similar to: Undefined Method

I am trying to monkey-patch the ActiveRecord::Base class to incorporate a generic search class method so that it can be used by all model classes which need this functionality. Since model classes directly inherit from ActiveRecord::Base and unlike controllers and helpers, do not have an ancestor class defined, I think I am forced to open the ActiveRecord::Base class and patch it? May be I am

This is becoming painful. Where the file should be? What should be in it? I am running will_paginate 3.0.pre Here is my current code sitting in initializers/ class WillPaginateRenderer < WillPaginate::LinkRenderer def rel_value(page) "nofollow" end end Thanks for your help, -- Posted via http://www.ruby-forum.com/. -- You received this message because you are subscribed

Does anyone have experience with will_paginate? I''m trying to use it with acts_as_ferret. routes.rb ... map.search ''/search'', :controller => ''notes'', :action => ''search'' notes.rb ... acts_as_ferret :fields => [ ''body'' ] notes_controller.rb ... def search if params[ :query ] @query = params[

Hi I am having issues with getting my pretty urls to work. routes.rb: map.connect '':user'' , :controller => ''front'' , :action => ''list'' , :filter => ''user'' front_controller.rb: def list @advert_pages, @adverts = paginate :adverts, :per_page => 10 @user =

Hi All! It''s been a while since I had to ask for help, but I''m back! I''ve finished beta testing my big app and started the transition to production. Everything went fine and the production version was working till I was asked to add another model :-( (Almost a year of beta testing and they only come up with it after moving to production :-D ) I successfully

I''m trying to figure out how to change the order of a list view and it''s obvious to me that I don''t understand what I get from a simple scaffold to know enough to alter it. If someone would be so kind to tell me what this means ... def list @placment_pages, @placements = paginate :placements, :per_page => 10 end @placement_pages, # I am guessing that this

I am trying to use pagination with the order option. I am following examples I''ve seen all over the web, but I am getting an error. My code seems simple: def list @upload_pages, @uploads = paginate :uploads, :per_page => 20, :order => ''id'' end Yet I keep getting this error: ___________________________________________

I''ve experimented around and have ran out of ideas, here''s the message: TypeError in True_false_questions#list can''t convert String into Integer RAILS_ROOT: script/../config/.. Application Trace <http://zbyte32:3000/true_false_questions/list/0#> | Framework Trace <http://zbyte32:3000/true_false_questions/list/0#> | Full

Hello. I call a find_all_by_subject("action") which returns 2 videos and displays them properly. But when I add @video_pages, @videos = paginate :videos, :per_page => 10 so I can paginate the videos, it displays ALL the videos as if I selected list videos. Can someone please tell me what I am doing wrong? Thank you. selectaction.rhtml <table> <tr> <% x = 0 %>

because I am a grasshopper... Now that I can sort my ''list''...is there a logical way of not repeating myself to having essentially the same list view with multiple sorts? i.e. def list_cl # ordered by clients last name @placement_pages, @placements = paginate( :placements, :include => [:client], :order_by =>

There must be a better way to write this code: @project_pages, @projects= paginate :project, :per_page => 10, :conditions => ["account_id = ?", account] ?! If only I could pass the sub-collection account = ... @projects = account.project to paginate, instead of letting it extract it with a find :all + sql conditions Alain. -- Posted via

In my database I have a products table that has a bunch of attributes (title, description, etc) including one for date_expires. Is there a best practices method to get the database to erase the expired items? Is that done outside RoR via Cron or something? Else is it better to just have my app filter out anything that is expired but still keep those records in my dbase? -- Posted via

I have some code working that lists only items from a particular user. The code in my list action finds the user and then conditionally lists only his/her items: def list user = User.find(session[:user]) user_id = user.id @product_pages, @products = paginate :products, :per_page => 10, :conditions =>[''user_id = ?'', user.id]

I''m using will_paginate in a Post class method; [code]def self.list(page) paginate :per_page => 10, :page => page, :include => :user end[/code] I can happily use the method on my posts controller index action; [code] class PostsController < ApplicationController def index @posts = Post.list(params[:page]) respond_to do |format|

I''m trying to create a paginated list that will take note of the "end_date" field in my table. This is what I have: @post_pages, @posts = paginate(:posts, :per_page => 10, :order_by => ''end_date'') in the controller. And for the view: <h1>Posts ending soon</h1> <ul><% for post in @posts do %> <strong>Post Title:

How do I adapt this code to only list articles made by the user logged into the session? def list @article_pages, @article = paginate :articles, :per_page => 10 end -- Posted via http://www.ruby-forum.com/.

I have the following: def index begin @restaurant_pages, @restaurants = paginate :restaurants, :order => (params[ :sort ] || "name"), :per_page => 2 @cuisines = Cuisine.find_all rescue redirect_to :action => :index end end # sort by cuisine def

Hi Guys, I am trying to paginate the results from a search. When I use actual constants in the search conditions, it works fine: def query @k2_result_pages, @k2_results = paginate (:k2_results, :conditions => [''e_date >= ? AND e_date <= ?'', ''2006-07-12'', ''2006-08-12''],

Hey all, I''m using a simple search function. It''s working great except for foreign keys. I have one table pets (id,name,owner_id) and another table people(id,name) owner_id being a foreign key of pet pointing to people name. here it is on the pet controller: @paginator, @pets= paginate(:pets, :conditions =>["name OR owner_id like

Hi, I have the following find statment @client_pages, @clients = paginate :clients, :per_page => 20, :order => "organisation_id, surname" currently im ordering by organisation_id however I need to order by the field in the organisation table organisations.name how can this be done? Thanks Scott -- Posted via http://www.ruby-forum.com/.