similar to: Getting the number of years between two dates

Dear all, I have a question related to the POSIXlt function in R. I have a set of dates and times, for exmaple: startx <- as.POSIXct("2011-01-01 00:00:00") finx <- as.POSIXct("2011-12-31 00:00:00") daysx<- seq(startx, finx, by="24 hours") I want to change the dates of all the days falling on a Saturday to the next working day (i.e. Monday). So I

Have you noticed any problems with big dates (>=1/1/2040) in R? Here is the bit of code that I'm having trouble with: > test.date <- strptime("1/1/2040",format="%m/%d/%Y") > > unlist(test.date) sec min hour mday mon year wday yday isdst 0 0 0 1 0 140 0 0 0 > > date.plus.one <- as.POSIXct(test.date) +

Hello help, I have changed around some graphing code and made it into a function. Previously they y label of the axis was inserted as text in its own layout box. text(1,1, expression(~degree~C),cex=1) This worked great and resulted in the symbol for degree. In the function, I have changed it so: text(1,1,paste(b_unit),cex=1) and b_unit<-expression(~degree~C) This now inserts ~degree~C

Hello and thanks for helping. #some data L3 <- LETTERS[1:3] dat1 <- data.frame(cbind(x=1, y=rep(1:3,2), fac=sample(L3, 6, replace=TRUE))) #When x==1 and y==1 I want to replace the 1 values with NA #I can select the rows I want: dat2<-subset(dat1,x==1 & y==1) #replace the 1 with NA dat2$x<-rep(NA,nrow(dat2) dat2$y<-rep(NA,nrow(dat2) #select the other rows and rbind

Hello, If I have a dataframe: example(data.frame) zz<-c("aa_bb","bb_cc","cc_dd","dd_ee","ee_ff","ff_gg","gg_hh","ii_jj","jj_kk","kk_ll") ddd <- cbind(dd, group = zz) and I want to divide the column named group by the "_", how would I do this? so instead of the first row being x

Is there a way to make datetime_select() dropdowns work on a 12hr clock? I need to make a input field that works exactly like the reminders datetime selecton dropdowns in Backpack to populate a datetime field in my DB. i.e in the format: month, day, year ? hour (1-12) minute am/pm. Should I change my database to have a separate column for date and one for time and use date_select()? Can

Hello, I am a bit over my head on this issue. My colleagues and I are running R off of our server. We all have admin rights and prior to yesterday we all had our own libraries. Our main system administrator advised us that we should have a shared library. So, I am trying to do this. I have downloaded the latest version of R and installed it on the main drive of our server in the "Program

Hi all, Is there a simple function already implemented for getting the ISO weeks of a Date object? I couldn't find one, and so wrote my own function to do it, but would appreciate a pointer to the "default" way. If a function is not yet implemented, could the code below be of interest to submit to CRAN? Best Regards, Gustaf --------------------

On converting character variables to ordered factors, regression result has strange names. Is it possible to obtain same variable names with and without intercept? Thanks, Naresh mydf <- data.frame(date = seq.Date(as.Date("2024-01-01"), as.Date("2024-03-31"), by = 1)) mydf[, "wday"] <- weekdays(mydf$date, abbreviate = TRUE) mydf.work <- subset(mydf, !(wday

Hello, I am a complete newbie with Ruby and Rails. I am working on learning it by writing a project I was going to write in PHP using Rails. I am having a difficult time finding clear information on how I would do this. I need to take a date out of a table in my database and given another day calculate the next 28 day anniversery of the original date. This is used to calculate a delivery

Hello, I am not sure where to begin with this problem or what to search for in r-help. I just don't know what to call this. If I have 5 columns, the first 2 are the x,y, locations and the last three are variables about those locations. x<-seq(1860,1950,by=10) y<-seq(-290,-200,by=10) ANN<-c(3,0,0,0,1,0,1,1,0,0) CTA<-c(0,1,0,0,0,0,1,0,0,2) GLM<-c(0,0,2,0,0,0,0,1,0,0)

Hello, I am trying to use R to download a bunch of .csv files such as: http://biocache.ala.org.au/ws/occurrences/download?q=Banksia+ericifolia I have tried the following and neither work: a<- getURL(" http://biocache.ala.org.au/ws/occurrences/download?q=Banksia+ericifolia") Error in curlPerform(curl = curl, .opts = opts, .encoding = .encoding) : embedded nul in string: and

Hello, I am trying to cycle through a csv and make some summary statistics. I need to select rows based on the number in the row name that comes after the letter 'y'. For example, ? BA1y1 would equal 1, ?C3A2r3y1 would equal 1 and ?MA3r3y1r3 would equal 1. I currently have my code ?cycling through by the 5th character but my rows have variable length and the y can occur in several

Hey All, Two questions. Firstly, what is the difference between create and create! I see that create is document in the api http://api.rubyonrails.org/classes/ActiveRecord/Base.html#M002269 What is the difference between the two of these functions and where is the create! function defined. Also, What are the differences between these two calls? a) SomeModel.create!{ :property_a =>

Wanted to raise two questions: 1. Is bugs.r-project.org down? I haven't been able to reach it for two or three days: ``` ping bugs.r-project.org PING rbugs.research.att.com (207.140.168.137): 56 data bytes Request timeout for icmp_seq 0 Request timeout for icmp_seq 1 Request timeout for icmp_seq 2 Request timeout for icmp_seq 3 Request timeout for icmp_seq 4 Request timeout for icmp_seq 5

Hello, I need to create a dataframe containing all possible combinations of three variables: SITE (101,102,103,104), WDAY (MON,TUE,WED,THR,FRI), and TOD (MORN, AFTN). There should be a total of 40 unique combinations in my dataframe. I used expand.grid() successfully(?) to create my dataframe, but then when I went to order it by SITE, the resultant dataframe only contained four rows, one for each

Hey guys, I was playing with the cron trigger, and I noticed that wday is not honored. Looking at the code confirms this. Has anyone else seen this? Thanks Adam -------------- next part -------------- An HTML attachment was scrubbed... URL: http://rubyforge.org/pipermail/backgroundrb-devel/attachments/20071217/44d3a8a6/attachment.html

Hey, I'm new to R but familiar with other programming languages. Basically, I want to store an array of dates. For each of these dates I want to store only the day of the week and the hour. So for example: "Monday 12" would be Monday at 12 o'clock and "Tuesday 20" would be Tuesday at 8 p.m. Alternatively it could be stored as 0-6 for Sunday to Saturday. So Tuesday

date <- as.POSIXlt(Sys.time()) #present date for (i in 1:difftime(as.POSIXlt(Sys.Date()),"2007-10-01")) if (date$wday != 0 & date$wday != 6) {print(date);assign("date", (date-86400))} else (assign("date", (date-86400))) I am trying to print dates from present day to a day in the past, but omitting weekends. I am not doing something right, but can't

Hi, I have a dataframe column of the form v<-c("Fri Feb 05 20:00:01.43000 2010","Fri Feb 05 20:00:02.274000 2010","Fri Feb 05 20:00:02.274000 2010","Fri Feb 05 20:00:06.34000 2010") I need to convert this to datetime form. I did the following.. lapply(v,function(x){strptime(x, "%a %b %d %H:%M:%OS %Y")}) This gives me a list that looks like