similar to: ggplot2

Hi.. i have an expression of the form: model1<-nls(y~beta1*(x1+(k1*x2)+(k1*k1*x3)+(k2*x4)+(k2*k1*x5)+(k2*k2*x6)+(k3*x7)+(k3*k4*x8)+(k3*k2*x9)+(k3*k3*x10)+ (k4*x11)+(k4*k1*x12)+(k4*k2*x13)+(k4*k3*x14)+(k4*k4*x15)+(k5*x16)+(k5*k1*x17)+(k5*k2*x18)+(k5*k3*x19)+

Hello All, I have a question about glm in R. I would like to fit a model with glm function, I have a vector y (size n) which is my response variable and I have matrix X which is by size (n*f) where f is the number of features or columns. I have about 80 features, and when I fit a model using the following formula,? glmfit = glm(y ~ x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 + x9 + x10 + x11 + x12 + x13

I don't see the issue here. It would be helpful if people would report their sessionInfo() when reporting whether or not they see this issue. Mine is > sessionInfo() R version 3.4.3 (2017-11-30) Platform: x86_64-pc-linux-gnu (64-bit) Running under: Arch Linux Matrix products: default BLAS/LAPACK: /usr/lib/libopenblas_haswellp-r0.2.20.so locale: [1] LC_CTYPE=en_US.UTF-8

Hello, I have looked on https://www.r-project.org/bugs.html , but it seems that this is the only way to do it. The issue is that the precision used by write.csv is on consistant for big files. See the following code: First I create a large dataframe filled with random uniform values. Then I write it to .csv and print out the first and last lines. df = data.frame(replicate(100, runif(1000000,

Hopefully this is really a generic question about IAX and doesn't turn out to be something specific to Teliax, because they haven't been too helpful so far. All they can tell me is that my login shows "status unknown" on their end, which prevents me from receiving inbound calls on my Teliax number. Outbound calls through the same server work fine, which rules out most networking

To my surprise, I can confirm on Windows 10 using R 3.4.3 . As tail is not recognized by Windows cmd, I replaced with: system('powershell -nologo "& "Get-Content -Path temp.csv -Tail 1') The last line shows only 7 digits after the decimal, whereas the first have 15 digits after the decimal. I agree with Dirk though, 1.6Gb csv files are not the best way to work with

Full_Name: Derek Elmerick Version: 2.4.0 OS: Windows XP Submission from: (NULL) (38.117.162.243) hello - i have some code that i run regularly using R version 2.3.x . the final step of the code is to build a multinomial logit model. the dataset is large; however, i have not had issues in the past. i just installed the 2.4.0 version of R and now have memory allocation issues. to verify, i ran

Hola: Como dice Carlos, algo así, por ejemplo: transforma <- function(df) sapply(df, function(x) ifelse(x%in%c("x1","x2","x3"), "prueba1",ifelse(x%in%c("x4","x5","x6"),"prueba2",x))) > transforma(df1)       col1  [1,] "prueba1"  [2,] "prueba1"  [3,] "x11"  [4,]

Dear List, I've around 1000 *.txt files, I've generate with other software. I've now done the following code (below). My question is how can I automate this (with do.call () ?), so it could be done for all the *.txt files. Thanks in advance, Rog??rio names<- list.files() file <- "BLU_Var_%04d.txt" for(i in 1:1000){

Hi - a newbie question, if someone can please help.... I want to change X1, X2,,.....to X.1 X.2 etc in the names below. I am using the Principal Component Regression function (pcr) and it seems to want it this way > datap3.pcr <- pcr(water ~ X, 10, data = datap3, Validation ="cv") Error in model.frame.default(formula = water ~ X, data = datap3) : invalid type (list) for

Hello there, I''m having lots of problems with my setup here. Let me explain: I am network administrator for my university dorm. We are about 300 users, and we have 2 ADSL connections doing load balancing with 300kbits upstream and 2Mbit downstream. The load balancing is working great, we are doing connection tracking so I can mark and hence prioritize interactive traffic and ACKS

Hi, I was wondering how it was possible to access the actual cluster exemplars from the APResult class. Currently it only spits it out onto the terminal if you type the object but there is no other way to see which one is the examplar. Would appreciate any help. Thanks, Sachin [[alternative HTML version deleted]]

If you want a character representation of a long formula (or a formula with long names), you can use: as.character(my.formula) However restriction on length of an as.character result returns only the beginning of a long formula, and without comment. In most cases, the following expression provides the complete result: paste(my.formula[[2]], " ~ ",

Hello everyone, I am trying to fit the following model All X. variables are continuous, while the conditions are categoricals. model <- lm(X2

Yo copio y pego este código y me sale correctamente. Se me ocurre que pueda deberse a la versión de R ¿cuál usas? El 10/09/2020 a las 17:51, Samura . escribió: > Gracias por las respuestas. > > Probé lo de hacer la función y no me salía. Pensaba que hacía algo mal. > Ahora con el código de Marcelino tampoco me sale. > > col1 <- c('x1', 'x2', 'x11',

Hola, me gustar?a hacer algo como en el siguiente ejemplo A un df a?adirle una columna que es la transformaci?n de otra, en plan a todo lo que sea x1, x2, x3 lo llamo prueba 1 todo lo que sea x4,x5,x6 lo llamo prueba 2 el resto de x las dejo como est?n. Ser?a algo as? col1 <- c('x1', 'x2', 'x11', 'x1','x33', 'x1','x4', 'x5',

Hallo, All, I have a question about changing the height or scale of the y axis. When I use following two R codes, I can get two plots. Please look at the y axes, the number of indices (x1, x2, ?) on the y axis in the first plot is smaller than that in the second plot, and hence the space between any two indices in the first plot is wider than that in the second plot. As the number of indices

Hi All, I have a query about time based sequences. I know such questions have been asked a lot on forums, but I couldnt find the exact thing that I was looking for. I want to create a time-based sequence which will mimic the trading window AND would span multiple days. Something like below: "2011-01-03 09:15:00 IST" "2011-01-03 09:15:01 IST" .... .... .... "2011-01-03

Hello, I'm working with an array; I'm trying to make it so that an array of dim(42,2,2) has names whose length corresponds to that of the array, and am hoping someone with experience with this can see what I'm not doing correctly: data11 = array(0,c(41,2,2)) y = lsoda(x0,times,fhn$fn.ode,pars)#This is make.fhn() from colloc infer package# y = y[,2:3]

I am new to more radical programming in R. I am trying to write a nested 'for' loop to produce output that takes subscripts like: for i taking values 1,2,3,4,5 and j taking values 1,2,3 I want to output for a computation using the combination values of i and j a value x like this; i j x 1 1 x11 1 2 x12 1 3 x13 2 1 x21 2 2 x22 2 3 x23 3 1 x31 3 2 x32