similar to: multiple pages with ggplot2 possible?

Suppose I have a list of logicals, such as returned by lapply: Theoph$Dose[1] <- NA Theoph$Time[2] <- NA Theoph$conc[3] <- NA lapply(Theoph,is.na) Is there a direct way to execute logical "or" across all vectors? The following gives the desired result, but seems unnecessarily complex. as.logical(apply(do.call("rbind",lapply(Theoph,is.na)),2,"sum"))

library(ggplot2) a<- read.table("data", header=T) b = na.omit(a) ggplot(data=b) + geom_line(aes(x=timepoint, y=value,group=sample, colour= factor(sample))) +? geom_point(aes(x=timepoint, y=value, group=s ample)) + facet_wrap(~bio, scales = "free",ncol = 5) +theme_bw() + opts(legend.direction = "horizontal",??? legend.position = "top",????

Hi, everyone, Try the following command to see if you get TRUE or FALSE. I get FALSE on a unix platform but TRUE on Windows. Any comment? all(paste(Theoph[1],Theoph[2])==paste(Theoph[[1]],Theoph[[2]])) -- Jun Shen PhD PK/PD Scientist BioPharma Services Millipore Corporation 15 Research Park Dr. St Charles, MO 63304 Direct: 636-720-1589 [[alternative HTML version deleted]]

Dear all, I tried to create a groupedData object, where the grouping factor is not ordered. Here ist the code: library(nlme) test<-groupedData(conc~Time|Subject,order.groups=F,data=as.data.frame(Theoph)) > getGroups(test) Levels: 6 < 7 < 8 < 11 < 3 < 2 < 4 < 9 < 12 < 10 < 1 < 5 I still get an ordered factor. As always thanks for your help peter

-Thank you James, well the problem of my type of data is that there can be many possible subsets and therefore plots, and I want to automatically generate them, and facet_wrap does not give me all the possible cases On Saturday, April 16, 2016 6:01 AM, James C. Whanger <james.whanger at gmail.com> wrote: Would facet_wrap or facet_grid give you what you want? On Sat, Apr 16, 2016 at

Dear all I have a problem when I make a trellis plot - I would like to reduce the white margin surrounding the plot. I used S some years age, as I remember it was possible to use the "par" and "oma" to control margin size even on a trelllis plot (see the plot below). However, it does not seem to work in R. All suggestions will be highly appreciated. Br Henrik

Dear all, I am trying to gain some experience with the function gnls from the nlme package. I tried to model the Theophyline data by trying to model the presumed dependency of the clearance on the body weight. This is my function call of gnls: gnls(conc~SSfol(Dose,Time,lKe,lKa,lCl),data=Theoph, params=list(lKe~1,lKa~1,lCl~Wt),start=c(-2.4,0.46,-3.22,0.01)) That's been the result: Error

I currently use lattice functions to produce multiple pages of plots using the "layout" argument to specify the number of rows and columns of panels, e.g., xyplot(price ~ carat | clarity, diamonds, layout = c(2, 2)) This results in 2 pages of 4 panels each. "diamonds" is a data.frame distributed with ggplot2. I would like to do the same with ggplot2 but have been

Dear all, In a plot command like xyplot(Y~X|ID*PERIOD,data=...) xyplot will generate all the possible ID*PERIOD combinations. But not all of them have data in there. So I have a lot of empty plots. How can I suppress those empty plots and ask xyplot only to generate plots actually with data. Thanks. Jun [[alternative HTML version deleted]]

Hello, I am drawing some data with ggplot2 and would like to reverse the order of the y axis and set a custom range for it. I can do the former but when I add the key `limits` to `scale_y_reverse` I get an error as shows below and, worse, no data shown in the plot. How can I properly set a reverse y scale with a defined range in ggplot2? Thank you ``` A <- rep(c(0, 3, 6, 12, 24), 3) B <-

On 05/03/2024 7:16 a.m., Luigi Marongiu wrote: > A <- rep(c(0, 3, 6, 12, 24), 3) > B <- c(rep(0,5), rep(1,5), rep(2,5)) > V <- c(27.5, 27.01, 27.75, 27.98, 27.4, 25.69, > 26.17, 27.78, 26.08, > 24.97, 23.18, 21.78, 22.49, 21.85, 22.2) > df <- data.frame(Conc = A, Time = B, Value = V) > df$Conc = as.factor(df$Conc) >

Dear list, I want to show all the objects starting with "d" and ending with a digit. How do I specify these conditions in the pattern argument I can do one condition but not two ls(pattern='^d') ls(pattern='[[:digit:]]$') are working. But, ls(pattern='^d'&'[[:digit:]]$') is not working. Appreciate any comment. Jun Shen [[alternative HTML

Hello R users and Hadley, Back again with a little problem in ggplot2 =o) (ggplot 0.8.1, R 2.8.0) Here the problem : library(ggplot2) df <- data.frame(id = 1:100, x1 = c(rnorm(50), rnorm(50, 1)), x2 = c(rnorm(50), rnorm(50, 1.5)), x3 = c(rnorm(50, 0.5), rnorm(50, 2.5)), group = as.factor(rep(c("a", "b"), each = 50))) df.melt <- melt(df, id = c("id",

Hi, I have a data set (mydata), which a part of this is like the following: 'data.frame': 36190 obs. of 16 variables: $ RE : int 38 41 11 67 30 18 38 41 41 30 ... $ LU : int 4200 3330 530 4500 3000 1790 4700 3400 3640 4000 ... $ COUNTRY : Factor w/ 4 levels "DE","FR","JP", "FR"? $Light

I have a matrix like this Name 1 2 3 4 5 NM_001039514 1.033557047 0.7469879518 0.9004524887 0.8613861386 0.7952499048 NM_001039723 1.0759493671 1.2315789474 0.8666666667 1.1142857143 0.9428011471 NM_001042605 0.9897435897 0.8870431894

Hi R users, I need to create more than 20 figures (one for each group) in one page. I have a common legend for 20 figures using the facet_wrap. However the range of the values among the groups are very wide. For example one group has the value of 0 to 3, but the values of some of the groups has ranged from 0 to 20 so that when I used a single common legend for all 20 figures, I could not display

Hi all, This seems like a basic problem, but no amount of playing with the code has solved it. I have a time-series data set like that shown below (only longer) and am seeking to plot the data with filled, circular points and error bars. I would like the error bars to be behind the points otherwise they tend to obscure the points (especially when I have a lot of points in the actual data set).

Suppose that I'm working on Hadley's diamond dataset and I want to review the relationship between price, colour and carat. I might run the following: library(ggplot2) #plot scatter and add some hex binning q<-qplot(carat,price,data=diamonds, geom=c("hex"), main="Variability of Diamond Prices by Carat and Colour") #facet to get one scatter for

Hi R Users, I tried to increase the legend height in ggplot2, but it did not respond at all using the follwoing code. Do you have any suggestions for me? dat<-data.frame(temperature) P1<-ggplot(dat, aes(X, Y)) Scenario1<-P1+geom_point(aes(colour = value), size = 1)+ theme_bw()+ theme(axis.text.x = element_blank(),axis.text.y = element_blank())

Hi Michael, I am trying the solution you've suggested below: DAT <- data.frame(x = runif(1000, 0, 20), y = rnorm(1000)) DAT$xbin <- with(DAT, cut(x, seq(0, 20, 2))) p <- ggplot(DAT, aes(x = x, y = y)) + geom_point(alpha = 0.2) + stat_quantile(aes(colour = ..quantile..), quantiles = seq(0.05, 0.95, by=0.05)) + facet_wrap(~ xbin, scales = "free") print(p)