similar to: removing string restrictions

Displaying 20 results from an estimated 6000 matches similar to: "removing string restrictions"

2006 Oct 19
1
default arguments in generics and methods
i believe the following is true but would appreciate confirmation that it is intended behavior and will continue: if a default argument is employed in the definition of a generic function, and the generic is called with the argument in question (call it 'ARG') missing, then the method for signature (..., ARG = "missing", ...) will be called by 'standardGeneric'
2006 Apr 11
2
About list to list - thanks
Thank you very much for your useful suggestions. These are exactly what I was looking for. foo <- list(foo1, foo2, foo3) lapply(foo, function(x) matrix(unlist(x), nrow = length(x), byrow = TRUE)) or lapply(foo, function(x) do.call('rbind', x)) Best, Muhammad Subianto On 4/11/06, Muhammad Subianto <msubianto at gmail.com> wrote: > Dear all, > I have a result my experiment
2006 Apr 11
2
About list to list
Dear all, I have a result my experiment like this below (here my toy example): foo1 <- list() foo1[[1]] <- c(10, 20, 30) foo1[[2]] <- c(11, 21, 31) foo2 <- list() foo2[[1]] <- c(100, 200, 300) foo2[[2]] <- c(110, 210, 310) foo3 <- list() foo3[[1]] <- c(1000, 2000, 3000) foo3[[2]] <- c(1100, 2100, 3100) list(foo1,foo2,foo3) The result: > list(foo1,foo2,foo3) [[1]]
2006 Jun 29
3
advice on arguments
I have a general style question about R coding. Suppose I'm writing a function (foo1) that calls other functions (foo2, foo3, ...) which have complicated argument lists (e.g. optim(), plot()), _and_ I may be calling several different functions in the body of foo1. Since foo2 and foo3 have different sets of arguments, I can't just use "..." ; I did write some code a while ago
2008 Mar 25
1
Passing (Optional) Arguments
Dear List: In short, I am writing a number of functions as building blocks for other functions and have some questions about scoping and passing arguments. Suppose I have functions foo1, foo2, and foo3 such that: foo1<-function(a=1,b=TRUE,c=FALSE){#do stuff}; foo2<-function(x=1,y=FALSE,z=c(1,2,3,4)){#do stuff}; foo3<-function(lambda,...){lambda*foo1()*foo2()}; I want to be able to
2010 Feb 10
1
How to solve: Error in * unused argument(s) ?
Hi all, For some reason, I would like to use functions bellow (see example code bellow), but instead I get the following error message: *Error in foo2(...) : unused argument(s) (arg3 = 3)* #--------------------- # example code #--------------------- foo1 <- function(arg1,...) { print(arg1) foo2(...) foo3(...) } foo2 <- function(arg2) { print(arg2) } foo3 <- function(arg3) {
2018 Aug 27
3
Replacing a function from one module into another one
Hello LLVM Developers, I'm trying to replace a function defined in one module into another module (different files). The first issue I ran into was that llvm::Function does not have a method "moveBefore" or "moveAfter" as the llvm::BasicBlock or llvm::Instruction do, so I figured I would just move the BasicBlocks of the replacing function into the function that was being
2018 Sep 02
2
Replacing a function from one module into another one
Hello and thanks for the answer, I'm still facing issues, I'll do my best to explain my situation, as I explained, I have two modules, each one with its own main and functions, I would like to replace in the *oldModule* a function call that is calling *foo2* (defined in *oldModule*) to instead call *foo3*, which is defined in the *refModule. *So in summary, I have: 1. The original
2018 Sep 02
2
Replacing a function from one module into another one
Hi Ahmad, What does that tool does besides what LLVM linker already does? I don't think my problem is in linking both modules, I think LLVM linker does the job for me, the issue is when changing the called function to call another function (in the example previously provided, to change it from foo2 to foo3, and adjusting the function parameter's references). Regards, Daniel Moya El
2018 Sep 06
2
Replacing a function from one module into another one
Hi Philip, The error happens when the program finishes and it automatically calls the destructors, so it is not an error specifically inside my program. Here's the full code: #include "llvm/ExecutionEngine/ExecutionEngine.h" #include "llvm/ExecutionEngine/MCJIT.h" #include "llvm/IRReader/IRReader.h" #include "llvm/Support/TargetSelect.h" #include
