similar to: Assigning NULL to large variables is much faster than rm() - any reason why I should still use rm()?

Dear R List, I am a new to R, so my question may be easy to answer for you: I have a dataframe, for example: df<-data.frame(loc=c("A","B","A","A","A"), year=as.numeric(c("1970","1970","1970","1976","1980"))) and I want to create the following table without using loops: 1970-74 ;

--============_-1179735293==_ma============ Content-Type: text/plain; charset="us-ascii" ; format="flowed" To: r-help-request@lists.R-project.org From: "Dr. Chris Wills" <cwills@ucsd.edu> Subject: Questions about sorting and functions Cc: Bcc: X-Attachments: Dear R-Gang - Two questions for you: 1) I cannot figure out how to sort one column in an array, and

Hi, I have a matrix, say m=matrix(c( 983,679,134, 383,416,84, 2892,2625,570 ),nrow=3 ) i can find its row/col sum by rowSums(m) colSums(m) How do I divide each row/column by its rowSum/colSums and still return in the matrix form? (i.e. the new rowSums/colSums =1) Thanks. Casper -- View this message in context:

(a) In R 2.12.2 rowsum can overflow if given an integer input: > rowsum(c(2e9L, 2e9L), c("a", "a")) [,1] a -294967296 > 2^32 + .Last.value [,1] a 4e+09 Should it be changed to coerce its x argument to numeric (double precision) so it always returns a numeric output? (b) When rowsum is given an x containing both NaN and NA it appears to use the last

Hi, I'd like to simply add column-wise using Matrix objects (Csparse). It looks like one can apply mosty any base function to these objects (i.e., apply, colSums), but there is a nasty conversion to traditional matrix objects if one does that. Is there any workaround? I can see colSum listed in the help for Class 'CsparseMatrix' , but I wonder whether I'm using the default

Hi R, Let, x=1:80 I want to sum up first 8 elements of x, then again next 8 elements of x, then again another 8 elements..... So, my new vector should look like: c(36,100,164,228,292,356,420,484,548,612) I used: aggregate(x,list(rep(1:10,each=8)),sum)[-1] or rowsum(x,group=rep(1:10,each=8)) But without grouping, can I achieve the required? Any other ways of doing

Dear list, I have some trouble generating a frequency table over a number of vectors. Creating these tables over simple numbers is no problem with table() > table(c(1,1,1,3,4,5)) 1 3 4 5 3 1 1 1 , but how can i for example turn: 0 1 0 0 0 1 0 1 0 1 0 0 0 1 0 1 0 0 into 0 0 1 1 1 0 0 2 0 1 0 3 My second problem is, sorting rows and columns of a matrix by the rowSums/colSums. I did it

Hi-- This is a question with a trivial and obvious answer, I'm sure, but I can't seem to find it in the help files and books that I have handy. I have a dataframe consisting of two columns, "Gene_Name," a list of gene symbols, and "Number," a numeric measure of how frequently a tag representing that gene showed up in a SAGE library. Several of the genes are

Hi, The result of rowsum() in R doesn't have the dimnames I'd expect, e.g.: > rowsum(matrix(1:12, 3,4), c("Y","X","Y")) [,1] [,2] [,3] [,4] 1 2 5 8 11 2 4 10 16 22 whereas S-Plus gives the more useful result: [,1] [,2] [,3] [,4] X 2 5 8 11 Y 4 10 16 22 This is because R's rowsum() code gives

The result of rowsum() in R doesn't have the dimnames I'd expect, e.g.: > rowsum(matrix(1:12, 3,4), c("Y","X","Y")) [,1] [,2] [,3] [,4] 1 2 5 8 11 2 4 10 16 22 whereas S-Plus gives the more useful result: [,1] [,2] [,3] [,4] X 2 5 8 11 Y 4 10 16 22 This is because R's rowsum() code gives the

