatterplot3d". Please see the example below. It looks like, for y axis, the tickmark text was cutoff. The number "10" does not show up completely. I tried to work with par(mpg). It does not seem to work. Hope to get some advice here. Thanks much! Hanna C <- runif(30) B <- rep(1:3, each=10) A

Sorry. I meant in the previous email that the function h() is a monotone decreasing function. Thanks very much. 2018-02-06 13:32 GMT-05:00 li li <hannah.hlx at gmail.com>: > Hi all, > The function h below is a function of c and it should be a monotone > increasing function since the integrand is nonnegative and integral is > taken from c to infinity. However, as we can see

Dear Community, I would like to make a group mapping between Unix and Windows groups. I have created a group called "Unix System Users" on Windows with Active Diectory User and Computers and I have also created a unix group called systemusers in Raspbian Buster. When a try to execute net groupmap add ntgroup="Unix System Users" unixgroup=systemusers type=d command, the

For a data frame, we can add an additional row or column easily. For example, we can add an additional row of zero and an additional row of column as follows. Is there an easy and similar way to add zeros in each dimension? For example, for array(1:12, dim=c(2,2,3))? Thanks for your help!! Hanna > x <- as.data.frame(matrix(1:20,4,5))> x[5,] <- 0> x[,6] <- 0> x V1 V2

Have you tried P2["20", "10", "0"] ? Jean On Thu, Jun 1, 2017 at 3:10 PM, li li <hannah.hlx at gmail.com> wrote: > Hi all, > I have a three dimensional array with the corresponding dimension names. > I would like to subset the array according to the dimension names. For > example, > suppose I want to extract the values corresponding to A=20,

Dear all, I got an error message when running the following code. Can anyone give any suggestions on fixing this type of error? Thank you very much in advance. Hanna > integrand <- function(x, rho, a, b, z){ + x1 <- x[1] + x2 <- x[2] + Sigma <- matrix(c(1, rho, rho, 1), 2,2) + mu <- rep(0,2) + f <-

Dear all, I want to fit a random effect model with only one random factor. I do not want to include the intercept term either. The model I using now is lmer(values ~ (1|lot), data=tmp) The results are as below. How do I take out the intercept term? Or if this is not possible for the lmer function, is it possible using lme function in the "nlme" package? Thank you very much in

Hi all, Is there a way to change the color of the boxplot plots outliers? Thanks. Hanna [[alternative HTML version deleted]]

Hi all, In my plotCI function, the argument x is chosen to be seq(0.05, 0.95, by=0.05). However, when I make the plot, the plot has the x coordinate goes 1:19. Does anyone know how to make the x coordinate to be (0,0.5, 0.1, ..., 0.95). Thank you. Hanna [[alternative HTML version deleted]]

> On 1 Jun 2017, at 03:41, li li <hannah.hlx at gmail.com> wrote: > > Hi all, > I have a question with regard to making plots using function > "scatterplot3d". > Please see the example below. It looks like, for y axis, the tickmark text > was cutoff. > The number "10" does not show up completely. I tried to work with par(mpg). > It does not

Dear all, The function f() below is a function of m1 and m2, both of which are matrices with 3 rows. The function works sequentially one row after another. So altogether there are three stages. I am trying to update the coding to write a generic function that will work for arbitrary k stages. I am hoping to get some suggestion and help. Thanks so much! Hanna ##x, y are two

Most likely, previous computations have ended up giving slightly different values of say 0.13333. A pragmatic way out is to round to, say, 5 digits before applying unique. In this particular case, it seems like all numbers are multiples of 1/30, so another idea could be to multiply by 30, round, and divide by 30. -pd > On 28 Jul 2017, at 17:17 , li li <hannah.hlx at gmail.com> wrote:

Mostly modelled after a snippet implemented in dib, it is an helper function to run multiple commands in parallel, waiting for all of them at once, and returning all their exit codes. It is possible to pass custom descriptors for collecting stdout and stderr of each command. Common_utils.run_command is adapted to use few helper methods used by run_commands, so all the existing code using it