similar to: R dataframe and looping help

Hi, I'd like to get away from SAS, but I don't really know R well enough at this point to know if it would be good for this project. I tried to describe the essence of the project below without getting bogged down in details. It starts when I receive a data flat file. There's lots of columns, but the relevant ones are: custid (customer ID number) saledt (date of sale)

Hello list, using asterisk 1.4.30 and trying GROUP() and GROUP_COUNT() for the first time... Having some troubles. This the dialplan (using a sub) : exten => s,n,Set(_custID=${custID}) exten => s,n,GROUP(${custID}) exten => s,n,NoOp(grouppcount = GROUP_COUNT(${custID})) exten => s,n,GoToIf($[ ${GROUP_COUNT(${custID})} > 2 ]?maxreached) The CLI shows : [Jun 5 16:06:26] --

Hi Allaisone, I took a slightly different approach but you might find this either as or more useful than your approach, or at least a start on the path to a solution you need. df1 <- data.frame(CustId=c(1,1,1,2,3,3,4,4,4),DietType=c("a","c","b","f","a","j","c","c","f"),

I assume that this is some newbie stupidity, but I haven''t found my way around this problem. I have an ActiveRecord object fetched from the database, and I need to evaluate the contents of the updated_on field. However, *any* attempt to access that data in the program results in a TypeError with the message ''no implicit conversion from nil to integer''. cust =

Apologies if this is an obvious question but I am teaching myself R and the occasional push in the right direction is much appreciated? I have a data.frame containing data that looks like this CustID itemID 1 a 1 b 2 c 3 a 3 c I want to assemble the vector of all the items bought by a particular customer and can't quite see how to do it. What is the best

Hi Hemant, Here is an example that might answer your questions. Please don't run previous code as it might not work. I define the break values as arguments to the function (rbreaks,fbreaks,mbreaks) If you want the breaks to work, make sure that they cover the range of the input values, otherwise you get NAs. # expects a three (or more) column data frame where # column 1 is customer ID,

I'm getting all the rows as NA in Cscore and almost most of the observation in R and F and M are also NA. what can be the reason for this. also suggest me the appropriate solution. On 9 October 2017 at 15:51, Jim Lemon <drjimlemon at gmail.com> wrote: > Hi Hemant, > Here is an example that might answer your questions. Please don't run > previous code as it might not work.

I seriously doubt that you are running the code I sent. What you have probably done is to run your data, which has a different date format, without changing the breaks or the date format arguments. As you haven't provided any example that shows what you are doing, I can't guess what the problem is. Jim On Mon, Oct 9, 2017 at 9:40 PM, Hemant Sain <hemantsain55 at gmail.com> wrote:

Hello Jim, i have converted all my variable data type according to your attached example including date, and my dataset looks like this. ID purchase date 1234 10.2 2017-02-18 3453 18.9 2017-03-22 7689 8 2017-03-24 but when I'm passing the data

Hello list, getting warning : *syntax error, unexpected '<token>'* dialplan : exten => pbx,n,Macro(CheckNetworkProblems,${custID}) exten => pbx,n,NoOp(status = ${STATUS}) exten => pbx,n,GoToIf($["${STATUS}"="congestion"]?backup:nocongestion) CLI : [Sep 9 12:27:07] -- Executing [pbx at cust:15] NoOp("SIP/test13-0000002a",

Dear all, I think this is an easy task, but I don't know how to do it. Specifically, I have 69 columns with 300.000 rows. In each cell there is a code like "2E3", "4RR", etc. I now have a list that replaces this with values, e.g., old new 2E3 5 4RR 3 etc. The list ist about 1600 rows long, so also to extensive for normal solutions Do you how to do that? It would

HI Elisa, You could use ?cut() vec1<-c(33,18,13,47,30,10,6,21,39,25,40,29,14,16,44,1,41,4,15,20,46,32,38,5,31,12,48,27,36,24,34,2,35,11,42,9,8,7,26,22,43,17,19,28,23,3,49,37,50,45) label1<-unlist(lapply(mapply(c,lapply(seq(0,45,5),function(x) x),lapply(seq(5,50,5),function(x) x),SIMPLIFY=FALSE),function(i) paste(i[1],"<x<=",i[2],sep="")))

I believe you need to spend time with an R tutorial or two: a data frame (presumably the "table" data structure you describe) can *not* contain "blanks" -- all columns must be the same length, which means NA's are filled in as needed. Also, 8e^5 * 7e^4 = 5.6e^10, which almost certainly will not fit into any local version of R (maybe it would in some server version --

Hi, I have two dataframes: (Fails, Refurb) each is identical in structure. The structure has columns consisting of the following: EquipID(Equipment Identification), CustID(Customer Identification), FailTimes(Time Equipment Failed). The for loop below is part of a larger Monte Carlo simulation involving the reliability of equipment and customers. for (i in 1:length(Fails$CustID)){ j<-1

Hi all, I've got some functioning code that I've literally taken hours to write. My 'R' coding is getting better...it used to take days :) I know I've done a poor job of optimizing the code. In addition, I'm missing an important step and don't know where to put it. So, three questions: 1) I'd like the resulting output to be sorted on distance (ascending) and

Hi All I have a datafram which looks like this : CustomerID DietType 1 a 1 c 1 b 2 f 2 a 3 j 4 c 4 c 4 f And I would like to reshape this so I can

As far as I know, btrfs comes from "btree file system", but why does btrfs pronounce "butter-eff-ess"? -- Wang Shaoyan -- To unsubscribe from this list: send the line "unsubscribe linux-btrfs" in the body of a message to majordomo@vger.kernel.org More majordomo info at http://vger.kernel.org/majordomo-info.html

Hi: I have a dataframe containing comma seperated group of words such as milk,bread bread,butter beer,diaper beer,diaper milk,bread beer,diaper I want to output the frequency of occurrence of comma separated words for each row and collapse duplicate rows, to make the output as shown in the following dataframe: milk,bread 2 bread,butter 1 beer,diaper 3 milk,bread 2 Thanks for help! deb

Hello everybody, I needed something to validates my HTML templates so I wrote a plugin and here is its first version: RailsTidy is a plugin for Ruby On Rails. It allows you to * validate your rhtml templates, * validate the html output of your functional tests, * clean the html generated by rails. For doing all this, it uses * Tidy[1], the popular HTML validator and

Hello, I'm looking for a solution for the following problem: I have two vectors V1 <- c("apple","honey","milk","bread","butter") V2 <- c("bread","milk") now, I would like to know for each element in V1 if it's equal to one of the elements in V2 I could do: which(V1 == V2[1] | V1 == V2[2]) but what if I