similar to: sortables and accept question

Displaying 20 results from an estimated 100 matches similar to: "sortables and accept question"

2010 Feb 26
3
Preserving lists in a function
Dear R users, A co-worker and I are writing a function to facilitate graph plotting in R. The function makes use of a lot of lists in its defaults. However, we discovered that R does not necessarily preserve the defaults if we were to input them in the form of list() when initializing the function. For example, if you feed the function codes below into R: myfunction=function( list1=list
2004 Jun 02
1
How to iterate through two objects of class "list" fast?
Hi! I have 2 list objects One list contains the data (list1) the second list2 contains the e.g linear model for each element of list 1. list2 <- lapply(list1,mylm,response) I obtain list 2 by something like this. now I have a function myfunc which takes an element from list1 and the coresponding element from list2 does something and .... list3[[x]] <- myfunc(list1[[x]],list2[[x]]) Until
2011 Feb 08
2
Extrcat selected rows from a list
Hi, I have two lists 1) List1- 30,000 rows and 104 columns 2) List2- a list of 14000 selected rownames  from List 1 Now, I want to extract all the 104 columns of List1  matching with the 14000 selected rownames from List2.  Psedocode will be something like this: match rownames(List2) with rownames(List1) extract selected matched 104 coloumns from (List1) strore in-> List3 So the
2009 Oct 12
1
Creating object referant from argument name
Hi all. I'd like to define an object within a function based on an argument to that function. Specifically, I've got: do.something<-function(input){ id<-substring(input,3,3) j<-list1 if(id==2)j<-list2 if(id==3)j<-list3 if(id==4)j<-list4 ...} Instead of all these if() arguments, I was hoping to use something like:
2005 Jul 21
1
again, a question between R and C++
Dear R Users, I want to make a call from R into C++. My inputs are List1, List2, List3, IntegerID. The amount of elements of the lists and their type depend on IntegerID. Typical elements of a given list can be vectors, doubles, and even other lists. I want to return also a list (whose nature will depend also, possibly, on IntegerID). What I want to do is to call these 4 inputs from C++ and then
2002 Oct 14
1
Question: concatenating lists
Dear R users, I have the following problem. I have a number of lists with identical structure. Each component is a vector, matrix or array, but components of different lists may be of different size. How do I combine the lists to get a new list such that each component of this list contains the components of the individual lists? An example may explain most clearly what I need. Suppose I have
2014 Mar 06
1
Create dataframe in C from table and return to R
Hi , I am trying to create a dataframe in C and sebd it back to R. Can anyone point me to the part of the source code where it is doing , let me explain the problem I am having . -------------------------------------------------------------------- My simple implementation is like this SEXP formDF() { SEXP dfm ,df , dfint , dfStr,lsnm; char *ab[3] =
2007 May 16
2
substitute "x" for "pattern" in a list, while preservign list "structure". lapply, gsub, list...?
I am experimenting with some of the common r functions. I had a question re:using "gsub" (or some similar functions) on the contents of a list. I want to design a function that looks at "everything" contained din a list, and anytime it finds the text string "pattern" replace it with "x". I also wish to preserve the "structure" of the original
2004 Feb 04
5
Date Time Conversion problems...
At one time (version 1.7), the code below used to work for converting and extracting based on the Date Time. In version 1.8.1, something changed I know, but I cannot for the life of me figure out what... Data: UserName,RequestDate,PO,OrderDate,ExpDelivDate,Vendor,Total "Woody, Jim",12/19/2002,AP15063,1/7/2003,2/10/2003,Ames ,8570 "Harrold,
2009 Apr 15
6
Intersection of two sets of intervals
Hi, Algorithm question: I have two sets of "intervals", where an interval is an ordered pair [a,b] of two numbers. Is there an efficient way in R to generate the intersection of two lists of same? For concreteness: I'm representing a set of intervals with a data.frame: > list1 = as.data.frame(list(open=c(1,5), close=c(2,10))) > list1 open close 1 1 2 2 5
2012 Nov 20
1
tcl/tk problem with tklistbox,the " " character and Rcmdr.
