similar to: Heroku, needs constant AppController updates?

Hi, I am using eventbright gem for getting the event brite events. I am doing like as follows:- EventBright.setup(api_key) res= EventBright.call("event_search", {:latitude=>37.3229978, :longitude=>-122.0321823}) puts res.inspect I am getting the response as the HTTPARTY object. Can anyone tell me how can I parse the response? Also, I think I am missing something during

Hi Jim, The data set is correct. I took two readings from the "SITE A" within a short time interval, therefore I want to take the first value if there are repeated within a same group of "timeGroup". Therefore I wanted following FinalData1 B1 B2 id_X "A" "B" id_Y "A" "B" thanks, On Tue, May 1, 2018 at 4:05 PM, Jim

Hi Marna, This is a condition that the function cannot handle. It would be possible to reformat the result based on the time intervals, but the stretch_df function doesn't try to interpret the values, just stretches them out to a wide format. Jim On Wed, May 2, 2018 at 9:16 AM, Marna Wagley <marna.wagley at gmail.com> wrote: > Hi Jim, > The data set is correct. I took two

Hi Jim, Thank you very much for your suggestions. I used it but it gave me three sites. But actually I do have only two sites "Id_X" and "Id_y" . In fact "A" is repeated two times for "Id_X". If it is repeated, I would like to take the first one among many repeated values. dat<-structure(list(ID = structure(c(1L, 1L, 1L, 2L, 2L), .Label =

Hi R user, I was trying to convert a long matrix to wide? I have an example and would like to get a table (FinalData1): FinalData1 B1 B2 id_X "A" "B" id_Y "A" "B" but I got the following table using the following code. FinalData1 B1 B2 id_X "A" "A" id_Y "A" "B" the code and the

Hi Marna, Try this: library(prettyR) stretch_df(dat,idvar="ID",to.stretch=c("EventDate","SITE")) Jim On Wed, May 2, 2018 at 8:24 AM, Marna Wagley <marna.wagley at gmail.com> wrote: > Hi R user, > I was trying to convert a long matrix to wide? I have an example and would > like to get a table (FinalData1): > > > FinalData1 > B1

Hi Marna, I think this is due to having three rows for id_X and only two for id_Y. The function creates a data frame with enough columns to hold the greatest number of values for each ID variable. Notice that the SITE_n columns contain three values for id_X (A, A, B) and two for id_Y (A, B, NA) as there was no third occasion of measurement for the latter. Even though there are only two _values_

Dear list, How can I calculate the difference in days between the eventdate and basedate in the below dataset? id basedate outcome.3 eventdate daydiff 1 1001 1999-09-28 2 1999-10-01 3 2 1002 1999-09-22 1 3 1003 2000-01-19 1 4 1004 2004-01-25 2 2004-02-03 9 5 1005 2005-08-11 1 6 1006 2000-07-04

I have wrote this: EventDate.find(:all, :include => [:container,{:event => [:photo,:event_type_names]},{:place=>:location}], :joins =>" RIGHT JOIN (SELECT event_dates.id,date_add(event_dates.date, INTERVAL i DAY ) AS date FROM (select 0 as i union all select 0 union all select 1 union all select 2) as integers CROSS JOIN event_dates

Hey all, I''m working on a site for a client that has a scedule im trying to display that pulls the next events for the upcoming Sunday from a MySQL table....The table stores the event date as mm/dd/yyyy. I''ve tried to think of everyway possible to get this thing to change after every sunday to show the next sunday''s events, but I end up doing it manually... Is it