similar to: Removing rows w/ smaller value from data frame

I am trying to replicate the SAS proc univariate in R. I got most of the stats I needed for a by grouping in a data frame using: all1 <- ddply(all,"ACT_NAME", summarise, mean=mean(COUNTS), sd=sd(COUNTS), q25=quantile(COUNTS,.25),median=quantile(COUNTS,.50), q75=quantile(COUNTS,.75), q90=quantile(COUNTS,.90), q95=quantile(COUNTS,.95), q99=quantile(COUNTS,.99) )

Hello, I was wandering if it is possible to perform on a dataframe called 'all' a shapiro wilk normality test for COUNTS by variable Group ACTIVITY? Could it be done using plyer? I saw an eg that applies to an array but not to a dataframe: lapply(split(dataset1$Height,dataset1$Group),shapiro.test) Any thoughts would be much appreciated. My dataframe is in shape: dat ACTIVIT

Hello, I am trying to re-code all my programs from SAS into R. In SAS I use the following code: proc sort data=upper; by tdate stock_symbol expire strike; run; data upper1; set upper; by tdate stock_symbol expire strike; if first.expire then output; rename strike=astrike; run; on the following data set: tdate stock_symbol expiration strike 9/11/2012 C 9/16/2012

Hello, I have a dataframe w/ 3 variables of interest: transaction,date(tdate) & time(event_tim). How could I create a 4th variable (last_trans) that would flag the last transaction of the day for each day? In SAS I use: proc sort data=all6; by tdate event_tim; run; /*Create last transaction flag per day*/ data all6; set all6; by tdate event_tim; last_trans=last.tdate; Thanks

Hello, I have a variable in a data frame that contains NA values. I just want to subset so that I get the obs where that variable is missing. In SAS I would do: data missing; set test; if myvalue=' '; run; How can I perform this simple task in R? Thanks in advance for your help. -- View this message in context:

Hello, I am a newbie to R coming from SAS background. I am trying to program the following: I have a monthly data frame with 2 variables: client pct_total A 15% B 10% C 10% D 9% E 8% F 6% G 4% I need to come up w/ a monthly list of clients that make 50% or just above it every month so I can pass them to the rest of the program.

I get following error message: trying URL 'http://cran.stat.ucla.edu/bin/windows/contrib/2.15/xlsx_0.4.2.zip' Content type 'application/zip' length 365611 bytes (357 Kb) opened URL downloaded 357 Kb Error in read.dcf(file.path(pkgname, "DESCRIPTION"), c("Package", "Type")) : cannot open the connection In addition: Warning messages: 1: In

1)I am wandering how the following SQL statement can be written in R language w/o using sqldf: create table detail2 as select a.* from detail a, pdetail b where a.TDATE=b.TDATE and (a.STIM >= b.STIM and a.STIM <=b.MAXTIM) 2) when try if then in R it only applies to the 1st row & not to whole dataset like in SAS. How do you get round that? in SAS: data summary; set all1;

Hello, I know how to increment a date by calendar date: ticker$ldate <- ticker$tdate + days(5) How do I increment it by business days only so that week-ends are not counted? So for example friday november 2 + 5days becomes friday november 9 & not wednesday nov 7. Thanks for your help. -- View this message in context:

I am new to R and I have the following SAS statements: if otype='M' and ocond='1' and entry='a.Prop' then MOC=1; else MOC=0; How would I translate that into R code? Thanks in advance -- View this message in context: http://r.789695.n4.nabble.com/if-then-in-R-versus-SAS-tp4641225.html Sent from the R help mailing list archive at Nabble.com.

Hello, We lost our SAS licence & I am busy transfering my old SAS programs to R environment. I am very new to R. In 1 program I was creating SAS macro vars & passing them into a SQL query to run against the server. There are 3 variables firm, begindt, enddt. # of values for each varies month to month. Is there anyway I could do the same thing in R & pass the afore mentioned values

Hello all, I have a question: I am using the interquantile method to spot outliers & it gives me values of say 234 & -120 or for the higher & lower benchmarks. I don't have any issues w/ the higher end. However I don't have any negative values. My lowest possible value is 0. Should I consider 0 as an outlier? Thanks ahead for your thoughts -- View this message in

Hello R Help! I would like to make a legible boxplot of tree growth rates for each of seven tree species at each of seven different sites. It's a lot of data to put on one figure, I know. I made a beautiful, interpretable figure using color, but my target journal can't deal with color figures. I can use seven shades of grey to fill the boxes, but the figure then becomes uninterpretable -

Hi. I'm trying to write an application to retrieve financial data (specially bonds data) from FINRA. The web page is served dynamically from an asp.net application: http://cxa.gtm.idmanagedsolutions.com/finra/BondCenter/AdvancedScreener.aspx I'd like to know if it's possible to fill dynamically the web page form from R and, after filling it (with the issuer name), retrieve the web

Hi. I'm trying to write an application to retrieve financial data (specially bonds data) from FINRA. The web page is served dynamically from an asp.net application: http://cxa.gtm.idmanagedsolutions.com/finra/BondCenter/AdvancedScreener.aspx I'd like to know if it's possible to fill dynamically the web page form from R and, after filling it (with the issuer name), retrieve the web

Hi everyone: This may be trivial but I just have not been able to figure it out. Imagine the following dataframe: a b c d TRUE TRUE TRUE TRUE FALSE FALSE FALSE TRUE FALSE TRUE FALSE FALSE I would like to create a new dataframe, in which TRUE gets 0 but if false then add 1 to the cell to the left. So the results for the example above should be something like: a b c

Hi, I'm trying to copy the first row of one data frame to another. This is the statement I am using : df2[1,]<-df1[1,]; I have printed them out separately: df1[1,] = A C D E F But after copying: df2[1,] = 96 29 88 122 68 Why isn't it copying? They are both data frames, and "as.character" isn't working either. Thanks for your input :) [[alternative HTML version

I am trying to concatenate 2 datasets that don't have exactly the same column. In SAS I did: data summary; set agency prop; run; No problem in R I get error message summary <-rbind(agency,prop) Error in match.names(clabs, names(xi)) : names do not match previous names But when I use rbin.fill, that overwrites the second file w/ first one. Is there a way to replicate the sas process

Hello, I want to use lag on a time variable but I have to take date into consideration ie I don't want days to overlap ie: I don't want my first time of today to match my last time of yeterday. In SAS I would use : data x; set y; by date tim; previous=lag(tim); if first.date then do; previous=.; end; run; How can I do something similar in R? I can't find

Thank you very much for your reply. Your code work well with this example. I modified a little to fit my real data, I got an error massage. Error in split.default(x = seq_len(nrow(x)), f = f, drop = drop, ...) : Group length is 0 but data length > 0 On Thu, Jan 31, 2013 at 12:21 PM, arun kirshna [via R] < ml-node+s789695n4657196h87@n4.nabble.com> wrote: > Hi, > Try this: >