similar to: choicemodelr is misbehaving under R3.0

Hello! I have Windows 7 Enterprise and two versions of R installed: 2.15.3 and 3.0.0. Before I had R 3.0 I made it a setting that all .RData files - when I double-click on them - were opened by R 2.15.3. Now I want them to be opened by R 3.0 instead of R 2.15.3 (but I don't want to remove R 2.15.3. yet). I right-click on some .RData file, select "Open with" - "Choose default

Hello, My target features some very-high-latency instructions that access an on-chip network (we'll call them FXLV). In one important kernel (snippet below), register allocation needs to spill values resulting from FXLV. The spiller is unaware of FXLV's latency, and thus naively inserts those spills immediately after the FXLV, incurring huge and unnecessary data stalls. FXLV r10,

My tuneR sawtooth wave function generator is broken. When I use the sine function, I get exactly what I expect: a sine wave whose frequency is defined by the freq parameter. In particular, higher frequencies have shorter wavelengths (more cycles per second means shorter waves). When I create a sawtooth wave, the opposite seems to occur: higher frequencies result in longer waves. But that?s not

Ccing the maintainer if the tuneR package. Looks to me like sawtooth (and square) don't behave as expected when using xunit="samples". Workaround is to use xunit="time" instead: sawtooth(110,duration=1/100,samp.rate=sample_rate,xunit="time") I looked at the code but found it to be opaque. -- Sent from my phone. Please excuse my brevity. On November 12, 2017

I have several demographic variables with which I want to explain the ordered choice of individuals within a survey in an ordered choice (probit or logit, this is not important) framework. Standard ordered choice estimations of course just give me aggregate/average parameter estimates. For my task it would however be useful to estimate or extract "hypothetical" individual-level parameter

Hola a todos. Un problema dos pasos. Quiero desde RStudio trabajar con dos versiones de R (pongamos R2.13 y R2.15) desde Linux, Ubuntu 10.04 (lucid). Ya tengo instalada la R.2.15.1. Por defecto trabajo con ella. Pasos que creo he de dar: 1º. Instalar dos versiones de R en la misma maquina. ¿Como se hace?. Me estoy metiendo con el PATH y tal... hay algún protocolo clarito por ahí? 2º.

Dear helpers, Does anyone have information on the status of bigmemory and R3.0? Will it just take time for the devs to re-code for the new environment? Or is there an alternative for this new version? Thanks Ben Caldwell [[alternative HTML version deleted]]

I think you should be more suspicious of yourself, Dimitri. A letter T variable can easily arise in the problem domain when you are not thinking of logical values at all, at which point your cavalier use of T as a synonym for TRUE can suddenly become a bug. -- Sent from my phone. Please excuse my brevity. On July 27, 2017 8:18:03 AM PDT, Dimitri Liakhovitski <dimitri.liakhovitski at

Dear R-list, maybe some of you could point me in the right direction: Are you aware of any FREE Fortran or Java libraries/actual pieces of code that are VERY efficient (time-wise) in running the regular linear least-squares multiple regression? More specifically, I have to run small regression models (between 1 and 15 predictors) on samples of up to N=700 but thousands and thousands of them. I

Hello! I have a column in my data frame that I have to split: I have to distill the numbers from the text. Below is my example and my solution. x<-data.frame(x=c("aaa1_bbb1_ccc3","aaa2_bbb3_ccc2","aaa3_bbb2_ccc1")) x library(stringr) out<-as.data.frame(str_split_fixed(x$x,"aaa",2)) out2<-as.data.frame(str_split_fixed(out$V2,"_bbb",2))

Hello! I am trying to understand how ggplot2's geom_bar treats NAs. The help file says: library(ggplot2) ?geom_bar na.rm: If FALSE, the default, missing values are removed with a warning. If TRUE, missing values are silently removed. I am trying it out: md <- data.frame(a = c(letters[1:5], letters[1:4], letters[1:3], rep(NA, 3))) str(md); levels(md$a) ggplot(data = md, mapping = aes(x =

Just a thought: Did you try na.rm = TRUE in case you have an object named "T" in scope? -- Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Thu, Jul 27, 2017 at 7:49 AM, Dimitri Liakhovitski <dimitri.liakhovitski at

Hello! s<-"start"; e<-"end" middle<-as.character(c(1,2,3)) I would like to get the following result: "start 123 end" or "start 1 2 3 end" or "start 1,2,3 end" How can I avoide this (undesired) result: paste(s,middle,e,sep=" ") Thank you! -- Dimitri Liakhovitski Ninah Consulting www.ninah.com

?hanks for the advice, Jeff. Will keep it in mind. But I am anal - I shy away from using letters and words that "look familiar" to me in R (such as mean, sd, T, etc.) But still, it's a good advice. On Thu, Jul 27, 2017 at 11:53 AM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote: > I think you should be more suspicious of yourself, Dimitri. A letter T > variable can

To clarify: my question is not about "who could I exclude NAs from being counted" - I know how to do that. My question is: Why na.rm = T is not working for geom_bar in this case? On Thu, Jul 27, 2017 at 8:24 AM, Dimitri Liakhovitski < dimitri.liakhovitski at gmail.com> wrote: > Hello! > > I am trying to understand how ggplot2's geom_bar treats NAs. > The help file

Dear R-ers! I have x as a variable in a data frame x. x<-data.frame(x=c("aa.bb","cc.dd.ee")) x$x<-as.character(x$x) x I am sorry for such a simple question - but how can I replace all periods in x$x with spaces? sub('.', ' ', x$x) - removes all letters to the left of each period... Thanks a lot for your advice! -- Dimitri Liakhovitski Ninah.com

Hello everyone! I have a list X with 3 elements, each of which is a data frame, for example: a<-data.frame(a=1,b=2,c=3) b<-data.frame(a=c(4,7),b=c(5,8),c=c(6,9)) c<-data.frame(a=c(10,13,16),b=c(11,14,17),c=c(12,15,18)) X<-list() X[[1]]<-a X[[2]]<-b X[[3]]<-c (X) How can I most effectively transform X into a data frame with columns a, b, and c? I would love to find a generic

Hello! I am using function "curve" to create a line graph. I was wondering, if it's possible to "turn off" the default tick marks and introduce those tick marks in specific locations. For example, currently in my X axis tick marks are (automatically) at 10, 11, 12, 13 but I want them to be in 5 specific locations, like 9.89, 10.34, etc. Any hint would be greatly

Context: R2.15-0 on Ubuntu. 1. I get a WARNING from CMD check for "Package vignette(s) without corresponding PDF: In this case the vignettes directory had both the pdf and Rnw; do I need to move the pdf to inst/doc? I'm reluctant to add the pdf to the svn source on Rforge, per the usual rule that a code management system should not have both a primary source and a object

Hello! I wrote a function that returns a data frame. Nowhere in the function do I say print(my.data.frame), but when I run the function - the data frame is printed on the console. Is there any way to suppress it? Thank you! -- Dimitri Liakhovitski Ninah Consulting www.ninah.com