similar to: DataMatrix barcode generator/reader

I there We are making an app using barcode readers and it would be great if we did not have to hit enter or click each time an product is scanned, does anuybody has eny idea about how to achive this? Thanks in advance

Hello Rubyists, I need to generate barcodes (in UPC and codabar symbologies) and would like to know if anyone has done this with Ruby. From what I can tell, it would be possible to use the gnu-barcode [1] or barcodewriter [2] to generate a PostScript, then through RMagick (via GhostScript) take the file and create a GIF/JPG. These will really only be used for web display (to be printed

********UNDEFINED METHOD REGISTER ERROR IN THE FALLOWING CODE ******* Hi all, I am trying to generate barcode(including its name as label at the bottom of barcode image for easy understand with out scanning by barcode scanner). For this I am Using barby, chuncky_png, rmagick gems. I am using the fallowing code to generate label at bottom of image by using rmagick gem: gem

I have huge data file, and I would like randomize just one column at a time , is there any easy way? Thanks a lot. -- View this message in context: http://www.nabble.com/Randomizing-one-column-in-the-dataMatrix-tf4957535.html#a14197423 Sent from the R help mailing list archive at Nabble.com.

One my of my CDs has a bar code, 4 011222 044068, which is titled "EAN CODE". Another one simply has a barcode, 07822-18646-2, without any title. Should I assume that the barcode of any CD is the EAN code? I'm asking this because I want to know how to title the comment of the Vorbis file -- "EAN code" or "Barcode". Thanks. -------------- next part

For the initial data step, assuming a data frame named stress already exists, and using base R, you can start with something like this: barcodes.to.delete <- c('16187DD4015', '16187DD6002', {complete the comma-delimited vector of barcodes you don't want} ) yield <- subset(stress, !(barcode %in% barcodes.to.delete) ) yield <- subset(yield , !(field %in%

On 13 September 2017 at 11:42, Johnny Hughes <johnny at centos.org> wrote: > On 09/13/2017 10:28 AM, hw wrote: >> >> Hi, >> >> https://ctan.org/tex-archive/graphics/pstricks/contrib/pst-barcode/ >> says that pst-barcode is included in texlive. >> >> I installed texlive, and it can?t find pst-barcode.sty. Is that a >> bug in the packaging

Hi, https://ctan.org/tex-archive/graphics/pstricks/contrib/pst-barcode/ says that pst-barcode is included in texlive. I installed texlive, and it can?t find pst-barcode.sty. Is that a bug in the packaging Centos does, or is texlive in Centos some derelict version?

On 09/13/2017 10:28 AM, hw wrote: > > Hi, > > https://ctan.org/tex-archive/graphics/pstricks/contrib/pst-barcode/ > says that pst-barcode is included in texlive. > > I installed texlive, and it can?t find pst-barcode.sty.? Is that a > bug in the packaging Centos does, or is texlive in Centos some > derelict version? CentOS has whatever version is in RHEL. sudo yum

Hi, On Fri, Dec 09, 2016 at 04:02:50PM -0500, m.roth at 5-cent.us wrote: > I'm about to go googling, but thought I'd ask here if anyone's using a > barcode scanner with CentOS, and if so, a) what scanner are you using, > and b) what, if any, software are you using to record what it scans? Most USB barcode scanners can operate in so called keyboard wedge mode (either

We use the debian 4.0 Linux with the wine 1.0. When we run our application on this platform, there is a problem: The Barcode can't be displayed correctly, but occurs some Garbled. The font we use is ?Carolinabar-B39-25F2?. But when we install the wine-0.9.25 instead of wine-1.0, the barcode can be displayed correctly. So could someone tell us the reason, and gives us some suggestions?

Hi, folks, I'm about to go googling, but thought I'd ask here if anyone's using a barcode scanner with CentOS, and if so, a) what scanner are you using, and b) what, if any, software are you using to record what it scans? <mutter, mutter, the serial number of every bloody h/d that we're asking them to deGauss...mutter,mutter> mark

https://bugs.freedesktop.org/show_bug.cgi?id=63790 Priority: medium Bug ID: 63790 Assignee: nouveau at lists.freedesktop.org Summary: Nouveau fb boots laptop screen a GIANT BARCODE QA Contact: xorg-team at lists.x.org Severity: critical Classification: Unclassified OS: Linux (All) Reporter: aka.bugle at

Dear R-users,  I have a problem, I have the following dataframe:   d<-data.frame(  'y1'=c(1,2,1,2,1,NA,NA), 'y2'=c(1,2,1,1,1,2,1), 'y3'=c(1,NA,1,NA,NA,2,1), 'y4'=c(NA,2,NA,1,1,2,NA), 'a'=c(1,1,1,1,1,1,2) ) where the last variable counts the number of missing values in a row. Now, i want to set rows where a>1 to NA and arrive at something like the

Hi, I have huge matrices in which the response variable is in the first column and the regressors are in the other columns. What I wanted to do now is something like this: #this is just to get an example-matrix DataMatrix <- rep(1,1000); Disturbance <- rnorm(900); DataMatrix[101:1000] <- DataMatrix[101:1000]+Disturbance; DataMatrix <- matrix(DataMatrix,ncol=10,nrow=100); #estimate

In datamatrix[, "y"] == datamatrix[, "y"][-1] : longer object length is not a multiple of shorter object length out = c(FALSE,datamatrix[,'y'] == datamatrix[,'y'][-1]) and I do not know why I get that error, the resulting out matrix is somehow one row larger than datamatrix... all I try to do is filter matrix by dropping rows where [,'y'][-1] ==

Hi. I have been looking at the PCAproj function in package pcaPP (R 2.4.1) for robust principal components, and I'm trying to interpret the results. I started with a data matrix of dimensions RxC (R is the number of rows / observations, C the number of columns / variables). PCAproj returns a list of class princomp, similar to the output of the function princomp. In a case where I can

Hi, I need to permute the rows of a matrix, where each row is independently rearranged. A simple solution is this: shuffled <- datamatrix <- matrix(1:24, ncol = 4) for (i in 1:nrow(datamatrix)) { shuffled[i, ] <- sample(datamatrix[i, ]) } > datamatrix [,1] [,2] [,3] [,4] [1,] 1 7 13 19 [2,] 2 8 14 20 [3,] 3 9 15 21 [4,] 4 10 16 22 [5,]

Hello R users, I'm wondering whether it is possible to manage big data set in R? I have a data set with 3 million rows and 3 columns (X,Y,Z), where X is the group id. For each X, I need to run 2 regression on the submatrix. I used the function "split": datamatrix<-read.csv("datas.csv", header=F, sep=",") dim(datamatrix) # [1] 2980523 3

Hello all, My statistical analysis training up until this point has been entirely done in SAS. The code I frequently used was: *Yield Champagin; data yield; set stress; if field='YV' then delete; if field='HB' then delete; if barcode='16187DD4015' then delete; if barcode='16187DD6002' then delete; if barcode='16187DD2007' then delete; if