Displaying 20 results from an estimated 20000 matches similar to: "Replacing strings to numbers"
2013 Jun 18
1
transform 3 numeric vectors empty of 0/1
Dear all,
Without a loop, I would like transform 3 numeric vectors empty of 0/1 of
same length
Vec1 : transform 1 to A and 0 to ""
Vec2 : transform 1 to B and 0 to ""
Vec3 : transform 1 to C and 0 to ""
to obtain only 1 vector Vec who is the paste of the 3 vectors (Ex : ABC,
BC, AC, AB,...)
Any idea ?
Thank you for your help
--
Michel ARNAUD
2013 Feb 17
1
addition in the initial question
Dear Elisa,
Try this:
vec1<-c(33,18,13,47,30,10,6,21,39,25,40,29,14,16,44,1,41,4,15,20,46,32,38,5,31,12,48,27,36,24,34,2,35,11,42,9,8,7,26,22,43,17,19,28,23,3,49,37,50,45)
vec2<-vec1[1:26]
names(vec2)<-LETTERS[1:26]
label1<-unlist(lapply(mapply(c,lapply(seq(0,45,5),function(x) x),lapply(seq(5,50,5),function(x) x),SIMPLIFY=FALSE),function(i)
2013 Jan 15
2
Need some help on Text manipulation.
Dear all,
Let say I have following data-frame:
Dat <- structure(list(dat = c(-0.387795842956327, -0.23270882099043,
-0.89528973290562, 0.95857175595512, 1.61680582493783, -1.17738110289352,
0.210601060411423, -0.827369747447338, -0.36896112964414, 0.440288648776096,
1.28018410608809, -0.897113649961341, 0.342216546981718, -1.17288066266219,
-1.57994101992621, -0.913655547602414,
2013 Jan 09
4
how to count "A","C","T","G" in each row in a big data.frame?
Dear All
I have a data.frame like that:
structure(list(name = c("Gga_rs10722041", "Gga_rs10722249", "Gga_rs10722565",
"Gga_rs10723082", "Gga_rs10723993", "Gga_rs10724555", "Gga_rs10726238",
"Gga_rs10726461", "Gga_rs10726774", "Gga_rs10726967", "Gga_rs10727581",
"Gga_rs10728004",
2013 Aug 29
4
Add new calculated column to data frame
Hi,
I have a following data set:
id event time (in sec)
1 add 1373502892
2 add 1373502972
3 delete 1373502995
4 view 1373503896
5 add 1373503996
...
I'd like to add new column "time on task" which is time elapsed between two
events (id2 - id1...). What would be the best approach to do that?
Thanks,
Srecko
[[alternative HTML
2012 Aug 24
6
updating elements of a vector sequentially - is there a faster way?
I would like to know whether there is a faster way to do the below
operation (updating vec1).
My objective is to update the elements of a vector (vec1), where a
particular element i is dependent on the previous one. I need to do this on
vectors that are 1 million or longer and need to repeat that process
several hundred times. The for loop works but is slow. If there is a faster
way, please let
2013 Sep 05
2
binary symmetric matrix combination
Hi,
May be this helps:
m1<- as.matrix(read.table(text="
y1 g24
y1 0 1
g24 1 0
",sep="",header=TRUE))
m2<-as.matrix(read.table(text="y1 c1 c2 l17
?y1 0 1 1 1
?c1 1 0 1 1
?c2 1 1 0 1
?l17 1 1 1 0",sep="",header=TRUE))
m3<- as.matrix(read.table(text="y1 h4??? s2???? s30
?y1 0 1 1 1
?h4 1 0 1 1
?s2 1 1 0 1
?s30 1 1 1
2005 Oct 28
3
replacing a factor value in a data frame
Hi All,
I have the following problem, that's driving me mad.
I have a dataframe of factors, from a genetic scan of SNPs. I DO have
NAs in the dataframe, which would look like:
V4 V5 V6 V7 V8 V9 V10
1 TT GG TT AC AG AG TT
2 AT CC TT AA AA AA TT
3 AT CC TT AC AA <NA> TT
4 TT CC TT AA AA AA TT
5 AT CG TT CC AA AA TT
6 TT CC TT AA AA AA TT
7 AT CC
2010 Aug 24
3
multiple assignments ?
Simple one, have read and googled, still no luck!
I want to create several empty vectors all of the same length.
I would like multiple empty vectors (vec1, vec2, vec3) and want to create them all in one line.
I've tried
vec1,vec2,vec3 <- vector(length=5)
and
c(vec1,vec2,vec3) <- vector(length=5)
and several other attempts but nothing seems to work ... suggestions?
