similar to: col2rgb, factors & documentation

The release notes for R 2.0.0 states: It is now possible to specify colours with a full alpha transparency channel via the new 'alpha' argument to the rgb() and hsv() functions, or as a string of the form "#RRGGBBAA". NOTE: most devices draw nothing if a colour is not opaque, but PDF and Quartz devices will render semitransparent colours. A new argument

Hi Martin, Great that you follow this. My original intention was to be able to translate colornames to hsv because this would allow using colornames to cut out a certain part of the colorwheel for colorcoding (HSV component H, see my code below) I think internally we might have colors represented as Colornames, ColorIntegers, ColorHexcodes, ColorRGBs, ColorHSVs (ColorCMYs?) however the R-user

Dear r-helpers, I wonder whether, given the "#rrggbb" representation of a colour, there is a simple way to select the complementary colour, also expressed as a "#rrggbb" string. Any suggestions would be appreciated. John -------------------------------- John Fox, Professor Department of Sociology McMaster University Hamilton, Ontario Canada L8S 4M4 905-525-9140x23604

Hello List Dwellers: I?ve looked around quite a bit, but don?t quite see an answer that I understand. I?m looking for a way to take any kind of color specification (rgb, hsv, hcl, hex) and match it to the n-nearest R official color names. Clearly it is easy to interconvert different specification schemes and color spaces, but matching to the name seems a bit trickier. Seems like if one has a

I want to get a lighter shade of a color...I have a lot of colored objects and want each one printed as a foreground against a slightly lighter background. I thought I could try something like changing the alpha channel by first converting it to rgb. But prior to trying that, I'm stuck with how to get the color after converting using col2rgb() to be interpreted again as a color, rather than

Hello I have a palette vector of colour blind colours (in hexadecimal) which I?m using for plots, but they are not see-through, and as I wanted to overlay some histograms I wanted to convert these colours to rgb, when you can set the opacity. I have found the function col2rgb(), which works in the sense that it gives a vector of numbers but these don?t work directly in rgb because they are too

Does adjustcolor() help? cb8<- c("#000000", "#E69F00", "#56B4E9", "#009E73","#F0E442", "#0072B2", "#D55E00", "#CC79A7") plot(0,0,xlim=c(1,8),ylim=c(0,1)) points(1:8,rep(0.5,8),col=cb8,pch=19,cex=2) points(1:8,rep(0.75,8),col=adjustcolor(cb8, alpha.f = 0.3), pch=19,cex=2) On 2023-07-23 2:15 p.m., Nick Wray

Thanks That works nicely Nick On Sun, 23 Jul 2023 at 19:26, Ben Bolker <bbolker at gmail.com> wrote: > Does adjustcolor() help? > > cb8<- c("#000000", "#E69F00", "#56B4E9", "#009E73","#F0E442", "#0072B2", > "#D55E00", "#CC79A7") > plot(0,0,xlim=c(1,8),ylim=c(0,1)) >

Just one addition which may or may not be useful: The color palette you use is also known as "Okabe-Ito" and it is the default set of colors in the palette.colors() function. This function also has an optional alpha argument. So if you want to generate these colors with an alpha of 0.3 you can also do: palette.colors(8, alpha = 0.3) or more explicitly palette.colors(8, palette =

Nick, I've also made colors transparent by pasting the hex equivalent of, say, 0.3*256 = 76.9 to the hex color code. e.q. for black it might be "#0000004d" and the 4d is 77 in hex. That way you don't need to convert back and forth so much. If col is "#000000" the transparent version is tcol <- paste0(col,"4d") This would work in one step on a whole

I think I more or less understand what a ?wrapper? is, but I?d like to hear how more experienced R users define it, and especially I'd like to know if there is a formal definition. In my reading, it seems like there are a fairly wide range of meanings, but they are all conceptually similar. I've looked in a couple of the classic R texts, the extensions and developers' manuals, and R

Dear, I am having a lucky day. I am programming in RStudio and when I type "black" (quotation signs included, the word turn into a word with black ground. Couldn't get rid of the background----copying to Word, Excel, text editor and paste back to Rstudio, the word is still in black background? Help! ??? dv.group<-c("black","othrrace");

Dear List, I have a 47 species * 83 samples matrix containing percentage abundance data. I have two cluster analyses one of the samples and one of the species, and have ordered the rows and columns of the species by samples matrix according to these two cluster analyses. So far so good! Now what I want to do is create a plot with the species dendrogram at the top of the plot, the samples

Gurus: I keep seeing other people?s code that contain ideas like If (x == 2L) X[-1L] X - 1L I have some idea of what?s going on, but where is the use of concepts like ?2L? documented? Thanks, Bryan ************* Bryan Hanson Acting Chair Professor of Chemistry & Biochemistry DePauw University, Greencastle IN USA

Hello Folks. This must be a silly question with a (not) obvious (to me) answer. Consider this: tmp <- matrix(1:200, nrow = 20) vec <- 300:309 tmp[9,] <- vec # replacing one row works fine p <- c(3, 11, 17) tmp[p,] <- vec # replacing multple rows pastes the values down a column and recycles vec. What I want to do is replace multiple rows simultaneously at once. I suppose I can

Hi, I have a data file in a KML format which is Google Earth's format for geographic data. I need to import it into a csv file . How can I do that. KML format is just like XML format .example below Which R module with deal with an OR problem (like transportation problem using geo coded data as in the example below) Regards, Ajay www.decisionstats.com - <?xml version="1.0"

hi all, i have a simple scatter plot, and i'd like to make it so the scatter plot colors are slightly transparent. i see in a previous post that someone mentioned the "alpha" parameter, but i am not sure how it can be used with the 'plot' function [*]. for example, suppose i have: plot(mydata$column1, mydata$column2, col="red", cex=1) i now want to make it so

hi, I have been attempting to run this script and am getting some strange results. The script connects to a database and retrieves a series of tables, using sequential sql statements. I have tested all of the sql statements in the PostGreSQL terminal and they all return the desired results. I place each table into a list and run a FOR loop for 'i' in the list. The script generates

Hi all... My students were conflating grepping for a value in a vector to get the index, and then removing it with [-index], for instance like this: set.seed(17) v <- rnorm(20) s <- v[-1.18] They were trying to remove the 12th value in v, which is -1.18 or so. But the result is, as documented in ?Extract, to coerce 1.18 to the next lowest integer, and remove the 1st value of v, not the

Hello R Masters and the Rest of Us: The first of these works fine, the 2nd is accepted but too literal (the "%->%" is shown in the plot label and in the wrong position). The 3rd throws and error due to "unexpected SPECIAL". Would someone recommend a way to format this? I want the two phrases connected by a right arrow. TIA, these things always elude me. Bryan