similar to: Problem with lapply

Dear R helpers, I have some difficulties in using ''break'' function with loop, and the followings are my script. What I try to do is (1) permute ''or'' first; (2) doing t-test if this ''or'' pass criteria 1 (k=1); (3) end the loop when I get 10 permutations; (4) redo everything again but this time use criteria 2 (k=2) (I have more criteria 1:n).

Hi,there, I am using R package "boot" to bootstrap. I have one question here: does anybody possibly know how the boot package generates the "indices" which is used in the statistic function? I thought "indices = sample(data, replace=TRUE)", but when I replaced "indices" with this command and used "boot", I got different results. Specifically,

#I wish to create a "list of three dataframes" ("results2") from a "list of two dataframes" (temp) and a dataframe ("c")? #Please advise. a <- data.frame(x=c(1,2,3),y=c(5,7,9)) b <- data.frame(x=c(2,4,7,9),y=c(2,3,5,4)) c <- data.frame(x=c(22,34,7,9),y=c(52,63,5,4)) results1 <- list(a,b,c) #what I want #but this is how I need to get there

Dear R-SIG-Debian, I am using R version 3.1.2 with rstudio-server 0.98.113 on debian build 3.2.0-4-amd64 #1 SMP Debian 3.2.68-1+deb7u1 x86_64 GNU/Linux. I often use the %dopar% operator in from the foreach package to run code in parallel. However, the only other use on the box seemingly installed a few items and suddenly %dopar% will use far more than the number of cores I am specifying and

Hi, this is more a general statistics question I think. I am working on a system which automatically answers user questions (such systems are commonly called "Question Answering systems"). I evaluated different versions of the same system on a publicly available test set. This set contains 500 question. Naturally, for each question the answer can be wrong or right, which is coded as

I am calculating the mean of each column grouped by the variable 'id'. I do this using aggregate, data.table, and plyr. My aggregate results do not match the other two, and I am trying to figure out what is incorrect with my syntax. Any suggestions? Thanks. Here is the data. myData <- structure(list(var1 = c(31.59, 32.21, 31.78, 31.34, 31.61, 31.61, 30.59, 30.84, 30.98, 30.79, 30.79,

Suppose we have files in one folder file1.bin, file2.bin, ... , and 1460slice(file) with dim of 720 * 360 in directory C:\\PHD\\Climate Data\\Wind\\ and we want to read them and make a loop to go from 1 to 4 and take the average, then from 4 to 8 and so on till 1460. in the end we will get 365 files . I need those 365 files to be in one new folder for later use in my model I tried using this

Hi, I've got the following code which seems to work fine for a single file if I specify the file name explicitly in the code. What I need to do is run it on all the files in the directory tested and augment the data frame I'm building to have more results columns.How can I do that? Here's the code: library(chron) # .Holidays / is.holiday / is.weekend TStoDate = function

Hello, I have a ferret index with 2 fields: Acts_as_ferret :fields => [:client, :content] If I do model.find_by_contents(query) I obtain all results by the query but I would like to obtain 3 results for each client. Any ideas? Thanks for all. -- Posted via http://www.ruby-forum.com/.

Martyn, you write > I don't think restart() is necessary - it just seems like an invitation to > bad programming to me. It's needed when comparing, say, the time to convergence (if at all) of various iterative processes, for each of a few hundred simulated values. For example one wants basically function(data){ summary<-rep(NA,1000) for(i in 1:1000){

https://bugzilla.mindrot.org/show_bug.cgi?id=1993 alex at testcore.net changed: What |Removed |Added ---------------------------------------------------------------------------- CC| |alex at testcore.net Version|5.9p1 |6.2p1 --- Comment #1 from alex at testcore.net --- Also