Displaying 20 results from an estimated 2000 matches similar to: "Interpreting the result of 'cutree' from hclust/heatmap.2"
2010 Sep 17
1
Question: how to obtain the clusters of genes (basically the ones in the row dendrograms) from an object obtained by heatmap.2 function
Hello R-Helpers,
I have a question about extracting the clusters of genes after we make the
heatmap (say ht4) using the heatmap.2 function. Basically, I want to get the
clusters which are shown as row dendrogram in the heatmap.
I understand that ht4$rowDendrogram is an object of dendrogram and it
containes details of all the nodes and branches, but lets say I want to know
the number of clusters
2011 Apr 11
1
heatmap clustering dendrogram export
Hi,
I am a beginner for R.
I had use gplots to generate a heatmap as following:
>heatmap.2(matrix, col=topo.colors(75), dendrogram="column", Rowv=FALSE,
trace="none", key=TRUE, keysize=0.8, density.info="none", cexRow=0.2,
cexCol=0.6)
It work well. It generate heatmap whith rcolumn clustering dendrogram and I
can export a very nice graph. But I don not know how
2009 May 27
1
How to write a loop?
Dear R helpers,
Following is a R script I am using to run the Fast Fourier Transform. The csv files has 10 columns with titles m1, m2, m3 .....m10.
When I use the following commands, I am getting the required results. The probelm is if there are 100 columns, it is not wise to define 100 commands as fk <- ONS$mk and so on. Thus, I need some guidance to write the loop for the STEP A and
2004 Jul 21
2
Cutting heatmap dendrogram
Hello,
I've been clustering my data using hclust and cutting the resulting tree
with cutree. Separately, I visualize the clusterings with heatmap. Is it
possible to have the dendrogram on the heatmap reflect the cutree results?
That is, instead of having one large dendrogram, it would have 4 or 25 in
the example below. Any guidance on if that's possible or not, and what
kinds of
2012 Mar 29
2
hclust and plot functions work, cutree does not
Hi,
I have the distance matrix computed and I feed it to hclust function. The
plot function produces a dense dendrogram as well. But, the cutree function
applied does not produce the desired list.
Here is the code
x=data.frame(similarity_matrix)
colnames(x) = c(source_tags_vec)
rownames(x) = c(source_tags_vec)
clust_tree=hclust(as.dist(x),method="complete")
plot(clust_tree)
2011 Sep 13
2
help with hclust and cutree
Hello,
I would like to cut a hclust tree into several groups at a specific
similarity. I assume this can be achieved by specifying the "h" argument
with the specified similarity, e.g.:
clust<-hclust(dist,"average")
cut<-cutree(clust,h=0.65)
Now, I would like to draw rectangles around the branches of the
dendrogram highlighting the corresponding clusters, as is done by
2011 Sep 16
1
cutree() and rect.hclust(): different labelling of classes
I've found that while cutree() and rect.hclust() make the same classes
for a given height in the dendrogram, the actual labeling of the classes
is different. For example, both produce the same 4 classes but
class 1 according to cutree() is class 4 according to rect.hclust().
Would it be possible that future versions provide the same labeling?
rect.hclust() is useful to display the classes
2011 Jul 01
1
highlighting clusters in a heatmap
I would like to draw horizontal or vertical lines on a heatmap to
highlight the clusters at some specified cut depth of the dendrogram.
As a hacked example, the following code would work if I could set the
coordinates of the top and bottom of the false color image correctly
(ymin and ymax), but the correct values seem to depend on the output
device and its size. I realize that heatmaps use a 2x2
2011 Sep 12
1
hclust and cutree: identifying branches as classes
Good afternoon,
After cuting a hierarchical tree using cutree(), how to check correspondances between classes and branches?
This is what we do:
srndpchc <- hclust(dist(srndpc$x[1:1000,1:3]),method="ward") #creation of hierarchical tree
plclust(srndpchc,hmin=20000) #visualisation
srndpchc20000 = cutree(srndpchc,h=20000) #returns 4 classes
table(srndpchc20000 )
srndclass20000 =
2007 May 28
0
using cutree() to figure out the heatmap cluster labels on the left
I've been using heatmap(), hclust(), and cutree(), and I'm trying to figure
out the column labels of the left (as opposed to the right) cluster.
