Displaying 20 results from an estimated 2000 matches similar to: "Implementing Samba 4 in multi site environment"
2008 Sep 18
2
graphing netCDF files
Hello
I'm working with a large hydrological data set stored in a netCDF format.
The file stores x and y coordinates in the UTM projected coordinate system,
yet when I use image to graphically display the z variable, the image is
distorted in the sense that it does not plot the map in the correct spatial
organization.
I'm wondering if I need to define the projection of the netCDF file
2014 Jan 21
1
DNS Setup
hii guys
i have some issue with dns in samba 4
i have install and setup 2 samba dc in different Site
site2 dc joint to site1 dc, with internal dns
topology :
site1 --- openvpn server --- firewall --- wan --- openvpn client --- site2
192.168.1.0/24
192.168.2.0/24
in site1 i have some application let say
email server: mail.local.lan > 192.168.1.2
web server : web.local.lan > 192.168.1.3
2012 Apr 18
2
quarter end dates between two date strings
Hello,
I have two date strings, say "1972-06-30" and "2012-01-31", and I'd like to
get every quarter period end date between those dates? Does anyone know how
to do this? Speed is important...
Here is a small sample:
Two dates:
"2007-01-31"
"2012-01-31"
And I'd like to get this:
[1] "2007-03-31" "2007-06-30"
2008 Jun 05
7
Improving data processing efficiency
Hi everyone!
I have a question about data processing efficiency.
My data are as follows: I have a data set on quarterly institutional
ownership of equities; some of them have had recent IPOs, some have not
(I have a binary flag set). The total dataset size is 700k+ rows.
My goal is this: For every quarter since issue for each IPO, I need to
find a "matched" firm in the same
2008 Jan 23
3
How to do more advanced cross tabulation in R?
Hi,
I am trying to reproduce some functionalities of Excel pivot table in R,
sadly, I couldn't figure out how to do it. I am wondering if this is even
possible in R. Does anyone know?
Here is an example:
year=rep(2003,16)
quarter=rep(1:4,each=4)
sales=1:16
company=rep(c("a","b","c","d"),4)
df=data.frame(year,quarter,sales,company) #this is the
2017 Aug 15
3
Trust Relationship between this work station and primary domain failed
Hai,
Was this pc a member of any NT4 Domain in the past?
You can try the following.
Login as a Local Administrator on the pc. ( you may need to create one first. )
Open PowerShell as administrator ( you need powershell 3.0 for this )
Run:
Reset-ComputerMachinePassword -Server AD_DC.DOMAIN.TLD -Credential YOUR_AD_DOM\Adminstrator
Restart-Computer
No powershell V3.
netdom.exe resetpwd
2017 Aug 15
5
Trust Relationship between this work station and primary domain failed
hi all
i still struggling for the last 2 month to figure out what happen with my
samba 4 AD server Installation
almost all my client mostly win 7 and 10 having same problem with trust
relationship
i have check the time on PC client all fine ..but the trust relationship
problem still happen
here is my samba server conf
*# Global parameters[global]
2010 Jan 16
3
Comparing dates in dataframes
I have two data frames. One (arr) has all arrivals to an airport for a
year, and the other (gw) has the dates and quarter hour of the day when
the weather is good. arr has a Date and quarter hour column.
>names(arr)
[1] "Date" "weekday" "hour" "month" "minute"
[6] "quarter" "ICAO"
2007 Jul 25
3
aggregate.ts
Consider the following scrap of code:
> x<- ts(1:50,start=c(1,11),freq=12)
> y <- aggregate(x,nfreq=4)
> c(y)
[1] 6 15 24 33 42 51 60 69 78 87 96 105 114 123 132 141
> y
Error in rep.int("", start.pad) : invalid number of copies in rep.int()
> tsp(y)
[1] 1.833333 5.583333 4.000000
So we can aggregate into quarters, but we cannot print it using
2007 Jul 25
3
aggregate.ts
Consider the following scrap of code:
> x<- ts(1:50,start=c(1,11),freq=12)
> y <- aggregate(x,nfreq=4)
> c(y)
[1] 6 15 24 33 42 51 60 69 78 87 96 105 114 123 132 141
> y
Error in rep.int("", start.pad) : invalid number of copies in rep.int()
> tsp(y)
[1] 1.833333 5.583333 4.000000
So we can aggregate into quarters, but we cannot print it using
2006 Jan 25
2
Question about Aggregate
hello,
Suppose you a monthly series you want to aggregate at a quaterly frequency
with the start and the end of your series in the middle of the quarter.