If all rows are in the same "group", rowsum() returns a vector instead of a (1xN) matrix, contrary to documentation: R> print(z <- rowsum(matrix(1:12, 3,4), rep("x",3))) [1] 6 15 24 33 R> dim(z) NULL It worked correctly in version 1.4.0 but was broken by version 1.6.1. I'm currently using 1.7.1 under Solaris 2.8. --please do not edit the information

Dear R-List, I am sure there must be a very simple way to do this - I just do not know how... This is what I want to do: #my dataframe df<-data.frame(id=c("x01","x02","x03","x04","x05","x06"),a=c(1,2,NA,4,5,6),b=c(2,4,6,8,10,NA),c=c(NA,3,9,12,NA,NA),sum=c(3,9,15,24,15,6))    id    a     b     c   sum 1 x01  1     2    NA   3 2

Hi, I have been experimenting with the new Survey package. Specifically, I was trying to use some of the functions on the public-use survey data from NHIS (2000 Sample Adult file). Error 1): The first error I get is when I try to specify the complex survey design. nhis.design<-svydesign(ids=~psu, probs=~probs, strata=~strata, data=nhis.df, check.strata=TRUE) Error in svydesign(ids =

Dear Sir/Madam, I'm getting a problem with a R-code which converts a data frame to a matrix. It first generate a (m^(n-m) * m) matrix A and then regenerate another matrix B having less dimension than A which satisfy some condition. Now I wish to assign each row of B to a vector as individual. My problem is when I set any choice of (n,m) except m=1 it works fine but setting m=1 I got the

any suggestions on the following gratefully welcome, I have a dataframe, which I am subsetting via labels atpi[, creativity] where (for example) atpi = as.data.frame(matrix(1:50, ncol = 5, nrow = 10)) names(atpi) = c("Q1", "Q2", "Q3", "Q4", "Q5") and creativity = c("Q1", "Q3", "Q4") I want to add an extra column

Hi! I have large matrices, one column per variable and I have a vector of factors / grouping symbols. Then I am computing subtotals for the groups but it takes pretty long and thus I wanted to ask if there is a better way to do it or if this is already the best way: subTotals <- function(x, groupvec) do.call("rbind",lapply(split(x,groupvec),colSums,na.rm=T)) Thanks reading my

I have a matrix 700x2000 which is sampled in each cycle from another matrix 788x2000 with the numbers 0,1 and 9 There is one specific collumn of this matrix, dart[,1977], that usually, after the samplimg procedure has only 1 and 9 (because the zero frequency in this collumn is low). However, when this happens, I want to include an IF conditional in my code. so basically what i wanted to do was to

'rowsum()' seems to add row names to the resulting matrix, corresponding to the respective 'group' values. This is very handy, but it is not documented. Should the documentation mention it so it could be relied upon as part of API? Cheers, Ott -- Ott Toomet Visiting Researcher School of Information Mary Gates Hall, Suite 310 University of Washington Seattle, WA 98195

Hello, I am trying to achieve something which I *think* is possible using rowsum, but a little help should be useful: Consider the following dataframe DF0: A B C 89 1 140 89 06 20 89 29 137 89 52 13 89 57 10 89 97 23 89 1 37 89 1 12 89 1 3 52 1 11 52 1 31 52 1 16 52 1 6 52 1 10 52 1 13 52 1 10 52 1 25 52 1 2 52 59 38 52 97 75 57 1 14 57 1 13 57 1 14 57 114 12 57 1 23 57 06 26 I need create a

Hi, Please consider the following : x = c(1,3,NA,5) y = c(2,NA,4,1) min(x,y,na.rm=TRUE) # ok [1] 1 max(x,y,na.rm=TRUE) # ok [1] 5 sum(x,y,na.rm=TRUE) # ok [1] 16 pmin(x,y,na.rm=TRUE) # ok [1] 1 3 4 1 pmax(x,y,na.rm=TRUE) # ok [1] 2 3 4 5 psum(x,y,na.rm=TRUE) [1] 3 3 4 6 # expected result Error: could not find function "psum" # actual result