I everyone, i have a little problem with tklistbox,the " " character and Rcmdr. Please look at this code require(tcltk) tt<-tktoplevel() levels.list2 <-tklistbox(tt,selectmode="multiple",exportselection="FALSE", height=4, yscrollcommand=function(...)tkset(levels.list2.scroll,...))
2012 Oct 10
7
multiple t-tests across similar variable names
Hi everyone- I have a dataset with multiple "pre" and "post" variables I want to compare. The variables are named "apple_pre" or "pre_banana" with the corresponding post variables named "apple_post" or "post_banana". The variables are in no particular order. apple_pre orange_pre orange_post pre_banana apple_post post_banana person_1
2010 Mar 15
1
rbind, data.frame, classes
Hi, This has bugged me for a bit. First question is how to keep classes with rbind, and second question is how to properly return vecotrs instead of lists after turning an rbind of lists into a data.frame list1=list(a=2, b=as.Date("20090102", format="%Y%m%d")) list2=list(a=2, b=as.Date("20090102", format="%Y%m%d")) rbind(list1, list2) #this loses the
2004 Oct 25
1
usage and behavior of 'setIs'
Hello, am I using 'setIs' in the correct way in the subsequent (artifical) example? Do I have to specify explicit 'setAs' for 'list' and 'vector' or should this work automatically, since "getClass("List1")" states an explicit coerce also for these classes. I'm working with R 2.0.0 Patched (2004-10-06) on windows 2000. Thanks for your
2011 May 05
1
lapply, if statement and concatenating to a list
Hi R users I was wondering on how to use lapply & co when the applied function has a conditional statement and the output is a 'growing' object. See example below: list1 <- list('A','B','C') list2 <- c() myfun <- function(x,list2) { one_elem <- x cat('one_elem= ', one_elem, '\n') random <- sample(1:2,1) show(random)
2011 Nov 21
1
Creating a list from all combinations of two lists
R-helpers: Say I have two lists of arbitrary elements, e.g.: list1=list(c(1:3),"R is fun!",c(3:6)) list2=list(c(10:5),c(5:3),c(13,5),"I am so confused") I would like to produce a single new list that is composed of all combinations of the "top level" of list1 and list2, e.g.: listcombo=list(list(list1[[1]],list2[[1]]),list(list1[[1]],list2[[2]]
2006 Mar 03
13
Listing help
Hi, I''ve created a Rails application and am having a problem listing by a particular category in an associated table. I followed the instructions found at the O''Reilly tutorial (http://www.onlamp.com/pub/a/onlamp/2005/03/03/rails.html?page=3) but have not had success. Can anyone please outline a better set of instructions than in the "Showing Recipes in a
2012 Jul 05
2
vector entry in matix
hi, i'm trying to figure out if there's any possibility to write a whole vector into a matrix or data.frame or something like that. i don't mean transormation. Here an example: [,1] [,2] [1,] "a" "d" [2,] "b" "e" [3,] "c" "f" where e.g. a is a<-c(0,1) vector of length 2, b a vector of length 4,... (i know that
2012 Apr 19
1
question about lists
I am new to R, and I have been running into the following situation when I mistype a variable name in some code: > list1 <- list( a=1, b=2 ) > list2 <- list( a=1 ) > list2$b <- list1$c > list2 $a [1] 1 I would think at the point where I am trying to reference a field called "c" -- that does not exist -- in list1, there would be an error flagged. Instead, list1$c
2011 Feb 06
1
Applying 'cbind/rbind' among different list object
Hi, I am wondering whether we can apply 'cbind/rbind' on many **equivalent** list objects. For example please consider following: > list1 <- list2 <- vector("list", length=2); names(list1) <- names(list2) <- c("a", "b") > list1[[1]] <- matrix(1:25, 5) > list1[[2]] <- matrix(2:26, 5) > list2[[1]] <- 10:14 > list2[[2]] <-