For example
2001M2 2001M3 2001M4 2001M5 2001M6 2001M7
12 13 12 14 16 15
how can you get something like :
2001Q1 2001Q2 200Q3
NA 14 NA
or
2001Q1 2001Q2 200Q3
12.5 14 15
Thanks in advance
2014 Aug 25
2
Samba4 Internal DNS Problem : Suddently Dns Crash
hii all
i have some issue with my samba 4 installation,
i use samba 4.1.3, suddenty my dns stop working and i try to restart the
service but nothing good happen
i check on samba log i found this
Aug 25 21:15:39 pdc samba[6605]: [2014/08/25 21:15:39.206091, 0]
../lib/util/fault.c:72(fault_report)
Aug 25 21:15:39 pdc samba[6605]:
===============================================================
2017 Aug 15
4
Fwd: Re: Trust Relationship between this work station and primary domain failed
On Tue, 15 Aug 2017 20:52:12 +0700
zhia chandra via samba <samba at lists.samba.org> wrote:
> hai belle
>
> Was this pc a member of any NT4 Domain in the past? nope ..
>
> but actually our samba4 server was upgrated from samba3 base on
> clearOS 5 ..
>
> and actually i still running samba3 in stand alone mode for netbios
> only, incase some PC cannot map /
2014 Jul 16
1
samba4 replication issue : outbound neighbour
hi all
i have some issues with my samba4 installation
here is the case
1. i have about 1 dc in my head office as a PDC and 9 dcs in 9
different site office
2. each site office connected to head office by VPN, but each site
office cant connect each other
3. each site and head office have a different network
4. i user samba 4.1.3
5. i put all dc in same site , because i think samba 4.1.* has
2008 Jun 06
6
Subsetting to unique values
I want to take the first row of each unique ID value from a data frame.
For instance
> ddTable <-
data.frame(Id=c(1,1,2,2),name=c("Paul","Joe","Bob","Larry"))
I want a dataset that is
Id Name
1 Paul
2 Bob
> unique(ddTable)
Will give me all 4 rows, and
> unique(ddTable$Id)
Will give me c(1,2), but not accompanied by the name column.
2013 Nov 22
2
issue on upgrade samba 3 to samba 4
hii all
i think i have finished trial to upgrade my samba 3 pdc server base on
clearos 5.2 into new samba 4.1.1 in new machine and different network
but then i realized when i check my user with samba-tool, i cant find any
of my samba 3 user account, all i find is
[root at pdcs4 ~]# samba-tool user list
Administrator
dns-pdc
krbtgt
Guest
has anyone got same problem with me ?
how to overcome it
2016 Aug 08
3
BIND as DNS Slave of SAMBA 4 Internal DNS and Windows 2008
hi guys
i need some advice for my case that i faced here..
i have Two AD with two different domain, platform and network :
i expect all user in different domain can resolve the other domain dns
let say
1. domainwin.com >> windows 2008 AD >> 172.16.1.2
2. domainnux.com >> Samba 4 AD >> 172.16.2.2
is it possible if i create 1 new BIND DNS Server in 172.16.3.2
2003 Apr 30
3
How to put 2 or more graphics in the same page ?
Hi,
I have a naive question...
I have produced about 60 graphics and want to put them in one postscipt
file , possibly 4 graphics on each page. I can put all of them in the
same file (that's ok), but I can't find the way to put 2 or more
(precisely 4, in my case) graphics on the same page (each graphics is
about 6 inches (width) X 4 inches (height)).
Any help would be very much
2008 May 31
1
Representing 'Date' as 'Year - Quarter'
I have financial data on a a set of firms, with a quarterly period
(fundamental data). The data spans 10 years, and four quarters per
year. The present file (.csv) reads the Date columns as "200706" for
the second quarter of 2007; "199809" for the third quarter of 1997.
Is there a way I can convert it to something like "2007 Q2", "1998 Q3"?
I am aware of
2006 Jan 18
3
Possible improvement in lm
Folks,
I do a series of regressions (one for each quarter in the dataset) and
then go and extract the residuals from each stored lm object that is
returned as follows:
vResiduals <- as.vector(unlist(resid(lQuarterlyRegressions[[i]])));
Here lQuarterlyRegressions is a vector of objects returned by lm().
Next, I may go find outliers using identify() on a plot or do some
other analysis which