Thanks
Jim
2008 May 12
1
lexicographic comparison of two vectors
Is there any built-in way to lexicographically compare two vectors of
the same length in R? The textbook algorithm could be coded as follows:
lex.cmp <- function (vec1,vec2) {
for (j in 1:length(vec1)) {
if (vec1[j] < vec2[j]) { return(-1) }
if (vec1[j] > vec2[j]) { return(1) }
}
return(0)
}
Thanks,
Gabriel
2010 Jul 12
2
findInterval and data resolution
Hello Wise Ones...
I need a clever way around a problem with findInterval. Consider:
vec1 <- 1:10
vec2 <- seq(1, 10, by = 0.1)
x1 <- c(2:3)
a1 <- findInterval(x1, vec1); a1 # example 1
a2 <- findInterval(x1, vec2); a2 # example 2
In the problem I'm working on, vec* may be either integer or numeric, like
vec1 and vec2. I need to remove one or more sections of this vector;
2004 Jul 09
3
Problem with bwplot
Try factor(vec2) in your bwplot() call.
-----Original Message-----
From: r-help-bounces at stat.math.ethz.ch
[mailto:r-help-bounces at stat.math.ethz.ch]On Behalf Of Ernesto Jardim
Sent: Friday, July 09, 2004 9:41 AM
To: Mailing List R
Subject: [R] Problem with bwplot
Hi,
I'm ploting some box-and-whisker plots with bwplot but I'm not getting
any box-and-whiskers ... just dots.
2009 Jul 27
1
how to use do.call together with cbind and get inside a function
Dear R-helpers:
I have a question related to using do.call to call cbind and get.
#the following works
vec1 <- c(1,2)
vec2 <- c(3,4)
ColNameVec <- c('vec1','vec2')
mat <- do.call("cbind",lapply(ColNameVec,get))
mat
#put code above into a function then it does not work
#before doing so, first remove vec1 and vec2 from global environment
rm(vec1,vec2)
test
2012 Nov 08
5
map two names into one
Thanks.
Yes. Your approach can identify:
Glaxy ace S 5830 and
S 5830 Glaxy ace
But you can not identify using same program:
Iphone 4S 16 G
Iphone 4S 16G
How should I solve both in same time.
Kind regards,Tammy
[[alternative HTML version deleted]]
2008 Dec 30
2
[LLVMdev] Folding vector instructions
Hello.
Sorry I am not sure this question should go to llvm or mesa3d-dev mailing
list, so I post it to both.
I am writing a llvm backend for a modern graphics processor which has a ISA
very similar to that of Direct 3D.
I am reading the code in Gallium-3D driver in a mesa3d branch, which
converts the shader programs (TGSI tokens) to LLVM IR.
For the shader instruction also found in LLVM IR,
2013 Mar 22
2
A question on function return
Hello again,
Let say I have following user defined function:
fn <- function(x, y) {
Vec1 <- letters[1:6]
Vec2 <- 1:5
return(list(ifelse(x > 0, Vec1, NA), ifelse(y > 0, Vec2, NA)))
}
Now I have following calculation:
> fn(-3, -3)
[[1]]
[1] NA
[[2]]
[1] NA
> fn(3, -3)
[[1]]
[1] "a"
[[2]]
[1] NA
Here I can not understand why in the second case, I get
2009 Feb 25
2
: record which entry in one file doesn't appear in a different file
Hi dear list,
If anybody could help me, it would be great!
I have two files:
File 1 is a list (one column and around 100000 rows)
File 2 is a list with all the names from file one and a few more (one
column and more than 100000 rows)
What I want is to add a column in file 2 that says which name appeared
in file 1 and which doesn't (yes and no would work as a code)
It's very important to
2002 Jun 18
5
insert number in vector
Hello R-users,
I need to create a vector inserting an 1 after each value of another vector.
For example:
vec1<-c(2,3,4)
I need to create a vector with the values 2,1,3,1,4
Does anyone know how create this vector without loops (vec1 could have 1000
elements)
Thank you,
Juan
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
r-help mailing list -- Read
2010 Feb 02
1
Finding the difference between two vectors
Hello everyone,
I have two vectors having only one element different:
vector1 vector2
vector1
TWC TWC
TWC
VFC TWX
NA
VIA/B VFC
VFC
2008 Sep 20
1
lower and upper limits in integrate as vectors
Dear R useRs,
i try to integrate the following function for many values
"integrand" <- function(z)
{
return(z * z)
}
i do this with a for-loop
for(i in 2:4)
{
z <- integrate(integrand, i-1, i)$value
cat("z", z, "\n")
}
to speed up the computation for many values i tried vectors
in integrate to do this.
vec1<-1:3
vec2<-2:4