similar to: Selecting divergent colors

Hi I am relatively new to R and am trying to figure out to plot 3d scatter plot using defined colors based on x-axis and y-axis values. Right now in the code below, I assign colors based on certain values in the names of the x-axis. Now if I want to extend the condition to assign a color based on the names of both x-axis and y-axis values, what should I be doing? Any help or ideas would be

R-help, I'm trying to read a data file with plenty of columns. I just need the first 5 but it doe not work by doing something like: > mycols <- rep(NULL, 430) ; mycols[c(1:4)] <- NA > read.table(myfile, skip=2, colClasses=mycols) Any suggestions? Thanks in advance

Hello, I have a data frame which looks like > head(d) a1 a2 n j col 1 1 1 88341002 11 #E7E7E7 2 1 2 25094882 11 #E7E7E7 3 1 3 16916246 11 #E7E7E7 4 1 4 14289229 11 #E7E7E7 5 1 5 11945929 11 #E7E7E7 6 1 6 8401235 11 #E7E7E7 The values in 'j' run from 1 to 11. I would like to plot the point (a1,a2) with color given by j I tried mi <-

Just as as.vector() takes a vector, matrix or array and returns a vector in row-major order, I'd like to write a function to take such an object and return the dimension names, pasted with some separator, as a similar vector. Here is something ugly cobbled together to demonstrate what I want: a function to work for any number of dimensions. vecnames <- function(x, sep=':') {

Hi, I was trying to get an image/pdf of a sequence of colors in the order given. For example: myCols <- c('#0000BF','#0000BF','#0000FF','#0000FF','#0000BF','#0000FF') I'd like to make a strip of colors as they appear in the order above and save it as a pdf file. Is there a function in the base package (or some other package) to do this?

Dear R People, I'm working on a plot function to produce the graph shown below. One of the features my supervisor does not like is that the labels in the Y- axix are shown vertically. Is there a way to change that to horizontally ? This is the axix() function I used : axis(2,at=seq(nstrat),labels=snames) The labels (snames) are: SEV1:HU:C, SEV1:MU:C, SEV1:MU:L, SEV1:RT:C and SEV1:RT:L,

I have a data frame. And I'd like to subset according to rownames. subset(mydataframe, rownames(mydataframe) == myrow, select = mycols) it turned out that "myrow" cannot be a vector. But I have multiple rows to pick. Is there a way to get around this problem?? Thank you for your help!! Lei Jiang Department of Chemsitry University of Washington Box 351700 Seattle, WA 98195

Dear R gurus, I want to wrap labels that are too long for a plot. I have looked at strsplit(), substr(), nchar(), and strwrap(). I think it's some combination but I'm having difficulty trying to figure out the right combo. I think I need to create some new matrix containing the labels already split, though I'm not sure if maybe there is a quick and dirty way to address this

I am reading some documentation about Cross Spectrum Analysis as a technique to compare spectra. My understanding is that it estimates the correlation strength between quasi-periodic structures embedded in two signals. I believe it may be useful for my signals analysis. I was referred to the R functions that implement this type of analysis. I tried all the examples which generated a series of

Dear All, I have a data frame with n columns: X1, X2, ., Xn. Now I want to create a new column: if X1 = X2 = . = Xn, the value is 1; Otherwise, the value is 0. How to do that in a quick way instead of doing (n choose 2) comparisons? Thank you, Frank [[alternative HTML version deleted]]

Hi, Im new to R so this question is quite fundamental. Im trying to compare some autocorrelations generated by the acf function to some theoretical correlations. How can I have acces to just the autocorrelations, for computation? This is some of my code: > acf.data<-c(acf(x)) > acf.data This is the R output: $acf , , 1 [,1] [1,] 1.000000000 [2,]

Hi everyone, I am just trying to figure out how to do a xyplot where in addition to dots and lines I can change dots' colors according to an individual variable (e.g., marital disruption across time, a dummy 0/1). When I use "groups" specification (see below), I get two different lines for each individual based on groups, and what I want is to get one line connecting dots, and

Hi, I'm having problems while working with large data sets with R 1.5.1 in windows 2000. Given a integer matrix size of 30 columns and 15000 rows my function should return a boolean matrix size of about 5000 rows and 15000 columns. First of all I tried to run this function on computer with 256 MB of RAM. I increased memory limit of R with memory.limit() up to 512 MB. I was inspecting

Hi Hugo, I've been able to replicate your bug, including for other distributions (runif, rexp, rgamma, etc) which shouldn't be surprising since they're probably all drawing from the same pseudo-random number generator. ?Interestingly, it does not seem to depend on the choice of seed, I am not sure why that is the case. I'll point out first of all that the R-devel mailing list is

Hi Hugo, I've been able to replicate your bug, including for other distributions (runif, rexp, rgamma, etc) which shouldn't be surprising since they're probably all drawing from the same pseudo-random number generator. ?Interestingly, it does not seem to depend on the choice of seed, I am not sure why that is the case. I'll point out first of all that the R-devel mailing list is

Hello, everybody: I'm back to share a long piece of example code. Because I had trouble understanding the role of par() and margins when customizing barplots, I have struggled with this example. In case you are a student wanting to place legends or textual markers in the outer regions of a barplot, you might run these examples. There are a few little things I don't quite understand.

I am trying to automate a report that my company does every couple of years for the state of Maine. In the past we have used SPSS to run the data and then used complicated Excel template to make the tables/graphics which we then imported into Word. Since there are 256 tables/graphics for this report, this work flow is a little painful. I would like to automate the process and I think I can do

Hi! I am new to R just 3 days in it and i apologize if my questions seem very trivial and consumed your valuable time. I am coding in perl and i stumbled upon R regarding plotting good statistical graphs. I tried the kmean clustering for a large matrix ,say > 150 * 150 . I tried the example code given in the tutorial to perform 2d plot # i ranges from 2 to 10 cl <- kmeans(x, i, 20)

> Dear expeRts, > > Currently, my colors are as follows: > mycol <- > c("blue1","blue2","blue3","blue4","black","yellow4","yellow3","yellow2","y > ellow1") > heatmap(snp, Rowv=NA, Colv=NA, col=mycol) > > However, I would like to have the following colors: > bright blue ->

Dear users, I have a double for loop that does exactly what I want, but is quite slow. It is not so much with this simplified example, but IRL it is slow. Can anyone help me improve it? The data and code for foo_reg() are available at the end of the email; I preferred going directly into the problematic part. Here is the code (I tried to simplify it but I cannot do it too much or else it