similar to: Subtracting elements of a vector from each other stepwise

Dear R forum I have a data.frame as cashflow_df = data.frame(instrument = c("ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC","ABC", "ABC", "PQR", "PQR",

Add more vDPA callbacks. [s/g]et_vq_state is added in patch 1, including a new control mechanism to read data from the DPU. suspend is added in patch 2. Alvaro Karsz (2): vdpa/snet: support getting and setting VQ state vdpa/snet: support the suspend vDPA callback drivers/vdpa/solidrun/Makefile | 1 + drivers/vdpa/solidrun/snet_ctrl.c | 324 +++++++++++++++++++++++++++++

Add more vDPA callbacks. [s/g]et_vq_state is added in patch 1, including a new control mechanism to read data from the DPU. suspend is added in patch 2. Alvaro Karsz (2): vdpa/snet: support getting and setting VQ state vdpa/snet: support the suspend vDPA callback drivers/vdpa/solidrun/Makefile | 1 + drivers/vdpa/solidrun/snet_ctrl.c | 324 +++++++++++++++++++++++++++++

The callback sends a resume command to the DPU through the control mechanism. Signed-off-by: Alvaro Karsz <alvaro.karsz at solid-run.com> --- drivers/vdpa/solidrun/snet_ctrl.c | 6 ++++++ drivers/vdpa/solidrun/snet_main.c | 15 +++++++++++++++ drivers/vdpa/solidrun/snet_vdpa.h | 1 + 3 files changed, 22 insertions(+) diff --git a/drivers/vdpa/solidrun/snet_ctrl.c

Dear R helpers I have a dataframe as df = data.frame(x = c(1, 14, 3, 21, 11), y = c(102, 500, 40, 101, 189)) > df    x   y 1  1 102 2 14 500 3  3  40 4 21 101 5 11 189 # Actually I am having dataframe having multiple columns. I am just giving an example. I need to subtract all the rows of df by the first row of df i.e. I need to subtract each element of 'x' column by 1. Likewise I

I am working on a gene expression microarray dataset, each sample has been taking from animal A and animal B on the same type of microarray. I would like to take the mean of these columns and create a dataset with columns with data which are means of the corresponding rows of A and B For example: TissueExpressionA <- HTissue[1:22284, c(29, 39, 57, 59, 63, 69, 71, 73, 77, 79, 83, 89, 99, 117,

Hi, I am calling in some data into R via the read.table function. The 'tail' of this data reads > tail(data) Date Open High Low Close Volume 3728 Fri 14-Sep-07 114.19 114.46 113.93 114.08 1117992 3729 Mon 17-Sep-07 113.99 114.37 113.91 114.27 899671 3730 Tue 18-Sep-07 114.30 114.32 113.47 113.85 1346282 3731 Wed 19-Sep-07 113.71 113.71

Afternoon- I am trying to subtract a matrix, basically a vector of 28 values, each by the same number to account for differences in regression fitting. I am taking the 1x28 and minus it by the mean value of the matrix, each number. The result I receive is a 1X29 matrix. Does anyone know why the result has an extra value? > lffeb_march [1] 6.588926 7.663877 6.917706 6.824374 7.029973

Hi, I'm a student doing my masters thesis and trying to work with S-Net version 1.0 (tool used for statistical analysis and visualizations of internet traffic) that is written in R. The problem is this: I have a perl script calling a function defined in an R script that is located in a directly different from where the perl script is. This gives the following error. >>> echo

Hi Jason, > > + /* Overwrite the control register with the new buffer size (in 4B words) */ > > + snet_write_ctrl(regs, buf_words); > > + /* Use a memory barrier, this must be written before the opcode register. */ > > + wmb(); > > > At least you need to use smp_wmb() but if you want to serialize MMIO > writes you can simply use

Hi Everyone, I posted a similar question about a week ago, but haven't gotten any replies -- I'm afraid that's because my previous question was too vague. Let me try again with a more specific question, and I hope someone can help. NOTE, I know I should be using the newer lme4 package, I just haven't had a chance to update my version of R yet, so the question below relates

Try this: 0.7-0.3==0.4 (We get FALSE) 0.7-0.3<0.4 (We get TRUE) but 0.8-0.3==0.5 (TRUE) 0.8-0.3<0.5 (FALSE) Funny, he? There is a way around: round(0.7-0.3,1)==0.4 (TRUE) Obviously there is a problem with some combinations of decimal subtractions, that - we have the feeling - shouldt be solved. Best regards Sven & Wolfgang -- View this message in context:

Try this: 0.7-0.3==0.4 (We get FALSE) 0.7-0.3<0.4 (We get TRUE) but 0.8-0.3==0.5 (TRUE) 0.8-0.3<0.5 (FALSE) Funny, he? There is a way around: round(0.7-0.3,1)==0.4 (TRUE) Obviously there is a problem with some combinations of decimal subtractions, that - we have the feeling - shouldt be solved. Best regards Sven & Wolfgang -- View this message in context:

oops, Forgot to cc to the list. Regards, Mike -----Original Message----- From: dr mike [mailto:dr.mike at ntlworld.com] Sent: 24 February 2005 19:21 To: 'Spencer Graves' Subject: RE: [R] Bayesian stepwise (was: Forward Stepwise regression based onpartial F test) Spencer, Obviously the problem is one of supersaturation. In view of that, are you aware of the following? A Two-Stage

Am Montag, 2. Februar 2015, 17:44:53 schrieb Marc Muehlfeld: > Hello Andreas, > > Am 02.02.2015 um 13:00 schrieb Andreas Hauffe: > > I set up a new AD with the Sernet Samba 4.1 packages. I did the > > provisioning with "samba-tool domain provision --use-rfc2307 > > --interactive". I checked the dc, ldap, kerberos and dns services under > > linux.

 Hi, Is there any function available to do stepwise selection of variables in Conditional(matched) logistic regression( clogit)? step, stepwise  etc are failing in case of conditional logistic regression. Please help.  Thanks P.T. Subha [[alternative HTML version deleted]]

Hi, S-PLUS includes the function "stepwise" which can use a variety of methods to conduct stepwise multiple linear regression on a set of predictors. Does a similar function exist in R? I'm having difficulty finding one. If there is one it must be under a different name because I get an error message when I try 'help(stepwise)' in R. Thanks for your help, Andy Taylor

Hello, I have a question pertaining to the stepwise regression which I am trying to perform. I have a data set in which I have 14 predictor variables accompanying my response variable. I am not sure what the difference is between the function "mle.stepwise" found in the wle package and the functions "step" or "stepAIC"? When would one use

Dear Gurus, Thank you in advance for your assistance. I'm trying to understand scope better when performing stepwise regression using "step." I have a model with a binary response variable and 10 predictor variables. When I perform stepwise regression I define scope=.^2 to allow interactions between all terms. But I am missing something. When I perform stepwise regression (both

Hello, I want to know how to perform stepwise elimination of variables to svyglm thanks [[alternative HTML version deleted]]