2012 Nov 06
1
Depends/Imports/Suggest/Enhence
Hi the list In the DESCRIPTION file of my package foo0, I have: Depends: foo1 Imports: foo2 Suggest: foo3 Enhence: foo4 If I understand correctly, to install foo0 on my computer, I need to already have foo1, foo2, foo3. foo4 is not necessary. I my R sesssion, when I will write: library(foo0), then the package foo1 will be attach. foo2, foo3 and foo4 will not. Is that correct? But what is
2018 Sep 03
2
Replacing a function from one module into another one
Thank you Ahmad, I figured out that, although the type of both p(oInst) and p(nInst) were the same, I had to: for (unsigned int i = 0; i < callOInst->getNumArgOperands(); i++) { callOInst->getArgOperand(i)->mutateType(callNInst->getArgOperand(i)->getType()); } that solves the issue at the calling instruction in the main function, but now I see that *linkModules* does not work
2018 Sep 06
2
Replacing a function from one module into another one
Hi Philip, Thanks for the reference, I was able to follow it and copy the code that I saw necessary, but I still have some issues (references are still not updated). I created the function: void populateVMap(llvm::ValueToValueMapTy &VMap, llvm::Function *fOld, llvm::Function *fNew) { llvm::Function::arg_iterator DestI = fOld->arg_begin(); for (llvm::Function::const_arg_iterator J =
2004 Apr 20
2
Creating variable names
My apologies for asking what is doubtless a dumb question, but I have scant experience in R. It would be very convenient in doing lots of plots to be able to do them in a loop that stepped through a vector of variable names. For example one could say x<-("mydates") y<-c("foo1","foo2","foo3") #where "foon" were vectors
2018 Sep 04
2
Replacing a function from one module into another one
Hi Philip, Thank you very much for your answer, the vector declaration example worked. I'm pretty sure the ValueToValueMapTy is the last thing I need because I even saw there is another function that could help me llvm*:*:RemapFunction <http://llvm.org/doxygen/namespacellvm.html#addf0183e92893bdbcde00fc9091dda93>; but my problem is that I don't know how to populate the
2014 May 02
1
Authors@R: and Author field
Hi to all Authors@R: c(person("fooa","foob", role = c("aut","cre"), email = "fooa.foob@fooc.de"), person("foo1","foo2", role = c("ctb"), email = "foo1.foo2@foo3.de")) Author: fooa foob, with contributions from foo1 foo2 using r CMD check --as-cran .. (R 3.1
2007 Mar 29
7
re-work option initialization
Dennis Kasprzyk and I have been discussing some changes to how options are initialized. Problems with how options are currently initialized. 1. Helper functions are not used to initialize options, which means that if we make a change to the option structure, all option initialization code needs to be updated. Using helper functions will also reduces the amount of duplicate code. 2. No
2007 Feb 06
2
state of blur plugin
I forgot to give everyone an update on this. The blur plugin is in a reasonable state now. It requires an OpenGL implementation with an accelerated CopyTexSubImage2D path for usable performance and that's likely not going to change sometime soon. One major performance improvement can still be made, which allow us to avoid the CopyTexSubImage2D path whenever the area behind a blurred region is
2013 Apr 02
2
How to remove all characters after comma in R
I have the following list of strings: x <- c("foo, foo2, foo3", "bar", "qux, qux1") what I want to do is to obtain foo, bar qux Namely for each element in the vector obtain only string before the first comma. What's the way to do it? - G.V. [[alternative HTML version deleted]]
2006 Apr 04
2
Return function from function with minimal environment
Hi, this relates to the question "How to set a former environment?" asked yesterday. What is the best way to to return a function with a minimal environment from a function? Here is a dummy example: foo <- function(huge) { scale <- mean(huge) function(x) { scale * x } } fcn <- foo(1:10e5) The problem with this approach is that the environment of 'fcn' does not