Using cutree(x, k=2), I get two clusters labeled 1 and 2. How do you figure
out if cluster 2 is the one associated with the left cluster on the heatmap
(instead of manually going to the heatmap)?
Thanks,
Andrew
Andrew Yee, MD
MGH Cancer Center
2004 May 05
1
heatmap for gene clustering?
I am using "heatmap" to cluster genes in microarrays. It works fine with
100~200 genes.
But when I draw a heatmap with 600 genes, I can't read a clustering tree
well.
Maybe I will be able to read it by dividing it into several subtrees using a
function such as "subtree".
I found "subtree" in Splus, but not in R. Is there a similar function in R?
Or, without it,
2010 Sep 08
1
saving heatmaps in graphical format that can be edited in graphic editor tool
I generated a heatmap in R using the following commands:
> mydata <- read.csv(file="Data.csv", header=TRUE, sep=",")
> mydata <- mydata[rowSums(mydata[,-1]^2) >0, ]
> rownames(mydata)=mydata$Name
> mydata <- mydata[,2:253]
> mydatamatrix <- data.matrix(mydata)
> mydatascale <- t(scale(t(mydatamatrix)))
> hr <-
2010 Sep 08
2
saving heatmaps in graphical format that can be edited in graphic editor tools
I generated a heatmap in R using the following commands:
> mydata <- read.csv(file="Data.csv", header=TRUE, sep=",")
> mydata <- mydata[rowSums(mydata[,-1]^2) >0, ]
> rownames(mydata)=mydata$Name
> mydata <- mydata[,2:253]
> mydatamatrix <- data.matrix(mydata)
> mydatascale <- t(scale(t(mydatamatrix)))
> hr <-
2008 May 16
2
heatmap on pre-established hclust output?
Hi,
Can someone please guide me towards how to produce "heatmap" output from the
output of "hclust" run prior to the actual "heatmap" call? I have some
rather lengthy clustering going on and tweeking the visual output
with "heatmap" recalculating the clustering every time is not feasible.
Thanks, Joh
2007 Dec 06
2
hclust in heatmap.2
Dear list,
I am using heatmap.2(x) to draw a heatmap. Ideally, I want to the matrix
x clustered only by columns and keep the original order of rows unchanged.
Is there a way to do that in heatmap.2()?
Thanks a lot! Any suggestions will be appreciated!
Best,
Allen
[[alternative HTML version deleted]]
2004 Dec 15
1
hclust and heatmap - slightly different dendrograms?
Good afternoon,
I ran heatmap and hclust on the same matrix x (strictly, I ran
heatmap(x), and hclust(dist(t(x))), and realized that the two
dendrograms were slightly different, in that the left-right
arrangement of one pair of subclusters (columns) was reversed in the
two functions (but all individual columns were grouped correctly).
Looking through the code for heatmap as a most definite
2010 Sep 22
0
How to Ignore NaN values in Rows when using hclust function in making Heatmap??
I am making heatmaps for a dataset (~ 300*600 matrix) with the following R
script (I am not familiar with R and this is the first time I am using it).
library("gplots")
library("Cairo")
mydata <- read.csv(file="data.csv", header=TRUE, sep=",")
rownames(mydata)=mydata$Name
mydata <- mydata[,2:297]
mydatamatrix <- data.matrix(mydata)
mydatascale
2003 Sep 24
1
heatmap and hclust
Hi all,
The function heatmap uses the functions dist and hclust with default
parameters.
How to change these parameters? For example, i want to use the ward
criterion for hierarchical
clustering with binary distance.
Best regards,
Olivier.
2006 Mar 09
1
Identifying or searching for labels in a hclust/dendrogram/heatmap
Hi
Sorry if this is in the help :-S
I've looked at example(dendrogram) and though it gives some indication of what I want, it doesn't do all.
OK, so here is what I want to do: draw a tree, and then have an action, on user-click, to either draw a sub tree or a plot of the data. I also want users to be able to search for a particular label and have it highlighted on the tree, say in
2011 Mar 02
2
clustering problem
Hi,
I have a gene expression experiment with 20 samples and 25000 genes each.
I'd like to perform clustering on these. It turned out to become much faster
when I transform the underlying matrix with t(matrix). Unfortunately then
I'm not anymore able to use cutree to access individual clusters. In general
I do something like this:
hc <- hclust(dist(USArrests), "ave")