similar to: Subseting a data.frame

Dear R forum, The example below is just an indicative one and I have constructed it. My real life data and conditions are different. I have a data.frame as given below mydat = data.frame(A = c(19, 20, 19, 19, 19, 18, 16, 18, 19, 20), B = c(19, 20, 20, 19, 20, 18, 19, 18, 17, 16)) if (length(mydat$A) > 10) { stop("A has length more than 10") }else if (max(mydat$B) > 18) {

Dear R helpers, I have following data.frame giving asset class (i.e. bank, corporate, sovereign etc. as there could be number of classes) and rating-wise default frequency. I need to plot graphs for each of these classes i.e. bank, corporate and sovereign where I will be plotting ratings (AAA, AA, etc) on the x-axis and their respective default probabilities on Y-axis. I have tried to write a

Dear R forum Suppose I have a data.frame df = data.frame(id = c(1:6), x = c(15, 21, 14, 21, 14, 38), y = c(36, 38, 55, 11, 5, 18), x.1 = c(15, 21, 14, 21, 14, 38), z = c("D", "B", "A", "F", "H", "P")) > df   id  x  y    x.1 z 1  1 15 36  15 D 2  2 21 38  21 B 3  3 14 55  14 A 4  4 21 11  21 F 5  5 14  5  14 H 6  6 38 18  38 P

Dear R forum I have a data.frame df = data.frame(currency_type = c("EURO_o_n", "EURO_o_n", "EURO_1w", "EURO_1w", "USD_o_n", "USD_o_n", "USD_1w", "USD_1w"), rates = c(0.47, 0.475, 0.461, 0.464, 1.21, 1.19, 1.41, 1.43))   currency_type     rates 1      EURO_o_n   0.470 2      EURO_o_n   0.475 3       EURO_1w   0.461

Dear R forum I have one stupid question, but I have no other solution to it in sight? Suppose some R process creates graphs etc alongwith main output as data.frame e.g output1 = data.frame(bands = c("A", "B", "C"), results = c(74, 108,  65)) I normally save this output as some csv file. But I need to save this output as some image (I understand this is weird,

Dear R forum I have a following vector of random no.s x = runif(100, 0.01, 0.99)  [1] 0.47212037 0.77867992 0.33947474 0.93369035   [5] 0.03720073 0.79307831 0.81801835 0.92710688 ................................................. I need to count the random no. falling in the range (0 - 0.10), (0.10 - 0.20), (0.20 - 0.30)..upto (0.90 - 1) Thus, I need to have a data frame as

Dear R forum, (Pl note this is not a finance problem) I have two data.frames as currency_df = data.frame(current_date = c("3/4/2013", "3/4/2013", "3/4/2013", "3/4/2013"), issue_date = c("27/11/2012", "9/12/2012", "14/01/2013", "28/02/2013"), maturity_date = c("27/04/2013", "3/5/2013",

Dear R forum, I have a data.frame as defied below - df = data.frame(names = c("C", "A", "A", "B", "C", "B", "A", "B", "C"), dates = c("4/15/2013", "4/13/2013", "4/15/2013", "4/13/2013", "4/13/2013", "4/15/2013", "4/14/2013",

Dear R forum I have a data.frame df = data.frame(dates = c("4/15/2013", "4/14/2013", "4/13/2013", "4/12/2013"), values = c(47, 38, 56, 92)) I need to to create a vector by repeating the dates as "Current_date", 4/15/2013, 4/14/2013, 4/13/2013, 4/12/2013,  "Current_date", 4/15/2013, 4/14/2013, 4/13/2013, 4/12/2013, Current_date,

Dear R Forum, I have a data.frame as df = data.frame(date = c("2013-04-15", "2013-04-14", "2013-04-13", "2013-04-12", "2013-04-11"), ABC_f = c(62.80739769,81.04525895,84.65712455,12.78237251,57.61345256), LMN_d = c(21.16794336,54.6580401,63.8923307,87.59880367,87.07693716), XYZ_p = c(55.8885464,94.1358684,84.0089114,98.99746696,64.71083712),

Dear R forum I have a vector say as given below df = c("F", "C", "F", "B", "D", "A", "D", "D", "A", "F", "D", "F", "B",    "C") I need to find (1) how many times each element occurs? e.g. in above vector F occurs 4 times, C occurs 2 times etc. (2)

Dear R forum I have a data.frame as cashflow_df = data.frame(instrument = c("ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC", "ABC", "PQR", "PQR",

Dear R helpers, Everyday I do receive many many mails from R forum and after some period of times, INBOX is filled with numerous mails. At times if for some period of time, I haven't accessed mails, it becomes difficult to keep track of mails and many times simply due to the volume (and owing to the lack of time due to office constraints), I have to simply delete the mails without opening

Dear R forum I have data.frame as df = data.frame(rate_name = c("USD_1w", "USD_1w", "USD_1w", "USD_1w", "USD_1m", "USD_1m", "USD_1m", "USD_1m", "USD_2m", "USD_2m", "USD_2m", "USD_2m",  "GBP_1w", "GBP_1w", "GBP_1w", "GBP_1w",

I have two issues. 1-I am trying to use morphology to identify gender. I have 9 variables, both continuous and categorical. I was using two-step cluster analysis in SPSS because two-step could deal with different types of variables. But the output tells me that an animal is in cluster 1 or 2, it does not give me a probability (ex. 0.70 cluster 2). I also did not want to specify that I want two

Dear R helpers, Last week Mr. Ista Zahn has taken lots of efforts and helped me with the following code generating basel_asset_wise (e.g. bank, corporate, sovereign) graphs. The code works excellently and assetwise grahs are aslo genereated. I have tried to customize the code as per my need. However, there is only one small problem with the graphs. The graph doesn't give me the asset names.

Hello Dear R community,  This is my problem.  I have a data set (dataframe) called "mydat". It consist of 3 numerical variable.  They are Centrecode, FSUSN and Round. I want to create unique ID by combining these 3 variables. Follwing commands gives me what I need. mydat1 <- paste(mydat$Centrecode, mydat$FSUSN,mydat$Round,sep="") newds <- data.frame(mydat1)    For a

Dear all, I have got two vectors coding for a stimulus presented in the current trial (mydat$Stimulus) and a prediction in the same trial (mydat$Prediciton), respectively. By applying an if-conditional I want to create a new vector that indicates if there is a match between both vectors in the same trial. That is, if the prediction equals the stimulus. When I pick out some trials randomly, I get

Thank you Jim, I read the data as you suggested but I could not find K1 in col1. rbind(preval,mydat) Col1 Col2 col3 1 <NA> <NA> <NA> 2 X1 <NA> <NA> 3 Y1 <NA> <NA> 4 K2 <NA> <NA> 5 W1 <NA> <NA> 6 Z1 K1 K2 7 Z2 <NA> <NA> 8 Z3 X1 <NA> 9 Z4 Y1 W1 On Sat, Feb 24, 2018 at 6:18 PM, Jim

Hi Val, My fault - I assumed that the NA would be first in the result produced by "unique": mydat <- read.table(textConnection("Col1 Col2 col3 Z1 K1 K2 Z2 NA NA Z3 X1 NA Z4 Y1 W1"),header = TRUE,stringsAsFactors=FALSE) val23<-unique(unlist(mydat[,c("Col2","col3")])) napos<-which(is.na(val23)) preval<-data.frame(Col1=val23[-napos],